Exam 14: Chemical Equilibrium: How Much Product Does a Reaction Really Make

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Calculate K for the following reaction, provided the concentration versus time graph shown below. 3A Calculate K for the following reaction, provided the concentration versus time graph shown below. 3A   B <font face=symbol></font> 2C  B 2C Calculate K for the following reaction, provided the concentration versus time graph shown below. 3A   B <font face=symbol></font> 2C

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A chemical equilibrium may be established by starting a reaction with ________

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The equilibrium constant for the formation of hydrogen iodide from hydrogen and iodine is 45.0 at a certain temperature. H2(g) I2(s) The equilibrium constant for the formation of hydrogen iodide from hydrogen and iodine is 45.0 at a certain temperature. H<sub>2</sub>(g) <font face=symbol></font> I<sub>2</sub>(s)   2 HI(g) Which of the following is true regarding this equilibrium? I.The reaction is product-favored. II.The reaction is reactant-favored. III.Equilibrium lies to the right. IV.Equilibrium lies to the left. 2 HI(g) Which of the following is true regarding this equilibrium? I.The reaction is product-favored. II.The reaction is reactant-favored. III.Equilibrium lies to the right. IV.Equilibrium lies to the left.

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Chemical equilibrium arises from the ________ of chemical reactions and is reached when the ________ of the forward reaction is equal to the ________ of the reverse reaction.

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A chemical equilibrium A A chemical equilibrium <sub> </sub><sub> </sub>A   3B Has a forward rate constant, s<font face=symbol><sup></sup></font><sup>1</sup> <font face=symbol></font> 5 M <font face=symbol><sup></sup></font><sup>1</sup>s<font face=symbol><sup></sup></font><sup>1</sup>, and a reverse rate constant, M <font face=symbol><sup></sup></font><sup>2</sup>s<font face=symbol><sup></sup></font><sup>1</sup> <font face=symbol></font> 0.5 s<font face=symbol><sup></sup></font><sup>1</sup>. What is the value of the equilibrium constant for this system? 3B Has a forward rate constant, s1 5 M 1s1, and a reverse rate constant, M 2s1 0.5 s1. What is the value of the equilibrium constant for this system?

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For the following hypothetical equilibrium, what is the value of the equilibrium constant if the concentrations at equilibrium are as shown? A 2 B For the following hypothetical equilibrium, what is the value of the equilibrium constant if the concentrations at equilibrium are as shown? <sub> </sub>A <font face=symbol></font> 2<sub> </sub>B   C [A] <font face=symbol></font> 4.5 <font face=symbol></font> 10<font face=symbol><sup></sup></font><sup>5 </sup>M [B] <font face=symbol></font> 2.2 <font face=symbol></font> 10<font face=symbol><sup></sup></font><sup>2 </sup>M [C] <font face=symbol></font> 9.4 <font face=symbol></font> 10<font face=symbol><sup></sup></font><sup>3 </sup>M C [A] 4.5 105 M [B] 2.2 102 M [C] 9.4 103 M

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The equilibrium constant for the acid ionization of mercaptoethanol (HSCH2CH2OH ) is 1.91 1010. HSCH2CH2OH(aq) The equilibrium constant for the acid ionization of mercaptoethanol (HSCH<sub>2</sub>CH<sub>2</sub>OH ) is 1.91 <font face=symbol></font> 10<font face=symbol><sup></sup></font><sup>10</sup><sub>.</sub> <sub> </sub><sub> </sub>HSCH<sub>2</sub>CH<sub>2</sub>OH(aq)   H<font face=symbol><sup></sup></font>(aq) <font face=symbol></font> SCH<sub>2</sub>CH<sub>2</sub>OH<font face=symbol><sup></sup></font>(aq) Which of the following is true regarding this equilibrium? I.The reaction is product-favored. II.The reaction is reactant-favored. III.Equilibrium lies far to the right. IV.Equilibrium lies far to the left. H(aq) SCH2CH2OH(aq) Which of the following is true regarding this equilibrium? I.The reaction is product-favored. II.The reaction is reactant-favored. III.Equilibrium lies far to the right. IV.Equilibrium lies far to the left.

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Which of the following is true for a chemical reaction at equilibrium?

