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Consider the Reaction -In the Same Reaction, the Expression For dθdE\frac { d \theta } { d E }

Question 27

Multiple Choice

Consider the reaction Psol⇄k1k−1Q−sol+e−Asol−⇄k2k−2Aads+e−\begin{array} { l } P _ { s o l }\underset { k _ { - 1 } } { \stackrel { k _ { 1 } } { \rightleftarrows } }Q _ { - s o l } + e ^ { - } \\A _ { s ol } ^ { - } \underset { k _ { - 2 } } { \stackrel { k _ { 2 } } { \rightleftarrows } } A _ { a d s } + e ^ { - } \\\end{array}

-In the same reaction, the expression for dθdE\frac { d \theta } { d E }
is given by


A) dθdE=b2k2dc[Asol−]−b−2k−2dck2dc[Asol−]+k−2dc+jωΓ\frac { d \theta } { d E } = \frac { b _ { 2 } k _ { 2dc } \left[ A _ { so l } ^ { - } \right] - b _ { - 2 } k _ { - 2 dc} } { k _ { 2 dc } \left[ A _ { s ol } ^ { - } \right] + k _ { - 2 { dc} } + j \omega \Gamma }
B) dθdE=b2k2dc[Asol−](1−θss) −b−2k−2dcθssk2dc[Asol−](1−θss) +k−2dcθss+jωΓ\frac { d \theta } { d E } = \frac { b _ { 2 } k _ { 2 dc } \left[ A _ { s ol } ^ { - } \right] \left( 1 - \theta _ { ss } \right) - b _ { - 2 } k _ { - 2 dc } \theta _ { s s } } { k _ { 2 d c} \left[ A _ { so l } ^ { - } \right] \left( 1 - \theta _ { s s } \right) + k _ { - 2 dc } \theta _ { ss } + j \omega \Gamma }
C) dθdE=b2k2dc[Asol−](1−θss) −b−2k−2dcθssk2dc[Asol−]+k−2dc+jωΓ\frac { d \theta } { d E } = \frac { b _ { 2 } k _ { 2dc } \left[ A _ { s o l } ^ { - } \right] \left( 1 - \theta _ { s s } \right) - b _ { - 2 } k _ { - 2 dc } \theta _ { s s } } { k _ { 2 dc } \left[ A _ { s o l } ^ { - } \right] + k _ { - 2 dc } + j \omega \Gamma }
D) dθdE=b2k2dc[Asol−]−b−2k−2dck2d˙[Asol−](1−θss) +k−2dcθss+jωΓ\frac { d \theta } { d E } = \frac { b _ { 2 } k _ { 2 dc } \left[ A _ { s o l } ^ { - } \right] - b _ { - 2 } k _ { - 2 d c } } { k _ { 2 d \dot { } } \left[ A _ { s o l } ^ { - } \right] \left( 1 - \theta _ { s s } \right) + k _ { - 2 d c } \theta _ { s s} + j \omega \Gamma }

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