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Decide What Values of the Variable Cannot Possibly Be Solutions 3x+1=3+x−4\sqrt { 3 x + 1 } = 3 + \sqrt { x - 4 }

Question 479

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- 3x+1=3+x−4\sqrt { 3 x + 1 } = 3 + \sqrt { x - 4 }


A) ∅\varnothing
B) {−1}\{ - 1 \}
C) {−5,−8}\{ - 5 , - 8 \}
D) {5,8}\{ 5,8 \}

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