Exam 2: Equations and Inequalities

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Find two consecutive odd integers whose product is 899.

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Solve the inequality. Write the solution set in interval notation. - ∣8x+8∣<1| 8 x + 8 | < 1

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Decide whether the statement is true or false. - −5 is a solution of 5x−6=−31. - 5 \text { is a solution of } 5 x - 6 = - 31 \text {. }

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Decide whether the equation is an identity, a conditional equation, or a contradiction. Give the solution set. - 5(2x−31)=10x−1555 ( 2 x - 31 ) = 10 x - 155

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Find the quotient. Write the answer in standard form. - 4+2i7−9i\frac { 4 + 2 i } { 7 - 9 i }

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Find the quotient. Write the answer in standard form. - 7+3i6−9i\frac { 7 + 3 i } { 6 - 9 i }

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Indicate whether the statement is true always, sometimes, or never. -A real number is a complex number.

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Solve the problem. -A cylindrical container has a volume of 1936πcm31936 \pi \mathrm { cm } ^ { 3 } and a radius of 11 cm. Find the height of the container.

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Solve the inequality. Write the solution set in interval notation. - ∣−3−8x∣>6| - 3 - 8 x | > 6

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Find two consecutive even integers whose product is 224.

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Solve the inequality. Write the solution set in interval notation. - x2(x+64)2≥0x ^ { 2 } ( x + 64 ) ^ { 2 } \geq 0

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Solve and graph the inequality. Give answer in interval notation. - 4x+9≥3x+134 x + 9 \geq 3 x + 13  Solve and graph the inequality. Give answer in interval notation. - 4 x + 9 \geq 3 x + 13

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Determine whether or not the equation is linear. - −3x+1=x−5- 3 x + 1 = x - 5

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Find the product. Write the answer in standard form. - (−2+3i)3( - 2 + 3 i ) ^ { 3 }

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Write the number as the product of a real number and i. - −23\sqrt { - 23 }

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Decide what values of the variable cannot possibly be solutions for the equation. - xx−5−13x6x+6=0\frac { x } { x - 5 } - \frac { 13 x } { 6 x + 6 } = 0

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Solve the rational inequality. Write the solution set in interval notation. - 2x+7x−7≤0\frac { 2 x + 7 } { x - 7 } \leq 0

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Solve the inequality. Write the solution set in interval notation. - ∣4x+1x−6∣≥0\left| \frac { 4 x + 1 } { x - 6 } \right| \geq 0

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Decide what values of the variable cannot possibly be solutions for the equation. - 3x+1=3+x−4\sqrt { 3 x + 1 } = 3 + \sqrt { x - 4 }

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Determine whether or not the equation is linear. - 6x−5x(x−2)=11x6 x - 5 x ( x - 2 ) = 11 x

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