Exam 2: Equations and Inequalities

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Solve and graph the inequality. Give answer in interval notation. - 2x−54<132\frac { 2 x - 5 } { 4 } < \frac { 13 } { 2 }  Solve and graph the inequality. Give answer in interval notation. - \frac { 2 x - 5 } { 4 } < \frac { 13 } { 2 }

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Solve the equation using the quadratic formula. - x2+x+5=0x ^ { 2 } + x + 5 = 0

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Decide what values of the variable cannot possibly be solutions for the equation. - 2x+3−x+1=1\sqrt { 2 x + 3 } - \sqrt { x + 1 } = 1

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Solve for y. - 5=7x−8y5 = 7 x - 8 y

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A can has a surface area of 790 square inches. Its height is 6.91 inches. What is the radius of the circular top? Round to the nearest hundredth.

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Decide what values of the variable cannot possibly be solutions for the equation. - 5x2+5x−103=5x2−3x+63\sqrt [ 3 ] { 5 x ^ { 2 } + 5 x - 10 } = \sqrt [ 3 ] { 5 x ^ { 2 } - 3 x + 6 }

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Decide what values of the variable cannot possibly be solutions for the equation. - 1+1x=20x21 + \frac { 1 } { x } = \frac { 20 } { x ^ { 2 } }

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Solve and graph the inequality. Give answer in interval notation. - 4x+6>3x+84 x + 6 > 3 x + 8  Solve and graph the inequality. Give answer in interval notation. - 4 x + 6 > 3 x + 8

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Determine whether or not the equation is linear. - 2x−4+5(x+1)=6x+52 x - 4 + 5 ( x + 1 ) = 6 x + 5

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Solve the rational inequality. Write the solution set in interval notation. - (x−3)(x+7)x−4≤0\frac { ( x - 3 ) ( x + 7 ) } { x - 4 } \leq 0

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Solve the equation using the quadratic formula. - 4x2+8x+2=04 x ^ { 2 } + 8 x + 2 = 0

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Graph the solution set. - ∣x∣=−3| x | = - 3  Graph the solution set. - | x | = - 3

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Determine whether or not the equation is linear. - 5x−6x=05 x - 6 x = 0

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Solve the inequality. Write the solution set in interval notation. - ∣x+4∣<2| x + 4 | < 2

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Solve the equation using the quadratic formula. - x2−14x+53=0x ^ { 2 } - 14 x + 53 = 0

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Solve the problem. -Mardi received an inheritance of $50,000. She invested part at 1.75% and deposited the remainder in tax-free bonds at 2%. Her total annual income from the investments was $925. Find the amount invested at 1.75%.

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Decide what values of the variable cannot possibly be solutions for the equation. - x2/3=3x1/3x ^ { 2 / 3 } = 3 x ^ { 1 / 3 }

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Solve the equation for the indicated variable. Assume no denominator is 0. - 2x2−4xy+3y2=12 x ^ { 2 } - 4 x y + 3 y ^ { 2 } = 1 , for xx

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Solve and graph the inequality. Give answer in interval notation. - 12x+20>4(2x+2)12 x + 20 > 4 ( 2 x + 2 )  Solve and graph the inequality. Give answer in interval notation. - 12 x + 20 > 4 ( 2 x + 2 )

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Graph the solution set. - ∣6x+1∣=−5| 6 x + 1 | = - 5

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