Exam 48: Genetics and Heredity

A man with type B blood and normal skin pigment married a woman with type A blood and normal skin pigment. They had a child with type O blood who was albino. Give the genotypes for blood type and skin pigment for each parent.

The chromosome that has the fewest genes contains only 200 genes and is called:

One specific transcribed mRNA strand will always produce the same polypeptide.

A female who is red-green color blind must be heterozygous for the condition.

All female gametes carry the X chromosome.

The products of meiosis are:

Carriers of cystic fibrosis are thought to be protected from:

Gene replacement therapy attempts to add genetically altered cells to the body.

A mutation caused by the loss of nucleotide bases in DNA sequence is called a deletion mutation.

A disease carried on mDNA must be received from the mother.

The egg cytoplasm rather than the egg nucleus is responsible for transmission of mitochondrial DNA.

The genotype XXY results in Turner syndrome.

A genetic carrier is someone who has the gene but does not express the trait. An example would be someone who is heterozygous for a dominant/recessive trait.

People with xeroderma pigmentosum have a high risk of developing skin cancer.

Match each term with its corresponding definition or description. -Entire group of proteins encoded by the DNA of a cell

Color blindness is a sex-linked trait. Which of the following parental genotypes could produce a color-blind female? (X' indicates the color-blind trait.)

Mitochondrial DNA (mDNA):

An adult who is homozygous for Tay-Sachs disease is more resistant to TB.

In order for reproduction to be successful, all gametes must be haploid cells.

Crossing over is a unique phenomenon that prevents genetic variation among offspring of a single set of parents.