Exam 17: Entropy Free Energy and Equilibrium

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The solubility product constant at 25°C for AgI(s)in water has the value 8.3 × 10-17.Calculate Δ\Delta Grxn at 25°C for the process AgI(s)  The solubility product constant at 25°C for AgI(s)in water has the value 8.3 × 10<sup>-17</sup>.Calculate  \Delta G<sub>rxn</sub> at 25°C for the process AgI(s)   <sub> </sub> Ag<sup>+</sup>(aq)+ I<sup>- </sup>(aq)where [Ag<sup>+</sup>] = 9.1 × 10<sup>-9</sup> and [I<sup>-</sup>] = 9.1 × 10<sup>-9</sup>. Ag+(aq)+ I- (aq)where [Ag+] = 9.1 × 10-9 and [I-] = 9.1 × 10-9.

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Predict the signs (-, +, or 0)of Δ\Delta H and Δ\Delta S, in that order, for the expansion of an ideal gas into a vacuum.

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The entropy of any pure substance at 0 K is 0 J/mol.

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A sample of solid naphthalene is introduced into an evacuated flask.Use the data below to calculate the equilibrium vapor pressure of naphthalene (C10H8)in the flask at 35°C. A sample of solid naphthalene is introduced into an evacuated flask.Use the data below to calculate the equilibrium vapor pressure of naphthalene (C<sub>10</sub>H<sub>8</sub>)in the flask at 35°C.

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For a given substance the entropy always increases in the following order: S (gas)< S (liq)< S (solid).

(True/False)
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Given the following data, estimate the boiling point of carbon disulfide, CS2, assuming that Δ\Delta S° and Δ\Delta H° are temperature-independent.  Given the following data, estimate the boiling point of carbon disulfide, CS<sub>2</sub>, assuming that  \Delta S° and  \Delta H° are temperature-independent.

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For the reaction CuS(s)+ H2(g)  For the reaction CuS(s)+ H<sub>2</sub>(g)   <sub> </sub> <sub> </sub>H<sub>2</sub>S(g)+ Cu(s),  \Delta G°<sub>f</sub> (CuS)= -53.6 kJ/mol  \Delta G°<sub>f</sub> (H<sub>2</sub>S)= -33.6 kJ/mol  \Delta H°<sub>f</sub> (CuS)= -53.1 kJ/mol  \Delta H°<sub>f</sub> (H<sub>2</sub>S)= -20.6 kJ/mol Calculate  \Delta G at 798 K and 1 atm pressure (assume  \Delta S°<sub> </sub>and  \Delta H° do not change with temperature). H2S(g)+ Cu(s), Δ\Delta G°f (CuS)= -53.6 kJ/mol Δ\Delta G°f (H2S)= -33.6 kJ/mol Δ\Delta H°f (CuS)= -53.1 kJ/mol Δ\Delta H°f (H2S)= -20.6 kJ/mol Calculate Δ\Delta G at 798 K and 1 atm pressure (assume Δ\Delta S° and Δ\Delta H° do not change with temperature).

(Short Answer)
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For the reaction HCONH2(g)  For the reaction HCONH<sub>2</sub>(g)   <sub> </sub> NH<sub>3</sub>(g)+ CO(g), K<sub>c</sub> = 4.84 at 400 K.If  \Delta H° for this reaction is 29 kJ/mol, find K<sub>c</sub> at 500 K. NH3(g)+ CO(g), Kc = 4.84 at 400 K.If Δ\Delta H° for this reaction is 29 kJ/mol, find Kc at 500 K.

(Multiple Choice)
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Melting an ionic solid always results in an increase in entropy.

(True/False)
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Find the temperature at which Kp = 4.00 for the reaction N2O4(g)  Find the temperature at which K<sub>p</sub> = 4.00 for the reaction N<sub>2</sub>O<sub>4</sub>(g)   <sub> </sub> 2NO<sub>2</sub>(g).[Given: at 25°C, for NO<sub>2</sub>(g),  \Delta H°<sub>f</sub> = 33.85 kJ/mol, S° = 240.46 J/mol·K; for N<sub>2</sub>O<sub>4</sub>(g),  \Delta H°<sub>f</sub> = 9.66 kJ/mol, S° = 304.3 J/mol·K; assume that  \Delta H° and  \Delta S° are independent of temperature.] 2NO2(g).[Given: at 25°C, for NO2(g), Δ\Delta H°f = 33.85 kJ/mol, S° = 240.46 J/mol·K; for N2O4(g), Δ\Delta H°f = 9.66 kJ/mol, S° = 304.3 J/mol·K; assume that Δ\Delta H° and Δ\Delta S° are independent of temperature.]

