Exam 10: Monoprotic Acid-Base Equilibria
Exam 1: The Analytical Process20 Questions
Exam 2: Chemical Measurements21 Questions
Exam 3: Tools of the Trade19 Questions
Exam 4: Experimental Error20 Questions
Exam 5: Statistics22 Questions
Exam 6: Quality Assurance and Calibration Methods20 Questions
Exam 7: Chemical Equilibrium20 Questions
Exam 8: Let the Titrations Begin20 Questions
Exam 9: Activity and the Systematic Treatment of Equilibrium20 Questions
Exam 10: Monoprotic Acid-Base Equilibria20 Questions
Exam 11: Polyprotic Acid-Base Equilibria20 Questions
Exam 12: Acid-Base Titrations20 Questions
Exam 13: Edta Titrations20 Questions
Exam 14: Advanced Topics in Equilibrium20 Questions
Exam 15: Fundamentals of Electrochemistry20 Questions
Exam 16: Electrodes and Potentiometry20 Questions
Exam 17: Redox Titrations20 Questions
Exam 18: Electroanalytical Techniques20 Questions
Exam 19: Fundamentals of Spectrophotometry23 Questions
Exam 20: Applications of Spectrophotometry20 Questions
Exam 21: Spectrophotometers20 Questions
Exam 22: Atomic Spectroscopy20 Questions
Exam 23: Mass Spectrometry20 Questions
Exam 24: Introduction to Analytical Separations20 Questions
Exam 25: Gas Chromatography20 Questions
Exam 26: High-Performance Liquid Chromatography20 Questions
Exam 27: Chromatographic Methods and Capillary Electrophoresis20 Questions
Exam 28: Gravimetric and Combustion Analysis20 Questions
Exam 29: Sample Preparation19 Questions
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Which of the following statements is NOT true for weak acids?
Free
(Multiple Choice)
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Correct Answer:
D
The pH of a weak-base solution is calculated using systematic treatment.Which of the following is NOT an equation needed to solve for pOH?
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(Multiple Choice)
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Correct Answer:
A
One liter of a pH 5.00 propionic acid buffer with a total concentration of 50 mM must be prepared.Calculate the mmols propionic acid and sodium propionate needed to prepare the buffer.Ka = 1.34 x 10-5 for propionic acid.
(Essay)
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The pH of a weak-acid solution is calculated using systematic treatment.Which of the following is NOT an equation needed to solve for pH?
(Multiple Choice)
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A student calculates the pOH for a 0.01 M triethanolamine solution to be 4.12.To simplify the math she decided to neglect the change in the formal concentration.Was she justified in her decision? Kb = 5.78 × 10−7
(Multiple Choice)
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Calculate the percent dissociation for a 0.01 M HCN solution,neglecting activity coefficients.Ka = 6.2 × 10−10 for HCN.
(Essay)
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Which of the following statements is NOT true for weak bases?
(Multiple Choice)
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There are seven common strong acids.Which of the following statements is NOT true for strong acids?
(Multiple Choice)
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Calculate the pH for a 4.3 × 10−8 M HCl solution with an ionic strength of = 0.1.H+ = 0.83,OH− = 0.76 and Cl− = 0.755.
(Essay)
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The buffer needed for a capillary electrophoresis experiment must have a pH of 10.0.Which weak acid is the best choice for the buffer? Assume = 0.
(Multiple Choice)
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The rule of thumb for neglecting the change in the formal concentration of a weak acid or a weak base,x,during an equilibrium problem is valid:
(Multiple Choice)
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A buffer is prepared by mixing 200.0 mL of 0.1500 M NaOH with 200.0 mL of 0.200 M CH3CO2H in a 1-L volumetric flask and then diluted to volume with distilled deionized water.Calculate the pH of the buffer.Ka = 1.75 × 10−5
(Multiple Choice)
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There are two types of metal hydroxides,soluble metal hydroxides and insoluble hydroxides,both of which are strong bases.Which of the following statements is NOT true for strong bases?
(Multiple Choice)
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A 0.01 M solution of a weak base has a percent association of 18.32%.Calculate the Kb for the weak base.
(Multiple Choice)
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Calculate the percentage dissociation for a 0.010 M hypochlorous acid solution.The Ka for hypochlorous acid is 3.0 x 10−8.
(Multiple Choice)
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For a 0.0005 M HBr solution,the dissociation of water produces____________________ H3O+ and____________________ OH−.
(Multiple Choice)
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Which of the following is NOT true for weak acids and weak bases?
(Multiple Choice)
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Calculate the pH of 0.01 M HCN ( = 0.10)using activity coefficients,neglecting activity coefficients,and the percent difference between the two.Ka = 6.2 x 10−10 for HCN.H+ = 0.83,OH− = 0.76 and CN− = 0.755.
(Essay)
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