Exam 4: Inverse, Exponential, and Logarithmic Functions

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Solve the problem. -If f(x)=25xf ( x ) = 25 ^ { x } , find f[log⁡25(ln⁡25)]f [ \log 25 ( \ln 25 ) ] .

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Use the properties of logarithms to rewrite the expression. Simplify the result if possible. Assume all variables represent positive real numbers. - log⁡3(x4y56)\log _ { 3 } \left( \frac { x ^ { 4 } y ^ { 5 } } { 6 } \right)

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Find the value. Give an approximation to four decimal places. -ln 0.000772

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Write an equivalent expression in exponential form. - log⁡3(19)=−2\log _ { 3 } \left( \frac { 1 } { 9 } \right) = - 2

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Given log⁡102=0.3010 and log⁡103=0.4771, \log _ { 10 } 2 = 0.3010 \text { and } \log _ { 10 } 3 = 0.4771 \text {, } find the logarithm without using a calculator. - log⁡1098\log _ { 10 } \frac { 9 } { 8 }

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Solve the equation and express the solution in exact form. - log⁡4(x+4)+log⁡4(x−4)=3\log _ { 4 } ( x + 4 ) + \log _ { 4 } ( x - 4 ) = 3

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Graph the exponential function using transformations where appropriate. - f(x)=4x−5f(x)=4^{x-5}  Graph the exponential function using transformations where appropriate. - f(x)=4^{x-5}

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Provide an appropriate response. -Use the properties of exponents to write the function of the form f(t)=katf ( t ) = k a t , where kk is a constant. f(t)=33t+2f ( t ) = 3 ^ { 3 t } + 2

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Solve the problem. Round your answer to the nearest tenth, when appropriate. Use the formula pH=−log⁡[H3O+]\mathrm { pH } = - \log \left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right] as needed. -Find the pH\mathrm { pH } if [H3O+]=5.9×10−4\left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right] = 5.9 \times 10 ^ { - 4 } .

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Write the word or phrase that best completes each statement or answers the question. -  With the function f(x)=log⁡ax, why can’t x be less than 0 ? \text { With the function } \mathrm { f } ( \mathrm { x } ) = \log _ { \mathrm { a } } x \text {, why can't } x \text { be less than } 0 \text { ? }

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Write the word or phrase that best completes each statement or answers the question. -How long will it take a sample of radioactive substance to decay to half of its original amount, if it decays according to the function A(t)=450e−.168t\mathrm { A } ( \mathrm { t } ) = 450 \mathrm { e } ^ { - .168 \mathrm { t } } , where t\mathrm { t } is the time in years? Round your answer to the nearest hundredth year.

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Provide an appropriate response. -  Explain how the graph of y=3x−3+1 can be obtained from the graph of y=3x\text { Explain how the graph of } y = 3 ^ { x } - 3 + 1 \text { can be obtained from the graph of } y = 3 ^ { x }

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Solve the equation. - ex−1=(1e2)x+5e ^ { x - 1 } = \left( \frac { 1 } { e ^ { 2 } } \right) ^ { x + 5 }

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If the function is one-to-one, find its inverse. If not, write ʺnot one-to-one.ʺ - f(x)=7x3+6f ( x ) = 7 x ^ { 3 } + 6

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Solve the following graphically. If necessary, round answers to the nearest thousandth. - ex+ln⁡3=4ex\mathrm { e } ^ { \mathrm { x } } + \ln 3 = 4 \mathrm { e } ^ { \mathrm { x } }

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For the function as defined that is one-to-one, graph f and f-1 on the same axes. - f(x)=x3+4f(x)=x^{3}+4  For the function as defined that is one-to-one, graph f and f-1 on the same axes. - f(x)=x^{3}+4    A)   B)   C)   D)    A)  For the function as defined that is one-to-one, graph f and f-1 on the same axes. - f(x)=x^{3}+4    A)   B)   C)   D)    B)  For the function as defined that is one-to-one, graph f and f-1 on the same axes. - f(x)=x^{3}+4    A)   B)   C)   D)    C)  For the function as defined that is one-to-one, graph f and f-1 on the same axes. - f(x)=x^{3}+4    A)   B)   C)   D)    D)  For the function as defined that is one-to-one, graph f and f-1 on the same axes. - f(x)=x^{3}+4    A)   B)   C)   D)

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Graph the function. - f(x)=(12)xf(x)=\left(\frac{1}{2}\right)^{x}  Graph the function. - f(x)=\left(\frac{1}{2}\right)^{x}

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Provide an appropriate response. -  Why can’t y=2x have an x-intercept? \text { Why can't } \mathrm { y } = 2 ^ { \mathrm { x } } \text { have an } \mathrm { x } \text {-intercept? }

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For the function as defined that is one-to-one, graph f and f-1 on the same axes. - f(x)=43x+4f ( x ) = \frac { 4 } { 3 } x + 4  For the function as defined that is one-to-one, graph f and f-1 on the same axes. - f ( x ) = \frac { 4 } { 3 } x + 4

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Find the domain and range of the inverse of the given function. - f(x)=7−x2;x≥0f ( x ) = 7 - x ^ { 2 } ; x \geq 0

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