Exam 8: Microbial Genetics
Exam 1: The Microbial World and You65 Questions
Exam 2: Chemical Principles65 Questions
Exam 3: Observing Microorganisms Through a Microscope65 Questions
Exam 4: Functional Anatomy of Prokaryotic and Eukaryotic65 Questions
Exam 5: Microbial Metabolism67 Questions
Exam 6: Microbial Growth65 Questions
Exam 7: The Control of Microbial Growth67 Questions
Exam 8: Microbial Genetics65 Questions
Exam 9: Biotechnology and Dna Technology64 Questions
Exam 10: Classification of Microorganisms65 Questions
Exam 11: The Prokaryotes: Domains Bacteria and Archaea60 Questions
Exam 12: The Eukaryotes: Fungi, algae, protozoa, and Helminths65 Questions
Exam 13: Viruses,viroids,and Prions66 Questions
Exam 14: Principles of Disease and Epidemiology65 Questions
Exam 15: Microbial Mechanisms of Pathogenicity63 Questions
Exam 16: Innate Immunity: Nonspecific Defenses of the Host65 Questions
Exam 17: Adaptive Immunity: Specific Defenses of the Host65 Questions
Exam 18: Practical Applications of Immunology65 Questions
Exam 19: Disorders Associated With the Immune System67 Questions
Exam 20: Antimicrobial Drugs65 Questions
Exam 21: Microbial Diseases of the Skin and Eyes65 Questions
Exam 22: Microbial Diseases of the Nervous System65 Questions
Exam 23: Microbial Diseases of the Cardiovascular and Lymphatic Systems65 Questions
Exam 24: Microbial Diseases of the Respiratory System65 Questions
Exam 25: Microbial Diseases of the Digestive System66 Questions
Exam 26: Microbial Diseases of the Urinary and Reproductive Systems65 Questions
Exam 27: Environmental Microbiology65 Questions
Exam 28: Applied and Industrial Microbiology65 Questions
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Assume the two E.coli strains shown below are allowed to conjugate.
Hfr: pro⁺,arg⁺,his⁺,lys⁺,met⁺,ampicillin-sensitive
F-: pro⁻,arg⁻,his⁻,lys⁻,met⁻,ampicillin-resistant
What supplements would you add to glucose minimal salts agar to select for a new recombinant cell that is lys⁺,arg⁺,amp-resistant?
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(Multiple Choice)
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Correct Answer:
C
Figure 8.1
-In Figure 8.1,which colonies are streptomycin-resistant and leucine-requiring?
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Correct Answer:
D
Figure 8.2
-In Figure 8.2,if base 4 is adenine,what is base 4'?
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(Multiple Choice)
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Correct Answer:
B
Explain why the following statement is false: Sexual reproduction is the only mechanism for genetic change.
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An enzyme that makes covalent bonds between Okazaki fragments in the lagging strand of DNA being replicated is
(Multiple Choice)
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Which of the following statements regarding a bacterium that is R⁺ is FALSE?
(Multiple Choice)
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Which of the following statements about bacteriocins is FALSE?
(Multiple Choice)
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In the Ames test,any colonies that form on the control plates,in the absence of chemical being tested,should be the result of spontaneous mutations.
(True/False)
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According to the operon model,for the synthesis of an inducible enzyme to occur,the
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The miRNAs in a cell inhibit protein synthesis by forming complementary bonds with rRNA.
(True/False)
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Table 8.2
Codons in mRNA molecule and their corresponding amino acids
UUU Phenylalanine UAU tyrosine UUA leucine UAA nonsense GCA alanine AAU asparagine AAG lysine UGC cysteine GUU valine UCG, UCU serine
-Refer to Table 8.2.When amino acid sequences from a cell cycle control protein from a patient with cancer and a healthy person are aligned,the sequence from the cancer patient indicates one amino acid has changed from phenylalanine (Phe)to leucine (Leu).A mutation in the cancer patient's DNA must have taken place.Identify the result of this DNA change in the mRNA codon that led to this change in the protein sequence.
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Transposition (insertion of a transposon into a DNA sequence)results in the formation of base substitution mutations in a cell's DNA.
(True/False)
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An enzyme produced in response to the presence of a substrate is called a(n)
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The cancer gene ras produces mRNA containing an extra exon that includes a number of UAA codons.Cancer cells produce ras mRNA missing this exon.This mistake most likely is due to a mistake by
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When two genes from two different people are sequenced and aligned,it is discovered that there are multiple sequence differences in the coding segment DNA level.However,when the proteins formed by the genes have their amino acids sequenced,there is no difference observed between the two.What is the most likely explanation for this observation?
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