Exam 6: Work and Kinetic Energy

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Force and potential energy: A potential energy function is given by U(x) = (3.00 N/m)x - (1.00 N/m3)x3. At what position or positions is the force equal to zero?

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Work: In the figure, a constant external force P = 160 N is applied to a 20.0-kg box, which is on a rough horizontal surface. While the force pushes the box a distance of 8.00 m, the speed changes from 0.500 m/s to 2.60 m/s. The work done by friction during this process is closest to Work: In the figure, a constant external force P = 160 N is applied to a 20.0-kg box, which is on a rough horizontal surface. While the force pushes the box a distance of 8.00 m, the speed changes from 0.500 m/s to 2.60 m/s. The work done by friction during this process is closest to

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Force and potential energy: A potential energy function is given by U(x) = (3.00 J/m)x + (1.00 J/m3)x3. What is the force function F(x) that is associated with this potential energy function?

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Hooke's law: Which of the graphs in the figure represents a spring that gets less stiff the more it is stretched? Hooke's law: Which of the graphs in the figure represents a spring that gets less stiff the more it is stretched?

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Kinetic energy: The coefficient of the restitution of an object is defined as the ratio of its outgoing to incoming speed when the object collides with a rigid surface. For an object with a coefficient of 0.78, what fraction of the object's kinetic energy is lost during a single collision?

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Work-energy theorem: Two objects, one of mass m and the other of mass 2m, are dropped from the top of a building. When they hit the ground

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Force and potential energy: The only force acting on an object moving along the x-axis is the conservative force given by F(x) = (2.00 N/m)x + (1.00 N/m3)x3. (a) What is the change in potential energy when the object moves from x = 1.00 m to x = 2.00 m? (b) What is the change in kinetic energy when the object moves from x = 1.00 m to x = 2.00 m?

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Energy conservation with conservative forces: In the figure, a stunt car driver negotiates the frictionless track shown in such a way that the car is barely in contact with the track at the top of the loop. The radius of the track is 9.9 m and the mass of the car is 1800 kg. Find the magnitude of the force of the car on the track when the car is at point A. You can treat the car as a point mass. Energy conservation with conservative forces: In the figure, a stunt car driver negotiates the frictionless track shown in such a way that the car is barely in contact with the track at the top of the loop. The radius of the track is 9.9 m and the mass of the car is 1800 kg. Find the magnitude of the force of the car on the track when the car is at point A. You can treat the car as a point mass.

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Force and potential energy: A force on an object is given by F(x) = (-4.00 N/m)x + ( 2.00 N/m3)x3. What is the change in potential energy in moving from x = 1.00 m to x = 2.00 m?

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