(Multiple Choice)
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Without reference to a table, arrange these reactions according to increasing Δ\Delta S. 1)CH4(g)+ H2O(g) →\rarr CO(g)+ 3H2(g) 2)C(s)+ O2(g) →\rarr CO2(g) 3)H2O2(l) →\rarr H2O(l)+ 1/2O2(g)

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For the reaction SbCl5(g)  For the reaction SbCl<sub>5</sub>(g)   <sub> </sub> SbCl<sub>3</sub>(g)+ Cl<sub>2</sub>(g),  \Delta G°<sub>f</sub> (SbCl<sub>5</sub>)= -334.34 kJ/mol  \Delta G°<sub>f</sub> (SbCl<sub>3</sub>)= -301.25 kJ/mol  \Delta H°<sub>f</sub> (SbCl<sub>5</sub>)= -394.34 kJ/mol  \Delta H°<sub>f</sub> (SbCl<sub>3</sub>)= -313.80 kJ/mol Calculate the value of the equilibrium constant (K<sub>p</sub>)at 800 K and 1 atm pressure. SbCl3(g)+ Cl2(g), Δ\Delta G°f (SbCl5)= -334.34 kJ/mol Δ\Delta G°f (SbCl3)= -301.25 kJ/mol Δ\Delta H°f (SbCl5)= -394.34 kJ/mol Δ\Delta H°f (SbCl3)= -313.80 kJ/mol Calculate the value of the equilibrium constant (Kp)at 800 K and 1 atm pressure.

(Short Answer)
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The equilibrium constant for the reaction AgBr(s)  The equilibrium constant for the reaction AgBr(s)   <sub> </sub> Ag<sup>+</sup>(aq)+ Br<sup>- </sup>(aq)is the solubility product constant, K<sub>sp</sub> = 7.7 × 10<sup>-13</sup> at 25°C.Calculate  \Delta G for the reaction when [Ag<sup>+</sup>] = 1.0 × 10<sup>-2</sup> M and [Br<sup>-</sup>] = 1.0 × 10<sup>-3</sup> M.Is the reaction spontaneous or nonspontaneous at these concentrations? Ag+(aq)+ Br- (aq)is the solubility product constant, Ksp = 7.7 × 10-13 at 25°C.Calculate Δ\Delta G for the reaction when [Ag+] = 1.0 × 10-2 M and [Br-] = 1.0 × 10-3 M.Is the reaction spontaneous or nonspontaneous at these concentrations?

(Multiple Choice)
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Sulfur can be separated from lead in the mineral galena, PbS(s), by "roasting" the ore in the presence of oxygen as shown in the following reaction: 2PbS(s)+ 3O2(g) →\rarr 2PbO(s)+ 2SO2(g) Calculate Δ\Delta S° for this reaction using the thermodynamic data provided below.  Sulfur can be separated from lead in the mineral galena, PbS(s), by roasting the ore in the presence of oxygen as shown in the following reaction:  2PbS(s)+ 3O<sub>2</sub>(g) \rarr 2PbO(s)+ 2SO<sub>2</sub>(g) Calculate  \Delta S° for this reaction using the thermodynamic data provided below.

(Multiple Choice)
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Under what conditions (always, never, high temperature only, low temperature only)is the process: H2O(l) →\rarr H2O(s)expected to be spontaneous?

(Short Answer)
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For the reaction H2O2(g) →\rarr H2O(g)+ 1/2O2(g), Δ\Delta H° = -106 kJ/mol and Δ\Delta S° = 58 J/K·mol at 25°C.Calculate Δ\Delta G° for this reaction at this temperature.

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The reaction rates of many spontaneous reactions are actually very slow.Which of these statements is the best explanation for this observation?

(Multiple Choice)
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Under what conditions (always, never, high temperature only, low temperature only)is the reaction O2(g) →\rarr 2O(g)expected to be spontaneous?

(Short Answer)
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For the reaction 2NO(g)+ O2(g) →\rarr 2NO2(g)if initially P(NO)= 1.5 atm, P(O2)= 1.4 atm, and P(NO2)= 2.0 atm, calculate Δ\Delta G for this reaction at 25°C.The following data is valid at 25°C:  For the reaction 2NO(g)+ O<sub>2</sub>(g) \rarr  2NO<sub>2</sub>(g)if initially P(NO)= 1.5 atm, P(O<sub>2</sub>)= 1.4 atm, and P(NO<sub>2</sub>)= 2.0 atm, calculate  \Delta G for this reaction at 25°C.The following data is valid at 25°C:

(Multiple Choice)
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At 1500°C the equilibrium constant for the reaction CO(g)+ 2H2(g)  At 1500°C the equilibrium constant for the reaction CO(g)+ 2H<sub>2</sub>(g)   <sub> </sub> CH<sub>3</sub>OH(g)has the value K<sub>p</sub> = 1.4 × 10<sup>-7</sup>.Calculate  \Delta G° for this reaction at 1500°C. CH3OH(g)has the value Kp = 1.4 × 10-7.Calculate Δ\Delta G° for this reaction at 1500°C.

(Multiple Choice)
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