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The equilibrium constants for the two reactions are known: Mm 4L The equilibrium constants for the two reactions are known: M<sup>m</sup><font face=symbol><sup></sup></font> <font face=symbol></font> 4L<font face=symbol><sup></sup></font>   [ML<sub>4</sub>]<sup>m</sup><font face=symbol><sup></sup></font><sup>4</sup> K<sub>a</sub> HL   H<font face=symbol><sup></sup></font> <font face=symbol></font> L<font face=symbol><sup></sup></font> K<sub>b</sub> What must be the value of the equilibrium constant, K<sub>overall</sub>, for the following overall reaction?, M<sup>m</sup><font face=symbol><sup></sup></font> <font face=symbol></font> 4HL   [ML<sub>4</sub>]<sup>m</sup><font face=symbol><sup></sup></font><sup>4</sup> <font face=symbol></font> 4H<font face=symbol><sup></sup></font> K<sub>overall</sub> [ML4]m4 Ka HL The equilibrium constants for the two reactions are known: M<sup>m</sup><font face=symbol><sup></sup></font> <font face=symbol></font> 4L<font face=symbol><sup></sup></font>   [ML<sub>4</sub>]<sup>m</sup><font face=symbol><sup></sup></font><sup>4</sup> K<sub>a</sub> HL   H<font face=symbol><sup></sup></font> <font face=symbol></font> L<font face=symbol><sup></sup></font> K<sub>b</sub> What must be the value of the equilibrium constant, K<sub>overall</sub>, for the following overall reaction?, M<sup>m</sup><font face=symbol><sup></sup></font> <font face=symbol></font> 4HL   [ML<sub>4</sub>]<sup>m</sup><font face=symbol><sup></sup></font><sup>4</sup> <font face=symbol></font> 4H<font face=symbol><sup></sup></font> K<sub>overall</sub> H L Kb What must be the value of the equilibrium constant, Koverall, for the following overall reaction?, Mm 4HL The equilibrium constants for the two reactions are known: M<sup>m</sup><font face=symbol><sup></sup></font> <font face=symbol></font> 4L<font face=symbol><sup></sup></font>   [ML<sub>4</sub>]<sup>m</sup><font face=symbol><sup></sup></font><sup>4</sup> K<sub>a</sub> HL   H<font face=symbol><sup></sup></font> <font face=symbol></font> L<font face=symbol><sup></sup></font> K<sub>b</sub> What must be the value of the equilibrium constant, K<sub>overall</sub>, for the following overall reaction?, M<sup>m</sup><font face=symbol><sup></sup></font> <font face=symbol></font> 4HL   [ML<sub>4</sub>]<sup>m</sup><font face=symbol><sup></sup></font><sup>4</sup> <font face=symbol></font> 4H<font face=symbol><sup></sup></font> K<sub>overall</sub> [ML4]m4 4H Koverall

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To solve an equation of the form To solve an equation of the form   for values of x, use ________ for values of x, use ________

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In a reversible reaction A In a reversible reaction A   B at a particular temperature, the rate constant for the reverse reaction is 4 times the rate constant for the forward reaction. What is the value of the equilibrium constant at that temperature? B at a particular temperature, the rate constant for the reverse reaction is 4 times the rate constant for the forward reaction. What is the value of the equilibrium constant at that temperature?

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A decrease in the number of moles of gas as the reaction goes from reactants to products in a gas-phase equilibrium results in ________

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Addition of reactants to a chemical reaction in solution or gas phase at equilibrium results in ________

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A 10.0 L flask at 500 K is filled with 0.30 mol of hydrogen and 0.30 mol of iodine. They react as indicated below. The equilibrium constant Kc 45.0. What are the equilibrium concentrations of the three gases? H2(g) I2(g) A 10.0 L flask at 500 K is filled with 0.30 mol of hydrogen and 0.30 mol of iodine. They react as indicated below. The equilibrium constant K<sub>c</sub> <font face=symbol></font> 45.0. What are the equilibrium concentrations of the three gases? H<sub>2</sub>(g) <font face=symbol></font> I<sub>2</sub>(g)   2HI(g) 2HI(g)

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In a reversible reaction A In a reversible reaction A   B at a particular temperature, the rate constant for the reverse reaction is twice the rate constant for the forward reaction. At equilibrium, how are the concentrations of A and B related? B at a particular temperature, the rate constant for the reverse reaction is twice the rate constant for the forward reaction. At equilibrium, how are the concentrations of A and B related?

