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Decide What Values of the Variable Cannot Possibly Be Solutions 1+1x=20x21 + \frac { 1 } { x } = \frac { 20 } { x ^ { 2 } }

Question 447

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- 1+1x=20x21 + \frac { 1 } { x } = \frac { 20 } { x ^ { 2 } }


A) {−4,5}\{ - 4,5 \}
B) {−15,14}\left\{ - \frac { 1 } { 5 } , \frac { 1 } { 4 } \right\}
C) {−5,4}\{ - 5,4 \}
D) {4,5}\{ 4,5 \}

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