Exam 7: Enzyme Kinetics and Inhibition
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If a Lineweaver-Burk plot was made for an enzyme-catalyzed reaction, both with and without a noncompetitive inhibitor present, what difference would be seen?
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Correct Answer:
D
How are the kinetics of an enzyme-catalyzed reaction affected by a mixed inhibitor?
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Correct Answer:
A
Which of the following is true regarding transition state analogs?
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Correct Answer:
E
For a reaction A + B C, if [B] is much larger than [A] so that [B] essentially remains constant over the course of the reaction, the kinetics will be _____.
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In a bisubstrate reaction, reactant A binds, followed by reactant B which then get converted to products C and D. An experiment showed that B cannot bind without A having bound first. What mechanism is indicated by this data?
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Which of the following must be true for an enzymatic reaction obeying the Michaelis-Menten equation to reach 3/4 of its maximum velocity?
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Find kcat for a reaction in which Vmax is 4 × 10-4 mol•min-1 and the reaction mixture contains one microgram of enzyme (the molecular weight of the enzyme is 200,000
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How are the kinetics of an enzyme-catalyzed reaction affected by a competitive inhibitor?
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Which of the following types of enzyme-catalyzed reactions follows non-Michaelis-Menten kinetics?
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When is KM considered to be the same as the dissociation constant for the ES complex i.e., KM [E] [S] / [ES].
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How is an enzyme-catalyzed reaction affected by the addition of more enzyme?
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If a Lineweaver-Burk plot was made for an enzyme-catalyzed reaction, both with and without a competitive inhibitor present, what difference would be seen?
(Multiple Choice)
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In a bisubstrate reaction, reactant A binds and is then converted to product C. Next, reactant B binds and is then converted to product D. An experiment showed that B cannot bind without C being released first. What mechanism is indicated by this data?
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Which of the following properly expresses the Michaelis-Menten equation?
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Find the initial velocity for an enzymatic reaction when Vmax = 6.5 × 10-5 mol•sec-1, [S] = 3.0 × 10-3 M, KM = 4.5 × 10-3 M, and the enzyme concentration at time zero is 1.5 × 10-2 M.
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How are the kinetics of an enzyme-catalyzed reaction affected by a purely noncompetitive inhibitor?
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What type of inhibition explains why even at very high substrate concentrations, enzyme activity will decrease as time increases?
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What percentage of Vmax is obtained when the substrate is present at ¼ of the KM?
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