Consider the reaction \[\begin{array} { l } M \stackrel { k _ { 1 } } { \longrightarrow } M _ { a ds} ^ { + } + e ^ { - } \\ M _ { a ds } ^ { + } \stackrel { k _ { 2 } } { \longrightarrow } M _ { s o l } ^ { + } \end{array}\] . Frumkin isotherm is used to describe the adsorption. The kinetic parameter values are kS1U1B110S1U1B0 = 10S1U1P1-9 S1S1P0mol cmS1U1P1-2S1S1P0 sS1U1P1-1S1S1P0, bS1U1B11S1U1B0 = 10 VS1U1P1-1S1S1P0, g = 15, $\beta$S1U1B11S1U1B0 = -0.5 , kS1U1B120S1U1B0 = 10S1U1P1-8S1S1P0 mol cmS1U1P1-2S1S1P0 sS1U1P1-1S1S1P0, $\beta$S1U1B12S1U1B0 = +0.5 and $\varGamma$ = 10S1U1P1-8S1S1P0 mol cmS1U1P1-2S1S1P0. -The maximum number of 'loops' that can appear in complex plane plots is _____________

The answer of Consider the reaction \[\begin{array} { l...

Consider the reaction \[\begin{array} { l } M \stackrel { k _ { 1 } } { \longrightarrow } M _ { a ds } ^ { + } + e ^ { - } \\ M + M _ { a d s } ^ { + } \stackrel { k _ { 2 } } { \longrightarrow } M _ { a d s } ^ { + } + M _ { s o l } ^ { + } + e ^ { - } \\ M _ { a d s } ^ { + } \stackrel { k _ { s } } { \longrightarrow } M _ { s o l } ^ { + } \end{array}\] -The mass balance equation for fractional surface coverage of \[M _ { a d s} ^ { + }\] is given by

A) \[\Gamma \frac { d \theta } { d t } = k _ { 1 } ( 1 - \theta ) - k _ { 2 } \theta ( 1 - \theta ) + k _ { 3 } \theta\] B) \[\Gamma \frac { d \theta } { d t } = k _ { 1 } ( 1 - \theta ) - k _ { 2 } \theta ( 1 - \theta )\] C) \[\Gamma \frac { d \theta } { d t } = k _ { 1 } ( 1 - \theta ) - k _ { 2 } \theta ( 1 - \theta ) - k _ { 3 } \theta\] D) \[\Gamma \frac { d \theta } { d t } = k _ { 1 } ( 1 - \theta ) - k _ { 3 } \theta\] A) \[\Gamma \frac { d \theta } { d t } = k _ { 1 } ( 1 - \theta ) - k _ { 2 } \theta ( 1 - \theta ) + k _ { 3 } \theta\] B) \[\Gamma \frac { d \theta } { d t } = k _ { 1 } ( 1 - \theta ) - k _ { 2 } \theta ( 1 - \theta )\] C) \[\Gamma \frac { d \theta } { d t } = k _ { 1 } ( 1 - \theta ) - k _ { 2 } \theta ( 1 - \theta ) - k _ { 3 } \theta\] D) \[\Gamma \frac { d \theta } { d t } = k _ { 1 } ( 1 - \theta ) - k _ { 3 } \theta\]

Consider the reaction \[\begin{array} { l } M \stackrel { k _ { 1 } } { \longrightarrow } M _ { a ds } ^ { + } + e ^ { - } \\ M + M _ { a d s } ^ { + } \stackrel { k _ { 2 } } { \longrightarrow } M _ { a d s } ^ { + } + M _ { s o l } ^ { + } + e ^ { - } \\ M _ { a d s } ^ { + } \stackrel { k _ { s } } { \longrightarrow } M _ { s o l } ^ { + } \end{array}\] -In the same reaction, the equation for fractional surface coverage of Aads is given by

A) \[\frac { k _ { 1 { dc } } } { k _ { 1 { dc} } + k _ { 2 dc } + k _ { 3 {dc } } }\] B) \[\frac { k _ { 1 d c } } { k _ { 1 dc} + k _ { 3 d c } }\] C) \[\frac { k _ { 3 { dc } } } { k _ { 1 { dc } } + k _ { 2 d \dot { } } + k _ { 3 { dc } } }\] D) \[\frac { k _ { 3 { dc } } } { k _ { 1 {dc } } + k _ { 3 d c} }\] A) \[\frac { k _ { 1 { dc } } } { k _ { 1 { dc} } + k _ { 2 dc } + k _ { 3 {dc } } }\] B) \[\frac { k _ { 1 d c } } { k _ { 1 dc} + k _ { 3 d c } }\] C) \[\frac { k _ { 3 { dc } } } { k _ { 1 { dc } } + k _ { 2 d \dot { } } + k _ { 3 { dc } } }\] D) \[\frac { k _ { 3 { dc } } } { k _ { 1 {dc } } + k _ { 3 d c} }\]

