Question 1

The area under a graph of ax vs. t from t = ti to t = tf represents

Accepted Answer

A)  xf − xi. 
B)  vf − vi. 
C)  xavg. 
D)  vavg. 
E)  aavg. 
A)  xf − xi. 
B)  vf − vi. 
C)  xavg. 
D)  vavg. 
E)  aavg.

Question 2

An object is thrown vertically and has an upward velocity of 18 m/s when it reaches one fourth of its maximum height above its launch point. What is the initial (launch) speed of the object?

Accepted Answer

A)  35 m/s 
B)  25 m/s 
C)  30 m/s 
D)  21 m/s 
E)  17 m/s 
A)  35 m/s 
B)  25 m/s 
C)  30 m/s 
D)  21 m/s 
E)  17 m/s

Question 3

A juggler throws two balls to the same height so that one is at the halfway point going up when the other is at the halfway point coming down. At that point:

Accepted Answer

A)  Their velocities and accelerations are equal. 
B)  Their velocities are equal but their accelerations are equal and opposite. 
C)  Their accelerations are equal but their velocities are equal and opposite. 
D)  Their velocities and accelerations are both equal and opposite. 
E)  Their velocities are equal to their accelerations. 
A)  Their velocities and accelerations are equal. 
B)  Their velocities are equal but their accelerations are equal and opposite. 
C)  Their accelerations are equal but their velocities are equal and opposite. 
D)  Their velocities and accelerations are both equal and opposite. 
E)  Their velocities are equal to their accelerations.

Question 4

A rock is thrown downward from an unknown height above the ground with an initial speed of 10 m/s. It strikes the ground 3.0 s later. Determine the initial height of the rock above the ground.

Accepted Answer

A)  44 m 
B)  14 m 
C)  74 m 
D)  30 m 
E)  60 m 
A)  44 m 
B)  14 m 
C)  74 m 
D)  30 m 
E)  60 m

Question 5

To help Kim practice for the Special Olympics, Sally runs beside him for half the required distance. She runs the remaining distance at her regular speed and arrives 90 seconds ahead of Kim. What is the ratio of Sally's regular speed to Kim's speed? Use tKim for Kim's total time.

Accepted Answer

A) 
  
B) 
  
C) 
  
D) 
  
E) 
  
A) 
  
B) 
  
C) 
  
D) 
  
E)

Question 6

An object is thrown vertically upward such that it has a speed of 25 m/s when it reaches two thirds of its maximum height above the launch point. Determine this maximum height.

Accepted Answer

A)  64 m 
B)  48 m 
C)  32 m 
D)  96 m 
E)  75 m 
A)  64 m 
B)  48 m 
C)  32 m 
D)  96 m 
E)  75 m

Question 7

A particle moving with a constant acceleration has a velocity of 20 cm/s when its position is x = 10 cm. Its position 7.0 s later is x = −30 cm. What is the acceleration of the particle?

Accepted Answer

A)  −7.3 cm/s2 
B)  −8.9 cm/s2 
C)  −11 cm/s2 
D)  −15 cm/s2 
E)  −13 cm/s2 
A)  −7.3 cm/s2 
B)  −8.9 cm/s2 
C)  −11 cm/s2 
D)  −15 cm/s2 
E)  −13 cm/s2

Question 8

A particle confined to motion along the x axis moves with constant acceleration from x = 2.0 m to x = 8.0 m during a 2.5-s time interval. The velocity of the particle at x = 8.0 m is 2.8 m/s. What is the acceleration during this time interval?

Accepted Answer

A)  0.48 m/s2 
B)  0.32 m/s2 
C)  0.64 m/s2 
D)  0.80 m/s2 
E)  0.57 m/s2 
A)  0.48 m/s2 
B)  0.32 m/s2 
C)  0.64 m/s2 
D)  0.80 m/s2 
E)  0.57 m/s2

Question 9

A ball thrown vertically from ground level is caught 3.0 s later when it is at its highest point by a person on a balcony which is 14 m above the ground. Determine the initial speed of the ball.

