Exam 2: Equations and Inequalities

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Decide what values of the variable cannot possibly be solutions for the equation. -An experienced accountant can prepare a tax return in 8 hours. A novice accountant can do the job in 14 hours. How long will it take them to do the job working together?

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Identify the number as real, complex, pure imaginary, or nonreal complex. More than one of these descriptions may apply. - −6\sqrt { - 6 }

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Solve the equation by the square root property. - (x−7)2=11( x - 7 ) ^ { 2 } = 11

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Solve the equation by completing the square. - x2+10x=−16x ^ { 2 } + 10 x = - 16

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Solve for the indicated variable. - Z=A(1+x)1/2Z = A ( 1 + x ) ^ { 1 / 2 } , for xx

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Decide what values of the variable cannot possibly be solutions for the equation. - (3x−5)2+7(3x−5)+12=0( 3 x - 5 ) ^ { 2 } + 7 ( 3 x - 5 ) + 12 = 0

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Indicate whether the statement is true always, sometimes, or never. -The difference between two real numbers is a real number.

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Indicate whether the statement is true always, sometimes, or never. -When i is raised to an odd power, the result  is −1\text { is } - 1

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Simplify the power of i. - i−55\mathrm { i } ^ { - 55 }

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Write the number as the product of a real number and i. - −−16- \sqrt { - 16 }

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Graph the solution set. - ∣−7x+6∣=1| - 7 x + 6 | = 1

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Solve the inequality. Write the solution set in interval notation. - ∣8x−7∣>−8| 8 x - 7 | > - 8

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Graph the solution set. - ∣x∣≠3| x | \neq 3  Graph the solution set. - | x | \neq 3

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Graph the solution set. - ∣x∣≤6| x | \leq 6  Graph the solution set. - | x | \leq 6

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Solve for y. - 8x−6(x+y)=y−x8 x - 6 ( x + y ) = y - x

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Solve the cubic equation using factoring and the quadratic formula. - x3+1=0x ^ { 3 } + 1 = 0

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Indicate whether the statement is true always, sometimes, or never. -The sum of two imaginary numbers is an imaginary number.

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Decide what values of the variable cannot possibly be solutions for the equation. - 4x=9x+94 \sqrt { x } = \sqrt { 9 x + 9 }

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Two cars leave an intersection. One car travels north; the other east. When the car traveling north had gone 12 mi, the distance between the cars was 4 mi more than the distance traveled by the car heading east. How far had The east bound car traveled?

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Decide what values of the variable cannot possibly be solutions for the equation. - −5x2−4x−4=−15xx−4+4\frac { - 5 x ^ { 2 } - 4 } { x - 4 } = \frac { - 15 x } { x - 4 } + 4

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