Consider the reaction given by \[\begin{array} { l } M \stackrel { k _ { 1 } } { \longrightarrow } M _ { ads } ^ { + } + e ^ { - } \\ \\ M _ { a d s} ^ { + } \frac { k _ { 2 } } { \longleftarrow k _ { - 2 } } M _ { s o l } ^ { 2 + } + e ^ { - } \end{array}\] . -In the same mechanism, the faradaic impedance (ZF) is given by \[i _ { F } = F \left[ k _ { 1 } ( 1 - \theta ) + k _ { 2 } \theta - k _ { - 2 } ( 1 - \theta ) C _ { M _ { \mathbf { sol } } ^ { +2 } } \right]\]

A) \[\left( Z _ { F } \right) ^ { - 1 } = F \left( b _ { 1 } k _ { 1 dc } \left( 1 - \theta _ { ss } \right) + b _ { 2 } k _ { 2 d { c } } \theta _ { ss } - b _ { - 2 } k _ { - 2 d c } C _ { M _ {sol } ^ { +2 } } \left( 1 - \theta _ { s s } \right) - \left( k _ { 1 d c } - k _ { 2 dc } + k _ { - 2 d c } C _ { M _ {sol} ^ {+ 2 } } \right) \frac { d \theta } { d E } \right)\] B) \[\left( Z _ { F } \right) ^ { - 1 } = F \left( b _ { 1 } k _ { 1 d c } \left( 1 - \theta _ { ss } \right) + b _ { 2 } k _ { 2 d { c } } \theta _ { ss } - b _ { - 2 } k _ { - 2 d c } C _ { M _ {sol } ^ { +2 } } \left( 1 - \theta _ { s s } \right) - \left( k _ { 1 d c } - k _ { 2 dc } + k _ { - 2 d c } C _ { M _ {sol} ^ {+ 2 } } \right) \frac { d \theta } { d E } \right)\] C) \[\left( Z _ { F } \right) ^ { - 1 } = F \left( b _ { 1 } k _ { 1 { dc } } \left( 1 - \theta _ { s s } \right) + b _ { 2 } k _ { 2 {dc } } \theta _ { ss } - \left( k _ { 1 { dc } } - k _ { 2 d { c } } + k _ { - 2 { dc } } C _ { M^{+2} _ { { sol } } } \right) \frac { d \theta } { d E } \right)\] D) \[\left( Z _ { F } \right) ^ { - 1 } = F \left( b _ { 1 } k _ { 1 d c } \left( 1 - \theta _ { ss } \right) + b _ { 2 } k _ { 2 d { c } } \theta _ { ss } - b _ { - 2 } k _ { - 2 d c } C _ { M _ {sol } ^ { +2 } } \left( 1 - \theta _ { s s } \right) +\left( k _ { 1 d c } - k _ { 2 dc } + k _ { - 2 d c } C _ { M _ {sol} ^ {+ 2 } } \right) \frac { d \theta } { d E } \right)\] A) \[\left( Z _ { F } \right) ^ { - 1 } = F \left( b _ { 1 } k _ { 1 dc } \left( 1 - \theta _ { ss } \right) + b _ { 2 } k _ { 2 d { c } } \theta _ { ss } - b _ { - 2 } k _ { - 2 d c } C _ { M _ {sol } ^ { +2 } } \left( 1 - \theta _ { s s } \right) - \left( k _ { 1 d c } - k _ { 2 dc } + k _ { - 2 d c } C _ { M _ {sol} ^ {+ 2 } } \right) \frac { d \theta } { d E } \right)\] B) \[\left( Z _ { F } \right) ^ { - 1 } = F \left( b _ { 1 } k _ { 1 d c } \left( 1 - \theta _ { ss } \right) + b _ { 2 } k _ { 2 d { c } } \theta _ { ss } - b _ { - 2 } k _ { - 2 d c } C _ { M _ {sol } ^ { +2 } } \left( 1 - \theta _ { s s } \right) - \left( k _ { 1 d c } - k _ { 2 dc } + k _ { - 2 d c } C _ { M _ {sol} ^ {+ 2 } } \right) \frac { d \theta } { d E } \right)\] C) \[\left( Z _ { F } \right) ^ { - 1 } = F \left( b _ { 1 } k _ { 1 { dc } } \left( 1 - \theta _ { s s } \right) + b _ { 2 } k _ { 2 {dc } } \theta _ { ss } - \left( k _ { 1 { dc } } - k _ { 2 d { c } } + k _ { - 2 { dc } } C _ { M^{+2} _ { { sol } } } \right) \frac { d \theta } { d E } \right)\] D) \[\left( Z _ { F } \right) ^ { - 1 } = F \left( b _ { 1 } k _ { 1 d c } \left( 1 - \theta _ { ss } \right) + b _ { 2 } k _ { 2 d { c } } \theta _ { ss } - b _ { - 2 } k _ { - 2 d c } C _ { M _ {sol } ^ { +2 } } \left( 1 - \theta _ { s s } \right) +\left( k _ { 1 d c } - k _ { 2 dc } + k _ { - 2 d c } C _ { M _ {sol} ^ {+ 2 } } \right) \frac { d \theta } { d E } \right)\]

