Exam 14: Chemical Equilibrium

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Calculate Kp for the reaction 2NOCl(g) Calculate K<sub>p</sub> for the reaction 2NOCl(g)   <sub> </sub> <sub> </sub>2NO(g)+ Cl<sub>2</sub>(g)at 400°C if K<sub>c</sub> at 400°C for this reaction is 2.1 * 10<sup>-2</sup>. 2NO(g)+ Cl2(g)at 400°C if Kc at 400°C for this reaction is 2.1 * 10-2.

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D

If the reaction 2H2S(g) If the reaction 2H<sub>2</sub>S(g)   <sub> </sub> <sub> </sub>2H<sub>2</sub>(g)+ S<sub>2</sub>(g)is carried out at 1065°C, K<sub>p</sub> = 0.0120. Starting from pure H<sub>2</sub>S introduced into an evacuated vessel at 1065°C, what will the total pressure in the vessel be at equilibrium if the equilibrated mixture contains 0.300 atm of H<sub>2</sub>(g)? 2H2(g)+ S2(g)is carried out at 1065°C, Kp = 0.0120. Starting from pure H2S introduced into an evacuated vessel at 1065°C, what will the total pressure in the vessel be at equilibrium if the equilibrated mixture contains 0.300 atm of H2(g)?

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E

Hydrogen iodide decomposes according to the equation 2HI(g) Hydrogen iodide decomposes according to the equation 2HI(g)   <sub> </sub> H<sub>2</sub>(g)+ I<sub>2</sub>(g), for which K<sub>c</sub> = 0.0156 at 400ºC. 0.550 mol HI was injected into a 2.00 L reaction vessel at 400ºC.Calculate the concentration of HI at equilibrium. H2(g)+ I2(g), for which Kc = 0.0156 at 400ºC. 0.550 mol HI was injected into a 2.00 L reaction vessel at 400ºC.Calculate the concentration of HI at equilibrium.

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B

Consider the equilibrium equation C(s)+ H2O(g)+ 2296 J Consider the equilibrium equation C(s)+ H<sub>2</sub>O(g)+ 2296 J   <sub> </sub> CO(g)+ H<sub>2</sub>(g).What will happen to the concentration of carbon monoxide if the temperature of this system is raised? CO(g)+ H2(g).What will happen to the concentration of carbon monoxide if the temperature of this system is raised?

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Equilibrium constants are known for the following reactions: S(s)+ 3/2O2(g) Equilibrium constants are known for the following reactions: S(s)+ <sup>3</sup>/<sub>2</sub>O<sub>2</sub>(g)   <sub> </sub> SO<sub>3</sub>(g)K<sub>c</sub> = 9.2 * 10<sup>23</sup> <sup> </sup>SO<sub>3</sub>(g)   <sub> </sub> SO<sub>2</sub>(g)+ <sup>1</sup>/<sub>2</sub>O<sub>2</sub>(g)K<sub>c</sub> = 4.8 *10<sup>- 4</sup> <sup> </sup>Thus, for the reaction S(s)+ O<sub>2</sub>(g)   <sub> </sub> SO<sub>2</sub>(g), K<sub>c</sub> = 4.4 * 10<sup>20</sup>. SO3(g)Kc = 9.2 * 1023 SO3(g) Equilibrium constants are known for the following reactions: S(s)+ <sup>3</sup>/<sub>2</sub>O<sub>2</sub>(g)   <sub> </sub> SO<sub>3</sub>(g)K<sub>c</sub> = 9.2 * 10<sup>23</sup> <sup> </sup>SO<sub>3</sub>(g)   <sub> </sub> SO<sub>2</sub>(g)+ <sup>1</sup>/<sub>2</sub>O<sub>2</sub>(g)K<sub>c</sub> = 4.8 *10<sup>- 4</sup> <sup> </sup>Thus, for the reaction S(s)+ O<sub>2</sub>(g)   <sub> </sub> SO<sub>2</sub>(g), K<sub>c</sub> = 4.4 * 10<sup>20</sup>. SO2(g)+ 1/2O2(g)Kc = 4.8 *10- 4 Thus, for the reaction S(s)+ O2(g) Equilibrium constants are known for the following reactions: S(s)+ <sup>3</sup>/<sub>2</sub>O<sub>2</sub>(g)   <sub> </sub> SO<sub>3</sub>(g)K<sub>c</sub> = 9.2 * 10<sup>23</sup> <sup> </sup>SO<sub>3</sub>(g)   <sub> </sub> SO<sub>2</sub>(g)+ <sup>1</sup>/<sub>2</sub>O<sub>2</sub>(g)K<sub>c</sub> = 4.8 *10<sup>- 4</sup> <sup> </sup>Thus, for the reaction S(s)+ O<sub>2</sub>(g)   <sub> </sub> SO<sub>2</sub>(g), K<sub>c</sub> = 4.4 * 10<sup>20</sup>. SO2(g), Kc = 4.4 * 1020.

