Exam 2: Equations and Inequalities

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Solve for y. - 9x+2y=59 x + 2 y = 5

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Solve for the indicated variable. - M=πr2hd\mathrm { M } = \pi \mathrm { r } ^ { 2 } \mathrm { hd } , for r\mathrm { r }

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Decide what values of the variable cannot possibly be solutions for the equation. - 8x−2+8x+2=3\frac { 8 } { x - 2 } + \frac { 8 } { x + 2 } = 3

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Decide what values of the variable cannot possibly be solutions for the equation. - 1−7x−30x2=01 - \frac { 7 } { x } - \frac { 30 } { x ^ { 2 } } = 0

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Solve for y. - 9x=10y−79 x = 10 y - 7

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Solve the inequality. Write the solution set in interval notation. - x3+4x2−4x−16≥0x ^ { 3 } + 4 x ^ { 2 } - 4 x - 16 \geq 0

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Write the statement as an absolute value inequality. - x\mathrm { x } is within 3 units of 2

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Solve the rational inequality. Write the solution set in interval notation. -The profit made when t units are sold, t > 0, is given by P=t2−30t+216\mathrm { P } = \mathrm { t } ^ { 2 } - 30 \mathrm { t } + 216 Determine the number of units to be sold in order for P > 0 (a profit is made).

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Decide what values of the variable cannot possibly be solutions for the equation. - x+6+2−x=4\sqrt { x + 6 } + \sqrt { 2 - x } = 4

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Decide what values of the variable cannot possibly be solutions for the equation. - 8x−5−3x+9=0\sqrt { 8 x - 5 } - \sqrt { 3 x + 9 } = 0

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Decide what values of the variable cannot possibly be solutions for the equation. - 12x+9x=12\frac { 1 } { 2 x } + \frac { 9 } { x } = 12

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Solve the problem. -In a chemistry class, 9 liters of a 4% silver iodide solution must be mixed with a 10% solution to get a 6% solution. How many liters of the 10% solution are needed?

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Solve the problem -The sum of the squares of two consecutive even integers is 2452. Find the integers.

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Solve the rational inequality. Write the solution set in interval notation. - −4x+62x2+2>0\frac { - 4 x + 6 } { 2 x ^ { 2 } + 2 } > 0

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Find the sum or difference. Write the answer in standard form. - (2+5i)−(−4−7i)−(−1−3i)( 2 + 5 i ) - ( - 4 - 7 i ) - ( - 1 - 3 i )

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Decide what values of the variable cannot possibly be solutions for the equation. - −4x−8+8x+8=−64x2−64\frac { - 4 } { x - 8 } + \frac { 8 } { x + 8 } = \frac { - 64 } { x ^ { 2 } - 64 }

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Solve the equation. - 1−68x=251 - \frac { 6 } { 8 x } = \frac { 2 } { 5 }

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Graph the solution set. - ∣x∣=3| x | = 3  Graph the solution set. - | x | = 3

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Decide what values of the variable cannot possibly be solutions for the equation. - 6x2/5+23x1/5+20=06 x ^ { 2 / 5 } + 23 x ^ { 1 / 5 } + 20 = 0

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Solve the formula for the indicated variable. - A=bhA = b h , for hh

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