Accepted Answer

A)  19 m/s 
B)  4.7 m/s 
C)  10 m/s 
D)  34 m/s 
E)  17 m/s 
A)  19 m/s 
B)  4.7 m/s 
C)  10 m/s 
D)  34 m/s 
E)  17 m/s

Question 10

The speed of an object is given by   where v is in m/s and t is in s.What is the acceleration of the object at t = 2.00 s?

Accepted Answer

A)  5.00 m/s2 
B)  9.00 m/s2 
C)  10.0 m/s2 
D)  14.0 m/s2 
E)  20.0 m/s2 
A)  5.00 m/s2 
B)  9.00 m/s2 
C)  10.0 m/s2 
D)  14.0 m/s2 
E)  20.0 m/s2

Question 11

Dallas says that any change in velocity is directly proportional to the time interval over which the change took place. Dana says that is true only when the acceleration is constant. Which one, if either, is correct?

Accepted Answer

A)  Dana, because it is true only when the acceleration is constant. 
B)  Dallas, because we can define ax, avg so that Δvx = ax, avgΔt. 
C)  Dallas, because ax, avg always is equal to
  . 
D)  All the above are correct. 
E)  Only (a) and (b) above are correct. 
A)  Dana, because it is true only when the acceleration is constant. 
B)  Dallas, because we can define ax, avg so that Δvx = ax, avgΔt. 
C)  Dallas, because ax, avg always is equal to
  . 
D)  All the above are correct. 
E)  Only (a) and (b) above are correct.

Question 12

The area under a graph of vx vs. t from t = ti to t = tf represents

Accepted Answer

A)  xi. 
B)  xf. 
C)  xf − xi. 
D) 
  (xi + xf). 
E)  xi + xf. 
A)  xi. 
B)  xf. 
C)  xf − xi. 
D) 
  (xi + xf). 
E)  xi + xf.

Question 13

A particle is moving with a constant acceleration of 4.0 m/s2. Its speed at t = 1.0 s is 4.0 m/s and at t = 3.0 s it is 12.0 m/s. What is the area under the position-time graph for the interval from t = 1.0 s to t = 3.0 s?

Accepted Answer

A)  8.0 m/s 
B)  8.0 m 
C)  12 m 
D)  16 m 
E)  16 m/s2 
A)  8.0 m/s 
B)  8.0 m 
C)  12 m 
D)  16 m 
E)  16 m/s2

Question 14

The position of a particle moving along the x axis is given by x = 6.0t2 − 1.0t3, where x is in meters and t in seconds. What is the position of the particle when it achieves its maximum speed in the positive x direction?

Accepted Answer

A)  24 m 
B)  12 m 
C)  32 m 
D)  16 m 
E)  2.0 m 
A)  24 m 
B)  12 m 
C)  32 m 
D)  16 m 
E)  2.0 m

Question 15

A car originally traveling at 30 m/s manages to brake for 5.0 seconds while traveling 125 m downhill. At that point the brakes fail. After an additional 5.0 seconds it travels an additional 150 m down the hill. What was the acceleration of the car after the brakes failed?

Accepted Answer

The answer of A car originally traveling at 30 m/s...

Question 16

The position of a particle as it moves along the x axis is given for t > 0 by x = (t3 − 3t2 + 6t) m, where t is in s. Where is the particle when it achieves its minimum speed (after t = 0)?

Accepted Answer

A)  3 m 
B)  4 m 
C)  8 m 
D)  2 m 
E)  7 m 
A)  3 m 
B)  4 m 
C)  8 m 
D)  2 m 
E)  7 m

Question 17

At t = 0, a particle is located at x = 25 m and has a velocity of 15 m/s in the positive x direction. The acceleration of the particle varies with time as shown in the diagram. What is the velocity of the particle at t = 5.0 s?

