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Decide What Values of the Variable Cannot Possibly Be Solutions 6x2/5+23x1/5+20=06 x ^ { 2 / 5 } + 23 x ^ { 1 / 5 } + 20 = 0

Question 379

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- 6x2/5+23x1/5+20=06 x ^ { 2 / 5 } + 23 x ^ { 1 / 5 } + 20 = 0


A) {2,3}\{ 2,3 \}

B) {312532,1024243}\left\{ \frac { 3125 } { 32 } , \frac { 1024 } { 243 } \right\}

C) {−312532,−1024243}\left\{ - \frac { 3125 } { 32 } , - \frac { 1024 } { 243 } \right\}

D) {−52,−43}\left\{ - \frac { 5 } { 2 } , - \frac { 4 } { 3 } \right\}

Correct Answer:

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