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Consider the Reaction -In the Same Reaction, the Faradaic Current Is Given by k

Question 39

Multiple Choice

Consider the reaction M⟶k1Mads++e−M+Mads+⟶k2Mads++Msol++e−Mads+⟶ksMsol+\begin{array} { l } M \stackrel { k _ { 1 } } { \longrightarrow } M _ { a ds } ^ { + } + e ^ { - } \\M + M _ { a d s } ^ { + } \stackrel { k _ { 2 } } { \longrightarrow } M _ { a d s } ^ { + } + M _ { s o l } ^ { + } + e ^ { - } \\M _ { a d s } ^ { + } \stackrel { k _ { s } } { \longrightarrow } M _ { s o l } ^ { + }\end{array}
-In the same reaction, the faradaic current is given by


A) iF=F{k1(1−θ) +k2θ(1−θ) }i _ { F } = F \left\{ k _ { 1 } ( 1 - \theta ) + k _ { 2 } \theta ( 1 - \theta ) \right\}
B) iF=F{k1(1−θ) +k2θ(1−θ) +k3θ}i _ { F } = F \left\{ k _ { 1 } ( 1 - \theta ) + k _ { 2 } \theta ( 1 - \theta ) + k _ { 3 } \theta \right\}
C) iF=F{k1(1−θ) −k2θ(1−θ) −k3θ}i _ { F } = F \left\{ k _ { 1 } ( 1 - \theta ) - k _ { 2 } \theta ( 1 - \theta ) - k _ { 3 } \theta \right\}
D) iF=F{k1(1−θ) −k3θ}i _ { F } = F \left\{ k _ { 1 } ( 1 - \theta ) - k _ { 3 } \theta \right\}

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