Consider the reaction \[\begin{array} { l } P _ { s o l }\underset { k _ { - 1 } } { \stackrel { k _ { 1 } } { \rightleftarrows } }Q _ { - s o l } + e ^ { - } \\ A _ { s ol } ^ { - } \underset { k _ { - 2 } } { \stackrel { k _ { 2 } } { \rightleftarrows } } A _ { a d s } + e ^ { - } \\ \end{array}\] -In the same reaction, the expression for \[\frac { d \theta } { d E }\] is given by

A) \[\frac { d \theta } { d E } = \frac { b _ { 2 } k _ { 2dc } \left[ A _ { so l } ^ { - } \right] - b _ { - 2 } k _ { - 2 dc} } { k _ { 2 dc } \left[ A _ { s ol } ^ { - } \right] + k _ { - 2 { dc} } + j \omega \Gamma }\] B) \[\frac { d \theta } { d E } = \frac { b _ { 2 } k _ { 2 dc } \left[ A _ { s ol } ^ { - } \right] \left( 1 - \theta _ { ss } \right) - b _ { - 2 } k _ { - 2 dc } \theta _ { s s } } { k _ { 2 d c} \left[ A _ { so l } ^ { - } \right] \left( 1 - \theta _ { s s } \right) + k _ { - 2 dc } \theta _ { ss } + j \omega \Gamma }\] C) \[\frac { d \theta } { d E } = \frac { b _ { 2 } k _ { 2dc } \left[ A _ { s o l } ^ { - } \right] \left( 1 - \theta _ { s s } \right) - b _ { - 2 } k _ { - 2 dc } \theta _ { s s } } { k _ { 2 dc } \left[ A _ { s o l } ^ { - } \right] + k _ { - 2 dc } + j \omega \Gamma }\] D) \[\frac { d \theta } { d E } = \frac { b _ { 2 } k _ { 2 dc } \left[ A _ { s o l } ^ { - } \right] - b _ { - 2 } k _ { - 2 d c } } { k _ { 2 d \dot { } } \left[ A _ { s o l } ^ { - } \right] \left( 1 - \theta _ { s s } \right) + k _ { - 2 d c } \theta _ { s s} + j \omega \Gamma }\] A) \[\frac { d \theta } { d E } = \frac { b _ { 2 } k _ { 2dc } \left[ A _ { so l } ^ { - } \right] - b _ { - 2 } k _ { - 2 dc} } { k _ { 2 dc } \left[ A _ { s ol } ^ { - } \right] + k _ { - 2 { dc} } + j \omega \Gamma }\] B) \[\frac { d \theta } { d E } = \frac { b _ { 2 } k _ { 2 dc } \left[ A _ { s ol } ^ { - } \right] \left( 1 - \theta _ { ss } \right) - b _ { - 2 } k _ { - 2 dc } \theta _ { s s } } { k _ { 2 d c} \left[ A _ { so l } ^ { - } \right] \left( 1 - \theta _ { s s } \right) + k _ { - 2 dc } \theta _ { ss } + j \omega \Gamma }\] C) \[\frac { d \theta } { d E } = \frac { b _ { 2 } k _ { 2dc } \left[ A _ { s o l } ^ { - } \right] \left( 1 - \theta _ { s s } \right) - b _ { - 2 } k _ { - 2 dc } \theta _ { s s } } { k _ { 2 dc } \left[ A _ { s o l } ^ { - } \right] + k _ { - 2 dc } + j \omega \Gamma }\] D) \[\frac { d \theta } { d E } = \frac { b _ { 2 } k _ { 2 dc } \left[ A _ { s o l } ^ { - } \right] - b _ { - 2 } k _ { - 2 d c } } { k _ { 2 d \dot { } } \left[ A _ { s o l } ^ { - } \right] \left( 1 - \theta _ { s s } \right) + k _ { - 2 d c } \theta _ { s s} + j \omega \Gamma }\]

