Exam 17: Entropy Free Energy and Equilibrium

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Dissolving an ionic solid in water always results in an increase in entropy.

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Calculate Δ\Delta G ∘\circ for the reaction 3NO2(g) + H2O(l) →\rarr 2HNO3(l) + NO(g). \Delta(/) () -237.2 () -79.9 ( ) 86.7 () 51.8

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For the reaction CuS(s) + H2(g) ⇋\leftrightharpoons H2S(g) + Cu(s), Δ\Delta G ∘\circ f (CuS) = -53.6 kJ/mol Δ\Delta G ∘\circ f (H2S) = -33.6 kJ/mol Δ\Delta H ∘\circ f (CuS) = -53.1 kJ/mol Δ\Delta H ∘\circ f (H2S) = -20.6 kJ/mol Calculate the value of the equilibrium constant (Kp) at 798 K and 1 atm pressure.

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Which response includes all of the following processes that are accompanied by an increase of entropy I) NaCl(s)→H2ONa+(aq)+Cl−(aq) \mathrm{NaCl}(\mathrm{s}) \xrightarrow{\mathrm{H}_{2} \mathrm{O}} \mathrm{Na}^{+}(\mathrm{aq})+\mathrm{Cl}^{-}(\mathrm{aq}) II) CaSO4(s)→H2OCa2+(aq)+SO42−(aq) \mathrm{CaSO}_{4}(\mathrm{s}) \xrightarrow{\mathrm{H}_{2} \mathrm{O}} \mathrm{Ca}^{2+}(\mathrm{aq})+\mathrm{SO}_{4}{ }^{2-}(\mathrm{aq}) III) KNO3(s)→H2OK+(aq)+NO3−(aq) \mathrm{KNO}_{3}(\mathrm{s}) \xrightarrow{\mathrm{H}_{2} \mathrm{O}} \mathrm{K}^{+}(\mathrm{aq})+\mathrm{NO}_{3}^{-}(\mathrm{aq})

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The reaction 3H2(g) + N2(g) ⇋\leftrightharpoons 2NH3(g), Kc = 9.0 at 350 ∘\circ C proceeds from right to left when 1.0 mol NH3, 5.0 mol N2, and 5.0 mol H2 are mixed in a 2.5 L reactor.

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Find the temperature at which Kp = 4.00 for the reaction N2O4(g) ⇋\leftrightharpoons 2NO2(g). [Given: at 25 ∘\circ C, for NO2(g), Δ\Delta H ∘\circ f = 33.85 kJ/mol, S ∘\circ = 240.46 J/mol·K; for N2O4(g), Δ\Delta H ∘\circ f = 9.66 kJ/mol, S ∘\circ = 304.3 J/mol·K; assume that Δ\Delta H ∘\circ and Δ\Delta S ∘\circ are independent of temperature.]

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Sulfur can be separated from lead in the mineral galena, PbS(s), by "roasting" the ore in the presence of oxygen as shown in the following reaction: 2PbS(s) + 3O2(g) →\rarr 2PbO(s) + 2SO2(g) Calculate Δ\Delta S ∘\circ for this reaction using the thermodynamic data provided below. (/\cdot) (s) 91.2 (g) 205.0 (s) 69.45 (g) 248.5

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What is the free energy change for the reaction SiO2(s) + Pb(s) →\rarr PbO2(s) + Si(s) Δ\Delta G ∘\circ f (PbO2) = -217 kJ/mol Δ\Delta G ∘\circ f (SiO2) = -856 kJ/mol

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Given the following data, calculate the boiling point of HCOOH (formic acid). () -410 130 () -363 251

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Consider the reaction CO(g) + 2H2(g) ⇋\leftrightharpoons CH3OH(l) at 25 ∘\circ C. Δ\Delta G ∘\circ f (CO) = -137.3 kJ/mol Δ\Delta G ∘\circ f (CH3OH) = -166.3 kJ/mol Δ\Delta H ∘\circ f (CO) = -110.5 kJ/mol Δ\Delta H ∘\circ f (CH3OH) = -238.7 kJ/mol S ∘\circ (CO) = 197.9 J/K·mol S ∘\circ (CH3OH) = 126.8 J/K·mol Calculate S ∘\circ (H2(g)).

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The reaction: 6CO2(g) + 6H2O(g) →\rarr C6H12O6(g) + 6O2(g) is never expected to be spontaneous.

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Which of these species would you expect to have the lowest standard entropy (S ∘\circ )

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The normal boiling point of acetic acid is 118.1 ∘\circ C. If a sample of the acetic acid is at 125.2 ∘\circ C, predict the signs of Δ\Delta H, Δ\Delta S, and Δ\Delta G for the boiling process at this temperature.

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Sodium carbonate can be made by heating sodium bicarbonate: 2NaHCO3(s) →\rarr Na2CO3(s) + CO2(g) + H2O(g) Given that Δ\Delta H ∘\circ = 128.9 kJ/mol and Δ\Delta G ∘\circ = 33.1 kJ/mol at 25 ∘\circ C, above what minimum temperature will the reaction become spontaneous under standard state conditions

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Consider the reaction CO(g) + 2H2(g) ⇋\leftrightharpoons CH3OH(l) at 25 ∘\circ C. Δ\Delta G ∘\circ f (CO) = -137.3 kJ/mol Δ\Delta G ∘\circ f (CH3OH) = -166.3 kJ/mol Δ\Delta H ∘\circ f (CO) = -110.5 kJ/mol Δ\Delta H ∘\circ f (CH3OH) = -238.7 kJ/mol S ∘\circ (CO) = 197.9 J/K·mol S ∘\circ (CH3OH) = 126.8 J/K·mol Calculate the value of the equilibrium constant (Kp) for this reaction at 25 ∘\circ C.

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For the reaction SbCl5(g) ⇋\leftrightharpoons SbCl3(g) + Cl2(g), Δ\Delta G ∘\circ f (SbCl5) = -334.34 kJ/mol Δ\Delta G ∘\circ f (SbCl3) = -301.25 kJ/mol Δ\Delta H ∘\circ f (SbCl5) = -394.34 kJ/mol Δ\Delta H ∘\circ f (SbCl3) = -313.80 kJ/mol Calculate the value of the equilibrium constant (Kp) for this reaction at 298 K.

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Rubidium has a heat of vaporization of 69.0 kJ/mol at its boiling point (686 ∘\circ C). Calculate Δ\Delta S for this process, Rb(l) →\rarr Rb(g), at 1 atm and 686 ∘\circ C.

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At a given temperature, O2(g) at 5 atm has a higher entropy per mole than O2(g) at 0.5 atm.

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Arrange these reactions according to increasing Δ\Delta S. 1) H2O(g) →\rarr H2O(l) 2) 2NO(g) →\rarr N2(g) + O2(g) 3) MgCO3(s) →\rarr MgO(s) + CO2(g)

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Under the conditions of high temperatures only, the reaction O2(g) →\rarr 2O(g) would be expected to be spontaneous.

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