Exam 2: Equations and Inequalities

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Decide what values of the variable cannot possibly be solutions for the equation. - x+7+5=x\sqrt { x + 7 } + 5 = x

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A rectangular enclosure must have an area of at least 600yd2600 \mathrm { yd } ^ { 2 } . If 140 yd of fencing is to be used, and the width cannot exceed the length, within what limits must the width of the enclosure lie?

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Multiply or divide, as indicated. Simplify the answer. - −5⋅−5\sqrt { - 5 } \cdot \sqrt { - 5 }

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Find the sum or difference. Write the answer in standard form. - (2+6i)−(−8−6i)+(8+8i)( 2 + 6 i ) - ( - 8 - 6 i ) + ( 8 + 8 i )

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Decide what values of the variable cannot possibly be solutions for the equation. - 6xx−6−4x=24x2−6x\frac { 6 x } { x - 6 } - \frac { 4 } { x } = \frac { 24 } { x ^ { 2 } - 6 x }

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Indicate whether the statement is true always, sometimes, or never. -The product of two imaginary numbers is a real number.

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Decide what values of the variable cannot possibly be solutions for the equation. - (x2+2)1/2−(2x+5)1/2=0\left( x ^ { 2 } + 2 \right) ^ { 1 / 2 } - ( 2 x + 5 ) ^ { 1 / 2 } = 0

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Solve the formula for the indicated variable. - I=\mathbf { I } = Prt, for P\mathrm { P }

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Find the sum or difference. Write the answer in standard form. - 7i+(−3−i)7 i + ( - 3 - i )

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Simplify the power of i. -Which one of the following equations is set up for direct use of the zero-factor property?

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Decide what values of the variable cannot possibly be solutions for the equation. - 2x+15−x=6\sqrt { 2 x + 15 } - x = 6

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Solve the inequality. Write the solution set in interval notation. - ∣x4+6x2+9∣<0\left| x ^ { 4 } + 6 x ^ { 2 } + 9 \right| < 0

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Decide what values of the variable cannot possibly be solutions for the equation. - (x−4)1/4+10=0( x - 4 ) ^ { 1 / 4 } + 10 = 0

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Decide what values of the variable cannot possibly be solutions for the equation. - x−34+8=0\sqrt [ 4 ] { x - 3 } + 8 = 0

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Graph the solution set. - ∣9x+6∣=5| 9 x + 6 | = 5

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Graph the solution set. - ∣x2+3x−10∣=0\left| x ^ { 2 } + 3 x - 10 \right| = 0

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Find the values of a, b, and c for which the quadratic equation ax2+bx+c=0a x ^ { 2 } + b x + c = 0 0 has the given numbers as solutions. Then use those values to write a quadratic equation. - −8+42,−8−42- 8 + 4 \sqrt { 2 } , - 8 - 4 \sqrt { 2 }

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The temperatures in parts of Antarctica in degrees Celsius roughly satisfy the inequality ∣C+92∣≤53| C + 92 | \leq 53 . What range of temperatures corresponds to this inequality?

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Solve for the indicated variable. - 1 A=1 m+1t\frac { 1 } { \mathrm {~A} } = \frac { 1 } { \mathrm {~m} } + \frac { 1 } { \mathrm { t } } , for t\mathrm { t }

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Solve the cubic equation using factoring and the quadratic formula. - x3−8=0x ^ { 3 } - 8 = 0

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