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Which expression corresponds to the equilibrium constant Kc for the reaction written as 2NH3(g) 2O2(g) Which expression corresponds to the equilibrium constant K<sub>c</sub> for the reaction written as 2NH<sub>3</sub>(g) <font face=symbol></font> 2O<sub>2</sub>(g)   N<sub>2</sub>O(g) <font face=symbol></font> 3H<sub>2</sub>O<sub>2</sub>(g) N2O(g) 3H2O2(g)

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Given the following reactions and associated equilibrium constants Given the following reactions and associated equilibrium constants     2NO(g) K<sub>1 </sub><font face=symbol></font> 1.70 <font face=symbol></font> 10<font face=symbol><sup></sup></font><sup>13</sup>     NO<sub>2</sub>(g) K<sub>2 </sub><font face=symbol></font> 6.83 <font face=symbol></font> 10<sup>6</sup> What is the equilibrium constant for the following reaction? 2N<sub>2</sub>O(g) <font face=symbol></font> 3O<sub>2</sub>(g)   4NO<sub>2</sub>(g) K<sub>new </sub><font face=symbol></font> ? Given the following reactions and associated equilibrium constants     2NO(g) K<sub>1 </sub><font face=symbol></font> 1.70 <font face=symbol></font> 10<font face=symbol><sup></sup></font><sup>13</sup>     NO<sub>2</sub>(g) K<sub>2 </sub><font face=symbol></font> 6.83 <font face=symbol></font> 10<sup>6</sup> What is the equilibrium constant for the following reaction? 2N<sub>2</sub>O(g) <font face=symbol></font> 3O<sub>2</sub>(g)   4NO<sub>2</sub>(g) K<sub>new </sub><font face=symbol></font> ? 2NO(g) K1 1.70 1013 Given the following reactions and associated equilibrium constants     2NO(g) K<sub>1 </sub><font face=symbol></font> 1.70 <font face=symbol></font> 10<font face=symbol><sup></sup></font><sup>13</sup>     NO<sub>2</sub>(g) K<sub>2 </sub><font face=symbol></font> 6.83 <font face=symbol></font> 10<sup>6</sup> What is the equilibrium constant for the following reaction? 2N<sub>2</sub>O(g) <font face=symbol></font> 3O<sub>2</sub>(g)   4NO<sub>2</sub>(g) K<sub>new </sub><font face=symbol></font> ? Given the following reactions and associated equilibrium constants     2NO(g) K<sub>1 </sub><font face=symbol></font> 1.70 <font face=symbol></font> 10<font face=symbol><sup></sup></font><sup>13</sup>     NO<sub>2</sub>(g) K<sub>2 </sub><font face=symbol></font> 6.83 <font face=symbol></font> 10<sup>6</sup> What is the equilibrium constant for the following reaction? 2N<sub>2</sub>O(g) <font face=symbol></font> 3O<sub>2</sub>(g)   4NO<sub>2</sub>(g) K<sub>new </sub><font face=symbol></font> ? NO2(g) K2 6.83 106 What is the equilibrium constant for the following reaction? 2N2O(g) 3O2(g) Given the following reactions and associated equilibrium constants     2NO(g) K<sub>1 </sub><font face=symbol></font> 1.70 <font face=symbol></font> 10<font face=symbol><sup></sup></font><sup>13</sup>     NO<sub>2</sub>(g) K<sub>2 </sub><font face=symbol></font> 6.83 <font face=symbol></font> 10<sup>6</sup> What is the equilibrium constant for the following reaction? 2N<sub>2</sub>O(g) <font face=symbol></font> 3O<sub>2</sub>(g)   4NO<sub>2</sub>(g) K<sub>new </sub><font face=symbol></font> ? 4NO2(g) Knew ?

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Calculate K for the following reaction, provided the concentration versus time graph shown below. 2A Calculate K for the following reaction, provided the concentration versus time graph shown below. <sub> </sub>2A   2B <font face=symbol></font> 3C  2B 3C Calculate K for the following reaction, provided the concentration versus time graph shown below. <sub> </sub>2A   2B <font face=symbol></font> 3C

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Which one of the following is the equilibrium expression, KP, for the reaction that produces lime, CaO, from limestone, CaCO3? CaCO3(s) Which one of the following is the equilibrium expression, K<sub>P</sub>, for the reaction that produces lime, CaO, from limestone, CaCO<sub>3</sub>? CaCO<sub>3</sub>(s)   CaO(s) <font face=symbol></font> CO<sub>2</sub>(g) CaO(s) CO2(g)

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Given the reaction below, which of the following would cause an increase in the concentration of products? 4NH3(g) 3O2(g) Given the reaction below, which of the following would cause an increase in the concentration of products? 4NH<sub>3</sub>(g) <font face=symbol></font> 3O<sub>2</sub>(g)   2N<sub>2</sub>(g) <font face=symbol></font> 6H<sub>2</sub>O(g) I. addition of water II. removal of ammonia III. decrease of the volume of the container IV. addition of oxygen 2N2(g) 6H2O(g) I. addition of water II. removal of ammonia III. decrease of the volume of the container IV. addition of oxygen

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