Accepted Answer

A)  +15 m/s 
B)  −15 m/s 
C)  +30 m/s 
D)  0 
E)  −1.2 m/s 
A)  +15 m/s 
B)  −15 m/s 
C)  +30 m/s 
D)  0 
E)  −1.2 m/s

Question 18

A particle is moving at constant velocity. Its position at t = 1.0 s is 3.0 m and its position at t = 4.0 s is 15.0 m. What is the slope of the position-time graph for this particle?

Accepted Answer

A)  0, since this is a constant velocity situation. 
B)  4.0 m/s 
C)  4.0 m/s2 
D)  9.0 m/s 
E)  12 m/s2 
A)  0, since this is a constant velocity situation. 
B)  4.0 m/s 
C)  4.0 m/s2 
D)  9.0 m/s 
E)  12 m/s2

Question 19

Two children start at one end of a street, the origin, run to the other end, then head back. On the way back Joan is ahead of Mike. Which statement is correct about the distances run and the displacements from the origin?

Accepted Answer

A)  Joan has run a greater distance and her displacement is greater than Mike's. 
B)  Mike has run a greater distance and his displacement is greater than Joan's. 
C)  Joan has run a greater distance, but her displacement is less than Mike's. 
D)  Mike has run a greater distance, but his displacement is less than Joan's. 
E)  Mike has run a shorter distance, and his displacement is less than Joan's. 
A)  Joan has run a greater distance and her displacement is greater than Mike's. 
B)  Mike has run a greater distance and his displacement is greater than Joan's. 
C)  Joan has run a greater distance, but her displacement is less than Mike's. 
D)  Mike has run a greater distance, but his displacement is less than Joan's. 
E)  Mike has run a shorter distance, and his displacement is less than Joan's.

Question 20

When starting from rest at the bottom of a straight road with constant upward slope, Joan bicycles to the top 50.0 s ahead of Sally, whose travel time is 5.00 minutes. What is the ratio of Joan's acceleration to Sally's acceleration?

Accepted Answer

A)  0.694 
B)  0.833 
C)  1.20 
D)  1.44 
E)  6.00 
A)  0.694 
B)  0.833 
C)  1.20 
D)  1.44 
E)  6.00

Exam 2: Motion in One Dimension

The area under a graph of ax vs. t from t = ti to t = tf represents

An object is thrown vertically and has an upward velocity of 18 m/s when it reaches one fourth of its maximum height above its launch point. What is the initial (launch) speed of the object?

A juggler throws two balls to the same height so that one is at the halfway point going up when the other is at the halfway point coming down. At that point:

A rock is thrown downward from an unknown height above the ground with an initial speed of 10 m/s. It strikes the ground 3.0 s later. Determine the initial height of the rock above the ground.

To help Kim practice for the Special Olympics, Sally runs beside him for half the required distance. She runs the remaining distance at her regular speed and arrives 90 seconds ahead of Kim. What is the ratio of Sally's regular speed to Kim's speed? Use tKim for Kim's total time.

An object is thrown vertically upward such that it has a speed of 25 m/s when it reaches two thirds of its maximum height above the launch point. Determine this maximum height.

A particle moving with a constant acceleration has a velocity of 20 cm/s when its position is x = 10 cm. Its position 7.0 s later is x = −30 cm. What is the acceleration of the particle?

A particle confined to motion along the x axis moves with constant acceleration from x = 2.0 m to x = 8.0 m during a 2.5-s time interval. The velocity of the particle at x = 8.0 m is 2.8 m/s. What is the acceleration during this time interval?

A ball thrown vertically from ground level is caught 3.0 s later when it is at its highest point by a person on a balcony which is 14 m above the ground. Determine the initial speed of the ball.

The speed of an object is given by where v is in m/s and t is in s.What is the acceleration of the object at t = 2.00 s?

Dallas says that any change in velocity is directly proportional to the time interval over which the change took place. Dana says that is true only when the acceleration is constant. Which one, if either, is correct?