Consider the reaction \[\begin{array} { l } P _ { s o l }\underset { k _ { - 1 } } { \stackrel { k _ { 1 } } { \rightleftarrows } }Q _ { - s o l } + e ^ { - } \\ A _ { s ol } ^ { - } \underset { k _ { - 2 } } { \stackrel { k _ { 2 } } { \rightleftarrows } } A _ { a d s } + e ^ { - } \\ \end{array}\] -For the above mechanism, the number of electrical elements (including polarization resistance) required to model the Faradaic impedance is _____

The answer of Consider the reaction \[\begin{array} { l }...

Consider the reaction \[\begin{array} { l } P _ { s o l }\underset { k _ { - 1 } } { \stackrel { k _ { 1 } } { \rightleftarrows } }Q _ { - s o l } + e ^ { - } \\ A _ { s ol } ^ { - } \underset { k _ { - 2 } } { \stackrel { k _ { 2 } } { \rightleftarrows } } A _ { a d s } + e ^ { - } \\ \end{array}\] -In the same reaction, the equation for fractional surface coverage of Aads is given by

A) \[\frac { k _ { 2 d c } \left[ A _ { s d } ^ { - } \right] } { k _ { 1 d \dot { k } } \left[ P _ { s o l } \right] - k _ { - 1 } \left[ Q _ { s o l } \right] + k _ { 2 d c } \left[ A _ { s o l } ^ { - } \right] + k _ { - 2 d c } }\] B) \[\frac { k _ { 1 { dc} } \left[ P _ { s o l } \right] + k _ { 2 {dc } } \left[ A _ { sol } ^ { - } \right] } { k _ { 1 { dc } } \left[ P _ { s o l ] } \right] - k _ { - 1 } \left[ Q _ { s o l } \right] k _ { 2 { dc } } \left[ A _ { s ol } ^ { - } \right] + k _ { - 2 { dc } } }\] C) \[\frac { k _ { 1 { dc } } \left[ P _ { s o l } \right] - k _ { - 1 } \left[ Q _ { s o l } \right] + k _ { 2{ dc } } \left[ A _ { s o l } ^ { - } \right] } { k _ { 1 \dot { k } } \left[ P _ { s o l } \right] - k _ { - 1 } \left[ Q _ { s o l } \right] + k _ { 2{dc } } \left[ A _ { s o l } ^ { - } \right] + k _ { - 2 { dc } } }\] D) \[\frac { k _ { 2dc } \left[ A _ { s o l } ^ { - } \right] } { k _ { 2 dc } \left[ A _ { s o l } ^ { - } \right] + k _ { - 2 dc } }\] A) \[\frac { k _ { 2 d c } \left[ A _ { s d } ^ { - } \right] } { k _ { 1 d \dot { k } } \left[ P _ { s o l } \right] - k _ { - 1 } \left[ Q _ { s o l } \right] + k _ { 2 d c } \left[ A _ { s o l } ^ { - } \right] + k _ { - 2 d c } }\] B) \[\frac { k _ { 1 { dc} } \left[ P _ { s o l } \right] + k _ { 2 {dc } } \left[ A _ { sol } ^ { - } \right] } { k _ { 1 { dc } } \left[ P _ { s o l ] } \right] - k _ { - 1 } \left[ Q _ { s o l } \right] k _ { 2 { dc } } \left[ A _ { s ol } ^ { - } \right] + k _ { - 2 { dc } } }\] C) \[\frac { k _ { 1 { dc } } \left[ P _ { s o l } \right] - k _ { - 1 } \left[ Q _ { s o l } \right] + k _ { 2{ dc } } \left[ A _ { s o l } ^ { - } \right] } { k _ { 1 \dot { k } } \left[ P _ { s o l } \right] - k _ { - 1 } \left[ Q _ { s o l } \right] + k _ { 2{dc } } \left[ A _ { s o l } ^ { - } \right] + k _ { - 2 { dc } } }\] D) \[\frac { k _ { 2dc } \left[ A _ { s o l } ^ { - } \right] } { k _ { 2 dc } \left[ A _ { s o l } ^ { - } \right] + k _ { - 2 dc } }\]

