Question 1

Which naturally-occurring monosaccharide forms the Haworth structure shown?

Accepted Answer

A)    
B)    
C)    
D)    
A)    
B)    
C)    
D)    B

Question 2

Why are humans not able to digest cellulose?

Accepted Answer

A) Humans cannot digest glucose. 
B) Humans do not possess the enzyme necessary to hydrolyze the 1$\rightarrow$4-$\beta$-glycoside linkages found in cellulose. 
C) Humans do not possess the enzyme necessary to unwind the helical shape of the cellulose molecule. 
D) Humans do not possess the enzyme necessary to hydrolyze the 1$\rightarrow$4-$\alpha$-glycoside linkages found in cellulose. 
A) Humans cannot digest glucose. 
B) Humans do not possess the enzyme necessary to hydrolyze the 1$\rightarrow$4-$\beta$-glycoside linkages found in cellulose. 
C) Humans do not possess the enzyme necessary to unwind the helical shape of the cellulose molecule. 
D) Humans do not possess the enzyme necessary to hydrolyze the 1$\rightarrow$4-$\alpha$-glycoside linkages found in cellulose. B

Question 3

Modern glucose meters are electronic devices that measure the amount of oxidizing agent that reacts with the glucose in a known amount of blood.

Accepted Answer

A) True 
 B)False  True

Question 4

Individuals with type AB blood are called universal recipients because their blood contains no antibodies to blood types A, B, or O. Individuals with type AB blood can receive blood of any type.

Accepted Answer

A) True 
 B)False

Question 5

The structure shown has four (4)chirality centers and is a D monosaccharide.

Accepted Answer

A) True 
 B)False

Question 6

When converting a Fischer projection to a Haworth projection, where are all of the substituents on the right side of the carbon skeleton drawn in the Haworth projection?

Accepted Answer

A) down 
B) up 
C) down in an $\alpha$ anomer and up in a $\beta$ anomer 
D) down in an $\beta$ anomer and up in a $\alpha$anomer 
A) down 
B) up 
C) down in an $\alpha$ anomer and up in a $\beta$ anomer 
D) down in an $\beta$ anomer and up in a $\alpha$anomer

Question 7

In aldohexoses, it is the -OH group on C5 that reacts with the aldehyde carbonyl to form two cyclic hemiacetals called anomers.

Accepted Answer

A) True 
 B)False

Question 8

Which carbohydrates cannot be converted to simpler compounds by hydrolysis?

Accepted Answer

A) disaccharides 
B) monosaccharides 
C) polysaccharides 
D) starches 
A) disaccharides 
B) monosaccharides 
C) polysaccharides 
D) starches

Question 9

What product forms when the compound below is treated with Benedict's reagent?

Accepted Answer

A)    
B)    
C)    
D)    
E) No reaction occurs. 
A)    
B)    
C)    
D)    
E) No reaction occurs.

Question 10

The carbonyl group of an aldose is reduced to a secondary alcohol using hydrogen (H2)in the presence of palladium (Pd)metal.

Accepted Answer

A) True 
 B)False

Question 11

Which labeled carbon atom in the structure below is the anomeric carbon?

Accepted Answer

A) A 
B) B 
C) C 
D) D 
A) A 
B) B 
C) C 
D) D

Question 12

Certain monosaccharides-notably aldopentoses and ketohexoses-form five-membered rings, not six-membered rings, in solution.

Accepted Answer

A) True 
 B)False

Question 13

What is the classification of the compound shown below?

Accepted Answer

A) a tetraketose 
B) a ketotriose 
C) a ketotetrose 
D) an aldotriose 
A) a tetraketose 
B) a ketotriose 
C) a ketotetrose 
D) an aldotriose

Question 14

When a monosaccharide forms a cyclic hemiacetal, the carbon atom that is part of the hemiacetal is a new chirality center, called the anomeric carbon.

Accepted Answer

A) True 
 B)False

Question 15

Monosaccharides with a carbonyl group at C2 are called ketoses.

Accepted Answer

A) True 
 B)False

Question 16

Dihydroxyacetone, shown below, is the simplest ketose. Does the structure shown represent D-dihydroxyacetone or L-dihydroxyacetone?