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Consider the following equilibrium, 4NH3(g)+ 3O2(g) Consider the following equilibrium, 4NH<sub>3</sub>(g)+ 3O<sub>2</sub>(g)   <sub> </sub> 2N<sub>2</sub>(g)+ 6H<sub>2</sub>O(g)+ 1531 kJ State whether the concentrations of the reactants would increase, decrease, or remain constant when the temperature is increased. 2N2(g)+ 6H2O(g)+ 1531 kJ State whether the concentrations of the reactants would increase, decrease, or remain constant when the temperature is increased.

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For the reaction at equilibrium 2SO3  For the reaction at equilibrium 2SO<sub>3</sub>   <sub> </sub> 2SO<sub>2</sub> + O<sub>2 </sub>( \Delta Hº<sub>rxn</sub>= 198 kJ/mol), if we increase the reaction temperature, the equilibrium will 2SO2 + O2 ( Δ\Delta Hºrxn= 198 kJ/mol), if we increase the reaction temperature, the equilibrium will

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Consider this gas phase equilibrium system: PCl5(g)  Consider this gas phase equilibrium system: PCl<sub>5</sub>(g)   <sub> </sub> PCl<sub>3</sub>(g)+ Cl<sub>2</sub>(g) \Delta Hº<sub>rxn</sub> = +87.8 kJ/mol. Which of these statements is false? PCl3(g)+ Cl2(g) Δ\Delta Hºrxn = +87.8 kJ/mol. Which of these statements is false?

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Kp for the reaction of SO2(g)with O2 to produce SO3(g)is 3 * 1024 .Calculate Kc for this equilibrium at 25ºC. (The relevant reaction is 2SO2(g)+ O2(g) K<sub>p</sub> for the reaction of SO<sub>2</sub>(g)with O<sub>2</sub> to produce SO<sub>3</sub>(g)is 3 * 10<sup>24</sup> .Calculate K<sub>c</sub> for this equilibrium at 25ºC. (The relevant reaction is 2SO<sub>2</sub>(g)+ O<sub>2</sub>(g)   <sub> </sub> <sub> </sub>2SO<sub>3</sub>(g).) 2SO3(g).)

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For the common allotropes of carbon (graphite and diamond), C(gr)  For the common allotropes of carbon (graphite and diamond), C(gr)   <sub> </sub>C(dia)with equilibrium constant K = 0.32. The molar volumes of graphite and diamond are, respectively, 5.30 cm<sup>3</sup>/mol and 3.42 cm<sup>3</sup>/mol;  \Delta H<sub>f</sub> of diamond is 1.90 kJ/mol. This data suggests that the formation of diamond is favored at C(dia)with equilibrium constant K = 0.32. The molar volumes of graphite and diamond are, respectively, 5.30 cm3/mol and 3.42 cm3/mol; Δ\Delta Hf of diamond is 1.90 kJ/mol. This data suggests that the formation of diamond is favored at

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For the following reaction at equilibrium, which one of the changes below would cause the equilibrium to shift to the left? 2NOBr(g)  For the following reaction at equilibrium, which one of the changes below would cause the equilibrium to shift to the left? 2NOBr(g)   <sub> </sub> 2NO(g)+ Br<sub>2</sub>(g),  \Delta Hº<sub>rxn</sub> = 30 kJ/mol 2NO(g)+ Br2(g), Δ\Delta Hºrxn = 30 kJ/mol

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The reaction 2SO3(g) The reaction 2SO<sub>3</sub>(g)   <sub> </sub> 2SO<sub>2</sub>(g)+ O<sub>2</sub>(g)is endothermic. If the temperature is increased, 2SO2(g)+ O2(g)is endothermic. If the temperature is increased,

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At 400ºC, Kc = 64 for the equilibrium H2(g)+ I2(g) At 400ºC, K<sub>c</sub> = 64 for the equilibrium H<sub>2</sub>(g)+ I<sub>2</sub>(g)   <sub> </sub> 2HI(g). If 3.00 mol H<sub>2</sub> and 3.00 mol I<sub>2</sub> are introduced into an empty 4.0 L vessel, find the equilibrium concentration of HI at 400ºC. 2HI(g). If 3.00 mol H2 and 3.00 mol I2 are introduced into an empty 4.0 L vessel, find the equilibrium concentration of HI at 400ºC.