Consider a reaction given by $\begin{array} { l } M \underset { k _ { - 1 } } { \stackrel { k _ { 1 } } { \rightleftarrows } } M _ { a ds } ^ { + } + e ^ { - } \\ M _ { a d s } ^ { + }\underset { k _ { - 2 } } { \stackrel { k _ { 2 } } { \rightleftarrows } } M _ { sol } ^ { + } \end{array}$ . -In the same mechanism, the value of \[\frac { d \theta } { d E }\] is given by

A) $\frac{\left(b_{1} k_{1 ak}\left(1-\theta_{s s}\right)-b_{-1} k_{-1ak} \theta_{ss}\right)}{\left(k_{1 dak}+k_{-1 ak}+k_{2}+k_{-2} C_{M_{2a}^{2}}+j \omega \Gamma\right)}$ B) \[\frac { \left( b _ { 1 } k _ { 1 \dot {dc } } - b _ { - 1 } k _ { - 1 \dot {dc } } \right) } { \left( k _ { 1 \dot { dc} } + k _ { - 1 \dot { dc } } + k _ { 2 } + k _ { - 2 } + j \omega \Gamma \right) }\] C) \[\frac { \left( b _ { 1 } k _ { 1 \dot { d } } - b _ { - 1 } k _ { - 1 \dot { \alpha } } \right) } { \left( k _ { 1 \dot { \alpha } } + k _ { - 1 \dot { k } } + k _ { 2 } + j \Gamma \Gamma \right) }\] D) \[\frac { \left( b _ { 1 } k _ { 1 \dot { dc } } \right) } { \left( k _ { 1 \dot { dc} } + k _ { - 1 \dot { dc } } + k _ { 2 } + j \omega \Gamma \right) }\] A) $\frac{\left(b_{1} k_{1 ak}\left(1-\theta_{s s}\right)-b_{-1} k_{-1ak} \theta_{ss}\right)}{\left(k_{1 dak}+k_{-1 ak}+k_{2}+k_{-2} C_{M_{2a}^{2}}+j \omega \Gamma\right)}$ B) \[\frac { \left( b _ { 1 } k _ { 1 \dot {dc } } - b _ { - 1 } k _ { - 1 \dot {dc } } \right) } { \left( k _ { 1 \dot { dc} } + k _ { - 1 \dot { dc } } + k _ { 2 } + k _ { - 2 } + j \omega \Gamma \right) }\] C) \[\frac { \left( b _ { 1 } k _ { 1 \dot { d } } - b _ { - 1 } k _ { - 1 \dot { \alpha } } \right) } { \left( k _ { 1 \dot { \alpha } } + k _ { - 1 \dot { k } } + k _ { 2 } + j \Gamma \Gamma \right) }\] D) \[\frac { \left( b _ { 1 } k _ { 1 \dot { dc } } \right) } { \left( k _ { 1 \dot { dc} } + k _ { - 1 \dot { dc } } + k _ { 2 } + j \omega \Gamma \right) }\]

Consider the reaction \[\begin{array} { l } P _ { s a } \stackrel { k _ { 1 } } { \longrightarrow } Q _ { s a } + e ^ { - } \\ A _ { s i l } ^ { - } \underset { k _ { - 2 } } { \stackrel { k _ { 2 } } { \rightleftarrows } } A _ { \alpha i j } + e ^ { - } \\ \end{array}\] The kinetic parameters are given by kS1U1B110S1U1B0 = 10S1U1P1-5 S1S1P0cm sS1U1P1-1S1S1P0, bS1U1B11S1U1B0 = 20 VS1U1P1-1S1S1P0, kS1U1B120S1U1B0 = 10S1U1P1-6S1S1P0 cm sS1U1P1-1S1S1P0, bS1U1B12S1U1B0 = 20 VS1U1P1-1S1S1P0, kS1U1B1-20S1U1B0 =10S1U1P1-6S1S1P0 mol cmS1U1P1-2S1S1P0 sS1U1P1-1S1S1P0 , bS1U1B1-2S1U1B0 = -18 VS1U1P1-1S1S1P0 and $\varGamma$ = 10S1U1P1-8S1S1P0 mol cmS1U1P1-2S1S1P0. Solution species concentrations are given by [PS1U1B1solS1U1B0] = [QS1U1B1solS1U1B0] =[ \[A _ { s o l } ^ { - }\] ] = 100 mM. -The equation for fractional surface coverage of Aads is given by

