Exam 2: Equations and Inequalities

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Decide what values of the variable cannot possibly be solutions for the equation. - x4+720=89x2x ^ { 4 } + 720 = 89 x ^ { 2 }

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Write the inequality in interval notation. - 6>x≥36 > x \geq 3

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Find the sum or difference. Write the answer in standard form. - i7+9−(4+7i7)−(9−i7)i \sqrt { 7 } + 9 - ( 4 + 7 i \sqrt { 7 } ) - ( 9 - i \sqrt { 7 } )

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Decide what values of the variable cannot possibly be solutions for the equation. - (10+x)1/2+(11−5x)1/2=−1( 10 + x ) ^ { 1 / 2 } + ( 11 - 5 x ) ^ { 1 / 2 } = - 1

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Solve the equation by completing the square. - 8x2+7x=−28 x ^ { 2 } + 7 x = - 2

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Solve and graph the inequality. Give answer in interval notation. - x−218≥x−524+172\frac { x - 2 } { 18 } \geq \frac { x - 5 } { 24 } + \frac { 1 } { 72 }  Solve and graph the inequality. Give answer in interval notation. - \frac { x - 2 } { 18 } \geq \frac { x - 5 } { 24 } + \frac { 1 } { 72 }

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Solve the quadratic inequality. Write the solution set in interval notation. - x2+8x+12≥0x ^ { 2 } + 8 x + 12 \geq 0

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Solve the problem -Find two consecutive odd integers whose product is 483.

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Write the statement as an absolute value inequality. -In a milling operation, the thickness of the wood panels that can be produced satisfies the inequality ∣x−1.88∣≤1.20| \mathrm { x } - 1.88 | \leq 1.20 . What range of thicknesses corresponds to this inequality?

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Solve the problem. -A triangular shaped lake-front lot has a perimeter of 1200 ft. One side is 100 ft longer than the shortest side, while the third side is 200 ft longer than the shortest side. Find the lengths of all three Sides.

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Solve the quadratic inequality. Write the solution set in interval notation. - x2+3x+2>0x ^ { 2 } + 3 x + 2 > 0

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Decide what values of the variable cannot possibly be solutions for the equation. - 7x−4=1+9x+4\frac { 7 } { x - 4 } = 1 + \frac { 9 } { x + 4 }

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Solve for the indicated variable. - Ve=12mv2\mathrm { Ve } = \frac { 1 } { 2 } \mathrm { mv } ^ { 2 } , for v\mathrm { v }

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Solve the quadratic inequality. Write the solution set in interval notation. - x2−3x≤−2x ^ { 2 } - 3 x \leq - 2

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Determine whether or not the equation is linear. - 6x2−5x+9=06 x ^ { 2 } - 5 x + 9 = 0

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Solve the inequality. Write the solution set in interval notation. - ∣x4+6x2+9∣<0\left| x ^ { 4 } + 6 x ^ { 2 } + 9 \right| < 0

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Decide what values of the variable cannot possibly be solutions for the equation. - 5x−1−8x1−x=10\frac { 5 } { x - 1 } - \frac { 8 x } { 1 - x } = 10

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Find the quotient. Write the answer in standard form. - 10−i\frac { 10 } { - i }

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Solve the equation. - ∣9x3+3x2−6x∣=0\left| 9 x ^ { 3 } + 3 x ^ { 2 } - 6 x \right| = 0

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Solve the equation by completing the square. - x2+4x+8=0x ^ { 2 } + 4 x + 8 = 0

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