Accepted Answer

A) D-dihydroxyacetone 
B) L-dihydroxyacetone 
C) Neither D nor L; dihydroxyacetone is not chiral 
D) It is impossible to tell from the Fischer projection alone. 
A) D-dihydroxyacetone 
B) L-dihydroxyacetone 
C) Neither D nor L; dihydroxyacetone is not chiral 
D) It is impossible to tell from the Fischer projection alone.

Question 17

All aldoses and ketoses are reducing sugars.

Accepted Answer

A) True 
 B)False

Question 18

Salicin is a naturally occurring, carbohydrate-containing pain reliever. Which statement concerning the functional groups present in salicin is incorrect?

Accepted Answer

A) Salicin contains an acetal. 
B) Salicin contains an alcohol. 
C) Salicin contains a hemiacetal. 
D) Salicin contains a phenol. 
A) Salicin contains an acetal. 
B) Salicin contains an alcohol. 
C) Salicin contains a hemiacetal. 
D) Salicin contains a phenol.

Question 19

In addition to the three monosaccharides that occur in all blood types, type A blood contains the monosaccharide N-acetyl-D-galactosamine, and type B blood contains an additional D-galactose unit.

Accepted Answer

A) True 
 B)False

Question 20

Dextrose is another name for the monosaccharide _____.

Accepted Answer

The answer of Dextrose is another name for the monosaccharide...

Exam 20: Carbohydrates

Which naturally-occurring monosaccharide forms the Haworth structure shown?

Why are humans not able to digest cellulose?

Modern glucose meters are electronic devices that measure the amount of oxidizing agent that reacts with the glucose in a known amount of blood.

Individuals with type AB blood are called universal recipients because their blood contains no antibodies to blood types A, B, or O. Individuals with type AB blood can receive blood of any type.

The structure shown has four (4)chirality centers and is a D monosaccharide.

When converting a Fischer projection to a Haworth projection, where are all of the substituents on the right side of the carbon skeleton drawn in the Haworth projection?

In aldohexoses, it is the -OH group on C5 that reacts with the aldehyde carbonyl to form two cyclic hemiacetals called anomers.

Which carbohydrates cannot be converted to simpler compounds by hydrolysis?

What product forms when the compound below is treated with Benedict's reagent?

The carbonyl group of an aldose is reduced to a secondary alcohol using hydrogen (H2)in the presence of palladium (Pd)metal.

Which labeled carbon atom in the structure below is the anomeric carbon?

Certain monosaccharides-notably aldopentoses and ketohexoses-form five-membered rings, not six-membered rings, in solution.

What is the classification of the compound shown below?

When a monosaccharide forms a cyclic hemiacetal, the carbon atom that is part of the hemiacetal is a new chirality center, called the anomeric carbon.

Monosaccharides with a carbonyl group at C2 are called ketoses.

Dihydroxyacetone, shown below, is the simplest ketose. Does the structure shown represent D-dihydroxyacetone or L-dihydroxyacetone?

All aldoses and ketoses are reducing sugars.

Salicin is a naturally occurring, carbohydrate-containing pain reliever. Which statement concerning the functional groups present in salicin is incorrect?

In addition to the three monosaccharides that occur in all blood types, type A blood contains the monosaccharide N-acetyl-D-galactosamine, and type B blood contains an additional D-galactose unit.

Dextrose is another name for the monosaccharide _____.

Matter and Measurement

Atoms and the Periodic Table

Ionic Compounds

Covalent Compounds

Chemical Reactions

Energy Changes, Reaction Rates, and Equilibrium

Gases, Liquids, and Solids

Solutions

Acids and Bases

Nuclear Chemistry

Introduction to Organic Molecules and Functional Groups

Alkanes

Unsaturated Hydrocarbons

Organic Compounds That Contain Oxygen, Halogen, or Sulfur

The Three-Dimensional Shape of Molecules

Aldehydes and Ketones

Carboxylic Acids, Esters, and Amides

Amines and Neurotransmitters

Lipids

Amino Acids, Proteins, and Enzymes

Nucleic Acids and Protein Synthesis

Digestion and the Conversion of Food Into Energy

Carbohydrate, Lipid, and Protein Metabolism

Filters

The carbonyl group of an aldose is reduced to a secondary alcohol using hydrogen (H₂)in the presence of palladium (Pd)metal.