The area under a graph of vx vs. t from t = ti to t = tf represents

A particle is moving with a constant acceleration of 4.0 m/s2. Its speed at t = 1.0 s is 4.0 m/s and at t = 3.0 s it is 12.0 m/s. What is the area under the position-time graph for the interval from t = 1.0 s to t = 3.0 s?

The position of a particle moving along the x axis is given by x = 6.0t2 − 1.0t3, where x is in meters and t in seconds. What is the position of the particle when it achieves its maximum speed in the positive x direction?

A car originally traveling at 30 m/s manages to brake for 5.0 seconds while traveling 125 m downhill. At that point the brakes fail. After an additional 5.0 seconds it travels an additional 150 m down the hill. What was the acceleration of the car after the brakes failed?

The position of a particle as it moves along the x axis is given for t > 0 by x = (t3 − 3t2 + 6t) m, where t is in s. Where is the particle when it achieves its minimum speed (after t = 0)?

At t = 0, a particle is located at x = 25 m and has a velocity of 15 m/s in the positive x direction. The acceleration of the particle varies with time as shown in the diagram. What is the velocity of the particle at t = 5.0 s?

A particle is moving at constant velocity. Its position at t = 1.0 s is 3.0 m and its position at t = 4.0 s is 15.0 m. What is the slope of the position-time graph for this particle?

Two children start at one end of a street, the origin, run to the other end, then head back. On the way back Joan is ahead of Mike. Which statement is correct about the distances run and the displacements from the origin?

When starting from rest at the bottom of a straight road with constant upward slope, Joan bicycles to the top 50.0 s ahead of Sally, whose travel time is 5.00 minutes. What is the ratio of Joan's acceleration to Sally's acceleration?

Physics and Measurement

Vectors

Motion in Two Dimensions

The Laws of Motion

Circular Motion and Other Applications of Newtons Laws

Energy of a System

Conservation of Energy

Linear Momentum and Collisions

Rotation of a Rigid Object About a Fixed Axis

Angular Momentum

Static Equilibrium and Elasticity

Universal Gravitation

Fluid Mechanics

Oscillatory Motion

Wave Motion

Superposition and Standing Waves

Temperature

The First Law of Thermodynamics

The Kinetic Theory of Gases

Heat Engines, Entropy, and the Second Law of Thermodynamics

Electric Fields

Gausss Law

Electric Potential

Capacitance and Dielectrics

Current and Resistance

Direct-Current Circuits

Magnetic Fields

Sources of the Magnetic Field

Faradays Law

Inductance

Alternating-Current Circuits

Electromagnetic Waves

The Nature of Light and the Principles of Ray Optics

Image Formation

Wave Optics

Diffraction Patterns and Polarization

Relativity

Introduction to Quantum Physics

Quantum Mechanics

Atomic Physics

Molecules and Solids

Nuclear Structure

Particle Physics and Cosmology

Filters

The area under a graph of a_x vs. t from t = t_i to t = t_f represents

To help Kim practice for the Special Olympics, Sally runs beside him for half the required distance. She runs the remaining distance at her regular speed and arrives 90 seconds ahead of Kim. What is the ratio of Sally's regular speed to Kim's speed? Use t_Kim for Kim's total time.

The area under a graph of v_x vs. t from t = t_i to t = t_f represents

A particle is moving with a constant acceleration of 4.0 m/s². Its speed at t = 1.0 s is 4.0 m/s and at t = 3.0 s it is 12.0 m/s. What is the area under the position-time graph for the interval from t = 1.0 s to t = 3.0 s?

The position of a particle moving along the x axis is given by x = 6.0t² − 1.0t³, where x is in meters and t in seconds. What is the position of the particle when it achieves its maximum speed in the positive x direction?

The position of a particle as it moves along the x axis is given for t > 0 by x = (t³ − 3t² + 6t) m, where t is in s. Where is the particle when it achieves its minimum speed (after t = 0)?