A) \[\frac { k _ { 2 \dot { dc } } } { k _ { 2 k \dot { dc } } + k _ { - 2 \dot { dc } } + k _ { 1 \dot { dc } } }\] B) \[\frac { k _ { 2 dc } } { k _ { 2dc } + k _ { - 2 \dot {dc } } }\] C) $\frac{k_{2 dc} C_{\mathcal{A}^-_{\mathrm{sol}}}}{k_{2 dc} C_{A^-_{sol}}+k_{-2 d c}+k_{1 d c} C_{P_{sol}}}$ D) $\frac{k_{2 dc} C_{A^-_{sol}}}{k_{2 dc} C_{A^-_{sol}}+k_{-2dc}}$ A) \[\frac { k _ { 2 \dot { dc } } } { k _ { 2 k \dot { dc } } + k _ { - 2 \dot { dc } } + k _ { 1 \dot { dc } } }\] B) \[\frac { k _ { 2 dc } } { k _ { 2dc } + k _ { - 2 \dot {dc } } }\] C) $\frac{k_{2 dc} C_{\mathcal{A}^-_{\mathrm{sol}}}}{k_{2 dc} C_{A^-_{sol}}+k_{-2 d c}+k_{1 d c} C_{P_{sol}}}$ D) $\frac{k_{2 dc} C_{A^-_{sol}}}{k_{2 dc} C_{A^-_{sol}}+k_{-2dc}}$

Consider the reaction \[\begin{array} { l } M \underset { k _ { - 1 } } { \stackrel { k _ { 1 } } { \rightleftarrows } } M _ { a ds } ^ { + } + e ^ { - } \\ M _ { a ds } ^ { + } + M \stackrel { k _ {2 } } { \longrightarrow } M _ { ads} ^ { + } +M _ { sol } ^ { + } + e ^ { - } \end{array}\] The kinetic parameters are given by kS1U1B110S1U1B0 = 10S1U1P1-S1S1P0S1U1P19S1S1P0S1U1P1 S1S1P0mol cmS1U1P1-2S1S1P0 sS1U1P1-1S1S1P0, bS1U1B11S1U1B0 = 10 VS1U1P1-1S1S1P0, kS1U1B1-1S1U1B0S1U1B10S1U1B0 = 10S1U1P1-S1S1P0S1U1P18S1S1P0 mol cmS1U1P1-S1S1P0S1U1P12S1S1P0 sS1U1P1-1S1S1P0, bS1U1B1-1S1U1B0 = -10 VS1U1P1-1S1S1P0, kS1U1B120S1U1B0 = 10S1U1P1-8S1S1P0 mol cmS1U1P1-2S1S1P0 sS1U1P1-1S1S1P0, bS1U1B12S1U1B0 = 10 VS1U1P1-1S1S1P0 and$\varGamma$ = 10S1U1P1-8S1S1P0 mol cmS1U1P1-2S1S1P0. -To model a system with the above mechanism, the minimum number of dc potentials at which EIS data should be taken to avoid an infinite number of solutions is __________

The answer of Consider the reaction \[\begin{array} { l...

Consider the reaction \[\begin{array} { l } M \stackrel { k _ { 1 } } { \longrightarrow } M _ { a ds } ^ { + } + e ^ { - } \\ M + M _ { a d s } ^ { + } \stackrel { k _ { 2 } } { \longrightarrow } M _ { a d s } ^ { + } + M _ { s o l } ^ { + } + e ^ { - } \\ M _ { a d s } ^ { + } \stackrel { k _ { s } } { \longrightarrow } M _ { s o l } ^ { + } \end{array}\] -In the same reaction, the expression for \[\frac { d \theta } { d E }\] is given by

