Consider the Reaction -In the Same Reaction, the Expression For $$\frac { d \theta } { d E }$$

Consider the reaction $$\begin{array} { l } M \stackrel { k _ { 1 } } { \longrightarrow } M _ { a ds } ^ { + } + e ^ { - } \\M + M _ { a d s } ^ { + } \stackrel { k _ { 2 } } { \longrightarrow } M _ { a d s } ^ { + } + M _ { s o l } ^ { + } + e ^ { - } \\M _ { a d s } ^ { + } \stackrel { k _ { s } } { \longrightarrow } M _ { s o l } ^ { + }\end{array}$$
-In the same reaction, the expression for $$\frac { d \theta } { d E }$$
is given by

A) $$\frac { d \theta } { d E } = \frac { b _ { 1 } k _ { 1 d c } \left( 1 - \theta _ { s s } \right) - b _ { 2 } k _ { 2 { dc } } \theta _ { ss } \left( 1 - \theta _ { s s } \right) } { k _ { 1 { dc } } + k _ { 2 d c} + j \omega \Gamma }$$
B) $$\frac { d \theta } { d E } = \frac { b _ { 1 } k _ { 1 dc } \left( 1 - \theta _ { s s } \right) - b _ { 2 } k _ { 2 { dc } } \theta _ { ss } \left( 1 - \theta _ { s s } \right) } { k _ { 1 dc } + k _ { 2 d c} + k _ { 3 } + j \omega \Gamma }$$
C) $$\frac { d \theta } { d E } = \frac { b _ { 1 } k _ { 1 dc } \left( 1 - \theta _ { ss} \right) } { k _ { 1dc } + k _ { 3 } + j \omega \Gamma }$$
D) $$\frac { d \theta } { d E } = \frac { b _ { 1 } k _ { 1 dc } \left( 1 - \theta _ { s s } \right) - b _ { 2 } k _ { 2 dc } \theta _ { s s } } { k _ { 1 dc } + k _ { 2 dc } + k _ { 3 } + j \omega \Gamma }$$

Correct Answer:

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Access For Free