Exam 2: Equations and Inequalities

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Solve the equation by the zero-factor property. - 6x2+23x+21=06 x ^ { 2 } + 23 x + 21 = 0

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Solve for y. - 3=4x−9y3 = 4 x - 9 y

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Solve the problem -Find two consecutive even integers whose product is 1520.

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Solve the problem. -Your company uses the quadratic model y y=−4.5x2+150xy = - 4.5 x ^ { 2 } + 150 x 150x to represent the average number of new customers who will be signed on (x) weeks after the release of your new service. How many new Customers can you expect to gain in week 16?

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Solve for the indicated variable. - A=2πa2A = 2 \pi a ^ { 2 } , for aa

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Solve and graph the inequality. Give answer in interval notation. - −2>5x+3≥−22- 2 > 5 x + 3 \geq - 22  Solve and graph the inequality. Give answer in interval notation. - - 2 > 5 x + 3 \geq - 22

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Solve the equation. - ∣2x+3∣+9=13| 2 x + 3 | + 9 = 13

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Solve the equation. - ∣x2+6x−27∣=0\left| x ^ { 2 } + 6 x - 27 \right| = 0

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Solve the problem. -The position of an object moving in a straight line is given by s s=2t2−3t\mathrm { s } = 2 \mathrm { t } ^ { 2 } - 3 \mathrm { t } where s is in meters and t 281) is the time in seconds the object has been in motion. How long (to the nearest tenth) will it take the Object to move 20 meters?

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Solve the equation. - ∣6x+6∣=5| 6 x + 6 | = 5

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Find the values of a, b, and c for which the quadratic equation ax2 + bx + c = 0 has the given numbers as solutions. Then use those values to write a quadratic equation. - 16i,−16i16 i , - 16 i

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Decide what values of the variable cannot possibly be solutions for the equation. - −5x2−6x−4=−15xx−4+6\frac { - 5 x ^ { 2 } - 6 } { x - 4 } = \frac { - 15 x } { x - 4 } + 6

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Solve the equation. - −7x+1=x−6- 7 x + 1 = x - 6

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Solve the equation for the indicated variable. Assume no denominator is 0. - 2x2−4xy+3y2=1, for x2 x ^ { 2 } - 4 x y + 3 y ^ { 2 } = 1 , \text { for } x

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Indicate whether the statement is true always, sometimes, or never. -The product of a pair of complex conjugates is a real number.

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Solve the formula for the indicated variable. - V=13BhV = \frac { 1 } { 3 } B h , for BB

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Decide whether or not the equations are equivalent. - = x+2=5

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Solve the problem. -Find the length of a rectangular lot with a perimeter of 148 m if the length is 6 m more than the width.

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Solve the inequality. Write the solution set in interval notation. - ∣−9x+5∣≥−9| - 9 x + 5 | \geq - 9

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Graph the solution set. - ∣x∣≤9| x | \leq 9  Graph the solution set. - | x | \leq 9

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