A) \[\frac { d \theta } { d E } = \frac { b _ { 1 } k _ { 1 d c } \left( 1 - \theta _ { s s } \right) - b _ { 2 } k _ { 2 { dc } } \theta _ { ss } \left( 1 - \theta _ { s s } \right) } { k _ { 1 { dc } } + k _ { 2 d c} + j \omega \Gamma }\] B) \[\frac { d \theta } { d E } = \frac { b _ { 1 } k _ { 1 dc } \left( 1 - \theta _ { s s } \right) - b _ { 2 } k _ { 2 { dc } } \theta _ { ss } \left( 1 - \theta _ { s s } \right) } { k _ { 1 dc } + k _ { 2 d c} + k _ { 3 } + j \omega \Gamma }\] C) \[\frac { d \theta } { d E } = \frac { b _ { 1 } k _ { 1 dc } \left( 1 - \theta _ { ss} \right) } { k _ { 1dc } + k _ { 3 } + j \omega \Gamma }\] D) \[\frac { d \theta } { d E } = \frac { b _ { 1 } k _ { 1 dc } \left( 1 - \theta _ { s s } \right) - b _ { 2 } k _ { 2 dc } \theta _ { s s } } { k _ { 1 dc } + k _ { 2 dc } + k _ { 3 } + j \omega \Gamma }\] A) \[\frac { d \theta } { d E } = \frac { b _ { 1 } k _ { 1 d c } \left( 1 - \theta _ { s s } \right) - b _ { 2 } k _ { 2 { dc } } \theta _ { ss } \left( 1 - \theta _ { s s } \right) } { k _ { 1 { dc } } + k _ { 2 d c} + j \omega \Gamma }\] B) \[\frac { d \theta } { d E } = \frac { b _ { 1 } k _ { 1 dc } \left( 1 - \theta _ { s s } \right) - b _ { 2 } k _ { 2 { dc } } \theta _ { ss } \left( 1 - \theta _ { s s } \right) } { k _ { 1 dc } + k _ { 2 d c} + k _ { 3 } + j \omega \Gamma }\] C) \[\frac { d \theta } { d E } = \frac { b _ { 1 } k _ { 1 dc } \left( 1 - \theta _ { ss} \right) } { k _ { 1dc } + k _ { 3 } + j \omega \Gamma }\] D) \[\frac { d \theta } { d E } = \frac { b _ { 1 } k _ { 1 dc } \left( 1 - \theta _ { s s } \right) - b _ { 2 } k _ { 2 dc } \theta _ { s s } } { k _ { 1 dc } + k _ { 2 dc } + k _ { 3 } + j \omega \Gamma }\]

Consider the reaction \[\begin{array} { l } M \stackrel { k _ { 1 } } { \longrightarrow } M _ { a ds } ^ { + } + e ^ { - } \\ M + M _ { a d s } ^ { + } \stackrel { k _ { 2 } } { \longrightarrow } M _ { a d s } ^ { + } + M _ { s o l } ^ { + } + e ^ { - } \\ M _ { a d s } ^ { + } \stackrel { k _ { s } } { \longrightarrow } M _ { s o l } ^ { + } \end{array}\] -In the same reaction, the faradaic current is given by

A) \[i _ { F } = F \left\{ k _ { 1 } ( 1 - \theta ) + k _ { 2 } \theta ( 1 - \theta ) \right\}\] B) \[i _ { F } = F \left\{ k _ { 1 } ( 1 - \theta ) + k _ { 2 } \theta ( 1 - \theta ) + k _ { 3 } \theta \right\}\] C) \[i _ { F } = F \left\{ k _ { 1 } ( 1 - \theta ) - k _ { 2 } \theta ( 1 - \theta ) - k _ { 3 } \theta \right\}\] D) \[i _ { F } = F \left\{ k _ { 1 } ( 1 - \theta ) - k _ { 3 } \theta \right\}\] A) \[i _ { F } = F \left\{ k _ { 1 } ( 1 - \theta ) + k _ { 2 } \theta ( 1 - \theta ) \right\}\] B) \[i _ { F } = F \left\{ k _ { 1 } ( 1 - \theta ) + k _ { 2 } \theta ( 1 - \theta ) + k _ { 3 } \theta \right\}\] C) \[i _ { F } = F \left\{ k _ { 1 } ( 1 - \theta ) - k _ { 2 } \theta ( 1 - \theta ) - k _ { 3 } \theta \right\}\] D) \[i _ { F } = F \left\{ k _ { 1 } ( 1 - \theta ) - k _ { 3 } \theta \right\}\]

Exam 5: Mechanistic Analysis

Consider the reaction M + . Frumkin isotherm is used to describe the adsorption. The kinetic parameter values are k₁₀ = 10^-9mol cm^-2 s^-1, b₁ = 10 V^-1, g = 15, $\beta$ ₁ = -0.5 , k₂₀ = 10^-8 mol cm^-2 s^-1, $\beta$ ₂ = +0.5 and $\varGamma$ = 10^-8 mol cm^-2. -The maximum number of 'loops' that can appear in complex plane plots is _____________

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Question 29

Consider the reaction + + -In the same reaction, the equation for fractional surface coverage of A_ads is given by

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Question 30

The following impedance spectrum was obtained for an electrochemical system. Which of the following mechanisms can be considered to describe the electrochemical system?

