Exam 53: Tubular Reabsorption and Secretion

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The plasma concentration at which glucose first appears in the urine is called the

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The Tm for a secreted material, X, is

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The filtered load of large proteins is

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The clearance of inulin

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The clearance of inulin is 100 mL min-1 in a patient. His plasm a concentration of solute X is 0.2mg% and a 4-hour urine specimen was 240 m L, with a urinary concentration of solute X of 60 mg% . From this information you can conclude

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[TF/P] inulin at the end of the proximal tubule is 3 and at the same place [TF/P]Na = 1. You conclude from this that

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Amino acids are

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At then end of the proxim al tubule, [TF / P] for glucose is normally

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The relatively sm all fraction of proteins filtered by the glom erulus is

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Glucose reabsorption

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Creatinine clearance is a good approximation to the GFR because creatinine

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The filtered load of solute X is calculated as

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The graph of the filtered load of inulin plotted against the plasm a concentration of inulin is linear. This is because inulin is

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At the end of the proxim al tubule, [TF / P] for am ino acids is normally

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The kidney plays a major role in the regulation of plasma concentrations of

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The filtered load of glucose per day

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The greatest part of water and nutrient reabsorption occurs in the

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Splay in renal titration curves is caused by

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HCO3- reabsorption in the proxim al tubule

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“Splay” refers to

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