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For the equilibrium reaction 2SO2(g)+ O2(g)  For the equilibrium reaction 2SO<sub>2</sub>(g)+ O<sub>2</sub>(g)   <sub> </sub> 2SO<sub>3</sub>(g),  \Delta Hº<sub>rxn</sub> = -198 kJ/mol. Which one of these factors would cause the equilibrium constant to increase? 2SO3(g), Δ\Delta Hºrxn = -198 kJ/mol. Which one of these factors would cause the equilibrium constant to increase?

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For the nitrogen fixation reaction 3H2(g)+ N2(g) For the nitrogen fixation reaction 3H<sub>2</sub>(g)+ N<sub>2</sub>(g)   <sub> </sub> 2NH<sub>3</sub>(g), K<sub>c</sub> = 6.0 * 10<sup>-2</sup> at 500°C. If 0.250 M H<sub>2</sub> and 0.050 M NH<sub>3</sub> are present at equilibrium, what is the equilibrium concentration of N<sub>2</sub>? 2NH3(g), Kc = 6.0 * 10-2 at 500°C. If 0.250 M H2 and 0.050 M NH3 are present at equilibrium, what is the equilibrium concentration of N2?

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Kc for the reaction CO2(g)+ H2(g) K<sub>c</sub> for the reaction CO<sub>2</sub>(g)+ H<sub>2</sub>(g)   <sub> </sub> H<sub>2</sub>O(g)+ CO(g)is 1.6 at about 990ºC.Calculate the number of moles of hydrogen gas in the final equilibrium system obtained by initially adding 1.00 mol of H<sub>2</sub>, 2.00 mol of CO<sub>2</sub>, 0.750 mol of H<sub>2</sub>O, and 1.00 mol of CO to a 5.00 L reactor at 990ºC. H2O(g)+ CO(g)is 1.6 at about 990ºC.Calculate the number of moles of hydrogen gas in the final equilibrium system obtained by initially adding 1.00 mol of H2, 2.00 mol of CO2, 0.750 mol of H2O, and 1.00 mol of CO to a 5.00 L reactor at 990ºC.

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When the following reaction is at equilibrium, which of these relationships is always true? 2NOCl(g) When the following reaction is at equilibrium, which of these relationships is always true? 2NOCl(g)   <sub> </sub> 2NO(g)+ Cl<sub>2</sub>(g) 2NO(g)+ Cl2(g)

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Consider the following equilibrium, 4NH3(g)+ 3O2(g) Consider the following equilibrium, 4NH<sub>3</sub>(g)+ 3O<sub>2</sub>(g)   <sub> </sub> 2N<sub>2</sub>(g)+ 6H<sub>2</sub>O(g)+ 1531 kJ State whether the concentrations the products would increase, decrease, or remain constant after nitrogen gas was removed from the system. 2N2(g)+ 6H2O(g)+ 1531 kJ State whether the concentrations the products would increase, decrease, or remain constant after nitrogen gas was removed from the system.

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Consider the reaction N2(g)+ 3H2(g) Consider the reaction N<sub>2</sub>(g)+ 3H<sub>2</sub>(g)   <sub> </sub> 2NH<sub>3</sub>(g). If we use a catalyst, which way will the reaction shift? 2NH3(g). If we use a catalyst, which way will the reaction shift?

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For the following reaction at equilibrium, which choice gives a change that will shift the position of equilibrium to favor formation of more products? 2NOBr(g)  For the following reaction at equilibrium, which choice gives a change that will shift the position of equilibrium to favor formation of more products? 2NOBr(g)   <sub> </sub> 2NO(g)+ Br<sub>2</sub>(g),  \Delta Hº<sub>rxn</sub> = 30 kJ/mol 2NO(g)+ Br2(g), Δ\Delta Hºrxn = 30 kJ/mol

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