Exam 2: Equations and Inequalities

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Solve the equation. - −7[−2x+4−3(x+1)]=−3x−4- 7 [ - 2 x + 4 - 3 ( x + 1 ) ] = - 3 x - 4

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Solve for y. - 7x−6(x+y)=y−x7 x - 6 ( x + y ) = y - x

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Write the statement as an absolute value inequality. -The temperatures in a freeze-dry process in degrees Celsius roughly satisfy the inequality ∣C+99∣| C + 99 | ≤64\leq 64 . What range of temperatures corresponds to this inequality?

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Identify the number as real, complex, pure imaginary, or nonreal complex. More than one of these descriptions may apply. - π\pi

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Multiply or divide, as indicated. Simplify the answer. - −10−250\frac { \sqrt { - 10 } } { \sqrt { - 250 } }

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Find the product. Write the answer in standard form. - 6i(9−6i)6 i ( 9 - 6 i )

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Solve the equation by the square root property. -Only one of the following equations does not require Step 1 of the method for completing the square. Which one is it?

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Decide what values of the variable cannot possibly be solutions for the equation. - 6x+5=1−1x−5\frac { 6 } { x + 5 } = 1 - \frac { 1 } { x - 5 }

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Decide what values of the variable cannot possibly be solutions for the equation. - 6x−2/5+13x−1/5+6=06 x ^ { - 2 / 5 } + 13 x ^ { - 1 / 5 } + 6 = 0

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Solve the equation. - ∣−5x+7∣=4| - 5 x + 7 | = 4

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Solve for the indicated variable. - V=1m2VemV = \frac { 1 } { m } \sqrt { 2 V e m } , for mm

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Solve the equation. - −6x−2−2(x+1)=−(−7x+7)- 6 x - 2 - 2 ( x + 1 ) = - ( - 7 x + 7 )

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Solve the inequality. Write the solution set in interval notation. - ∣9−x∣≥1| 9 - x | \geq 1

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Solve the inequality. Write the solution set in interval notation. - ∣−5x+1∣<4| - 5 x + 1 | < 4

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Solve the problem. -A can has a surface area of 831 square inches. Its height is 5.67 inches. What is the radius of the circular top? Round to the nearest hundredth.

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Solve the formula for the indicated variable. - I=nEnr+RI = \frac { n E } { n r + R } , for nn

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Decide what values of the variable cannot possibly be solutions for the equation. - 211x−2=314x\frac { 2 } { 11 x } - 2 = \frac { 3 } { 14 x }

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Solve the problem. -A lot is in the shape of a right triangle. The shorter leg measures 180 m. The hypotenuse is 60 m longer than the length of the longer leg. How long is the longer leg?

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Find the sum or difference. Write the answer in standard form. - (6−9i)+(3+6i)( 6 - 9 i ) + ( 3 + 6 i )

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Find the quotient. Write the answer in standard form. - 7+3i4−6i\frac { 7 + 3 i } { 4 - 6 i }

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