Exam 13: Chemical Kinetics

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The first-order decomposition of phosphene to phosphorus and hydrogen, shown below, 4PH3(g) →\rarr P4(g) + 6H2(g) Has a half-life of 35.0 s at 680 ∘\circ C. Starting with 520 mmHg of pure phosphene in an 8.00-L flask at 680 ∘\circ C, how long will it take for the total pressure in the flask to rise to 1.000 atm

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For a second order reaction, the half-life is equal to

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In general, to calculate the activation energy for an elementary step given the rate constants at two different temperatures, which equation should be used

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In general, to calculate the rate constant for a second order reaction with respect to A, given an initial and final concentration as well as the time required for this change, which equation should be used

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Nitric oxide gas (NO) reacts with chlorine gas according to the chemical equation given below.NO + 1/2Cl2 →\rarr NOCl The following initial rates of reaction have been measured for the given reagent concentrations. Expt.\# Rate(M/hr) NO(M) () 1 1.19 0.50 0.50 2 4.79 1.00 0.50 3 9.59 1.00 1.00 Which of the following is the rate law (rate equation) for this reaction

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The data below were determined for the reaction shown below.S2O82- + 3I - (aq) →\rarr 2SO42- + I3- Expt. \# [I-] Initial Rate 1 0.038 0.060 1.4\times1/ 2 0.076 0.060 2.8\times1/ 3 0.076 0.030 1.4\times1/ The rate law for this reaction must be:

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With respect to the figure below, which choice correctly identifies all the numbered positions  With respect to the figure below, which choice correctly identifies all the numbered positions    \begin{array}{llll} ~~~~~~~~1.&~2.&~3.&~4.\\ \text { A. ~~catalyst } & \text { intermediate } & \text { activated complex } & \text { product } \\ \text { B. ~~reactants } & \text { activated complex } & \text { intermediate } & \text { product } \\ \text { C. ~~reactants } & \text { activated complex } & \text { catalyst } & \text { product } \\ \text { D. ~~reactants } & \text { intermediate } & \text { activated complex } & \text { product } \\ \text { E. ~~reactants } & \text { intermediate } & \text { activated complex } & \text { catalyst } \end{array} \nobreakspace\nobreakspace\nobreakspace\nobreakspace\nobreakspace\nobreakspace\nobreakspace\nobreakspace1. \nobreakspace2. \nobreakspace3. \nobreakspace4. A. \nobreakspace\nobreakspacecatalyst intermediate activated complex product B. \nobreakspace\nobreakspacereactants activated complex intermediate product C. \nobreakspace\nobreakspacereactants activated complex catalyst product D. \nobreakspace\nobreakspacereactants intermediate activated complex product E. \nobreakspace\nobreakspacereactants intermediate activated complex catalyst

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The reaction 2A →\rarr products is second order with respect toA. If the concentration of A drops from 1.05 M to 0.815 M in a time of 15.0 min, what is the rate constant for this reaction (the same time units may be used)

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The rate determining step in the following mechanism is bimolecular. \rightarrow+ slow +\rightarrow+ fast

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Which of the following elementary steps is termolecular

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For the chemical reaction system described by the diagram below, which statement is true For the chemical reaction system described by the diagram below, which statement is true

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A reaction was experimentally determined to follow the rate law, Rate = k[A]2 where k = 0.456 s-1M-1. Starting with [A]o = 0.500 M, how many seconds will it take for [A]t = 0.250 M

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At a certain temperature, the data below were collected for the reaction below.2ICl + H2 →\rarr I2 + 2HCl.Determine the rate constant for the reaction.  At a certain temperature, the data below were collected for the reaction below.2ICl + H<sub>2</sub>  \rarr I<sub>2</sub> + 2HCl.Determine the rate constant for the reaction.

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The isomerization of cyclopropane to form propene is a first-order reaction. The isomerization of cyclopropane to form propene is a first-order reaction.   At 760 K, 85% of a sample of cyclopropane changes to propene in 79.0 min. Determine the rate constant for this reaction at 760 K. At 760 K, 85% of a sample of cyclopropane changes to propene in 79.0 min. Determine the rate constant for this reaction at 760 K.

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A nuclear stress test utilizes a gamma-emitting radioisotope such as thallium-201 to follow the flow of blood through the heart - first at rest, and then under stress. The first-order rate constant for the decay of thallium-201 is 9.5 x 10-3 hr-1. Calculate how long it takes for the amount of thallium-201 to fall to 5.0% of its original value.

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The following mechanism has been suggested for the reaction: +2+2\rightarrow+2 +\rightarrow+ +\rightarrow ++\rightarrow+ Identify the molecularity of the rate determining step.

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The isomerization of cyclopropane to form propene is a first-order reaction. The isomerization of cyclopropane to form propene is a first-order reaction.   At 760 K, 15% of a sample of cyclopropane changes to propene in 6.8 min. What is the half-life of cyclopropane at 760 K At 760 K, 15% of a sample of cyclopropane changes to propene in 6.8 min. What is the half-life of cyclopropane at 760 K

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For the reaction X + Y →\rarr Z, the reaction rate is found to depend only upon the concentration of X. A plot of 1/X verses time gives a straight line.  For the reaction X + Y  \rarr  Z, the reaction rate is found to depend only upon the concentration of X. A plot of 1/X verses time gives a straight line.   What is the rate law for this reaction What is the rate law for this reaction

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Aspirin, C9H8O4, slowly decomposes at room temperature by reacting with water in the atmosphere to produce acetic acid, HC2H3O2, and 2-hydroxybenzoic acid, C7H6O3 (this is why old bottles of aspirin often smell like vinegar): C9H8O4 + H2O →\rarr HC2H3O2 + C7H6O3 Concentration and rate data for this reaction are given below. 0.0100 0.0200 2.4\times1 0.0100 0.0800 9.6\times1 0.0200 0.0200 4.8\times1 Write the rate law for this reaction and calculate k (be sure to include the correct units).

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For the reaction A + 3B →\rarr 2C, the rate of disappearance of B given by ( Δ\Delta [B]/ Δ\Delta t) may also be expressed as

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