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Decide What Values of the Variable Cannot Possibly Be Solutions $\frac { - 5 x ^ { 2 } - 6 } { x - 4 } = \frac { - 15 x } { x - 4 } + 6$

Question 112

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- $\frac { - 5 x ^ { 2 } - 6 } { x - 4 } = \frac { - 15 x } { x - 4 } + 6$

A) $\left\{ - \frac { 6 } { 5 } , 3 \right\}$

B) $\left\{ \frac { 6 } { 5 } , - 3 \right\}$

C) $\{ 3 \}$

D) $\left\{ \frac { - 5 \pm \sqrt { 105 } } { 3 } \right\}$

Decide What Values of the Variable Cannot Possibly Be Solutions −5x2−6x−4=−15xx−4+6\frac { - 5 x ^ { 2 } - 6 } { x - 4 } = \frac { - 15 x } { x - 4 } + 6x−4−5x2−6​=x−4−15x​+6

Multiple Choice

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Decide What Values of the Variable Cannot Possibly Be Solutions $\frac { - 5 x ^ { 2 } - 6 } { x - 4 } = \frac { - 15 x } { x - 4 } + 6$

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