Consider the reaction M + M+ ++ -The mass balance equation for fractional surface coverage of $M _ { a d s} ^ { + }$ is given by

Consider the reaction M + M+ ++ -In the same reaction, the equation for fractional surface coverage of A_ads is given by

Consider the reaction given by M + + . -In the same mechanism, the faradaic impedance (Z_F) is given by $i _ { F } = F \left[ k _ { 1 } ( 1 - \theta ) + k _ { 2 } \theta - k _ { - 2 } ( 1 - \theta ) C _ { M _ { \mathbf { sol } } ^ { +2 } } \right]$

A Frumkin isotherm model will reduce to Langmuir isotherm when parameter "g" is _____

In a kinetic limited electrochemical reaction, the number of loops appearing in the complex plane plot of EIS can be related to the

Consider the reaction + + -In the same reaction, the expression for $\frac { d \theta } { d E }$ is given by

Consider the reaction + + -For the above mechanism, the number of electrical elements (including polarization resistance) required to model the Faradaic impedance is _____

The polarization plot of an electrochemical system is given below. -In the same system, if an impedance spectrum is acquired at E_dc = 1.2 V vs. OCP, then the polarization resistance is expected to be.

Consider the reaction + + -In the same reaction, the equation for fractional surface coverage of A_ads is given by

The following impedance spectrum was obtained for an electrochemical system. Which of the following mechanisms can be considered to describe the electrochemical system?

Temkin model describes the relationship between _______ and fractional surface coverage

Consider a reaction given by M + . -In the same mechanism, the value of $\frac { d \theta } { d E }$ is given by

Choose the mechanism(s), which, for appropriate values of kinetic parameters and dc potentials, can yield negative differential impedance.

Consider the reaction M + M+ ++ -In the same reaction, the expression for $\frac { d \theta } { d E }$ is given by

Consider the reaction M + M+ ++ -In the same reaction, the faradaic current is given by

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Exam 5: Mechanistic Analysis

Consider the reaction M + M+ ++ -The mass balance equation for fractional surface coverage of Mads+M _ { a d s} ^ { + }Mads+​ is given by

Consider the reaction M + M+ ++ -In the same reaction, the equation for fractional surface coverage of Aads is given by

A Frumkin isotherm model will reduce to Langmuir isotherm when parameter "g" is _____

In a kinetic limited electrochemical reaction, the number of loops appearing in the complex plane plot of EIS can be related to the

Consider the reaction + + -In the same reaction, the expression for dθdE\frac { d \theta } { d E }dEdθ​ is given by

Consider the reaction + + -For the above mechanism, the number of electrical elements (including polarization resistance) required to model the Faradaic impedance is _____

The polarization plot of an electrochemical system is given below. -In the same system, if an impedance spectrum is acquired at Edc = 1.2 V vs. OCP, then the polarization resistance is expected to be.

Consider the reaction + + -In the same reaction, the equation for fractional surface coverage of Aads is given by

The following impedance spectrum was obtained for an electrochemical system. Which of the following mechanisms can be considered to describe the electrochemical system?

Temkin model describes the relationship between _______ and fractional surface coverage

Consider a reaction given by M + . -In the same mechanism, the value of dθdE\frac { d \theta } { d E }dEdθ​ is given by

Choose the mechanism(s), which, for appropriate values of kinetic parameters and dc potentials, can yield negative differential impedance.

Consider the reaction M + M+ ++ -In the same reaction, the expression for dθdE\frac { d \theta } { d E }dEdθ​ is given by

Consider the reaction M + M+ ++ -In the same reaction, the faradaic current is given by

Introduction

Experimental Aspects

Data Validation

Data Analysis Equivalent Electrical Circuits

Eis Other Physical Phenomena

Nonlinear Eis

Filters

Consider the reaction M + M+ ++ -The mass balance equation for fractional surface coverage of $M _ { a d s} ^ { + }$ is given by

Consider the reaction M + M+ ++ -In the same reaction, the equation for fractional surface coverage of A_ads is given by

Consider the reaction + + -In the same reaction, the expression for $\frac { d \theta } { d E }$ is given by

The polarization plot of an electrochemical system is given below. -In the same system, if an impedance spectrum is acquired at E_dc = 1.2 V vs. OCP, then the polarization resistance is expected to be.

Consider the reaction + + -In the same reaction, the equation for fractional surface coverage of A_ads is given by

Consider a reaction given by M + . -In the same mechanism, the value of $\frac { d \theta } { d E }$ is given by

Consider the reaction M + M+ ++ -In the same reaction, the expression for $\frac { d \theta } { d E }$ is given by