Exam 7: Analytic Trigonometry

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Use a half-angle formula to find the exact value of sin⁡(−15∘)\sin \left( - 15 ^ { \circ } \right) .

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Use addition or subtraction formulas to find the exact value of tan⁡(−15∘)\tan \left( - 15 ^ { \circ } \right) .

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Use an addition or subtraction formula to write tan⁡2π15+tan⁡6π51−tan⁡2π15tan⁡6π5\frac { \tan \frac { 2 \pi } { 15 } + \tan \frac { 6 \pi } { 5 } } { 1 - \tan \frac { 2 \pi } { 15 } \tan \frac { 6 \pi } { 5 } } and find the exact value.

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Find all solutions of sec⁡2x−4=0\sec ^ { 2 } x - 4 = 0 .

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Find all solutions of 4sin⁡2x−2(3+2)sin⁡x+6=04 \sin ^ { 2 } x - 2 ( \sqrt { 3 } + \sqrt { 2 } ) \sin x + \sqrt { 6 } = 0 .

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Write the given expression in terms of x and y only. cos⁡(tan⁡−1y−sin⁡−1x)\cos \left( \tan ^ { - 1 } y - \sin ^ { - 1 } x \right)

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Simplify. sin⁡xcos⁡xtan⁡x\frac { \sin x \cos x } { \tan x }

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Use a half-angle formula to find the exact value of sin⁡π8\sin \frac { \pi } { 8 } .

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Prove sin⁡4x+sin⁡2xcos⁡4x+cos⁡2x=tan⁡3x\frac { \sin 4 x + \sin 2 x } { \cos 4 x + \cos 2 x } = \tan 3 x .

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Sketch the graphs of f(x)=2sin⁡xf ( x ) = 2 \sin x and g(x)=sin⁡2xg ( x ) = \sin 2 x on the same axes and find their points of intersection.  Sketch the graphs of  f ( x ) = 2 \sin x  and  g ( x ) = \sin 2 x  on the same axes and find their points of intersection.

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Use a double-angle formula or half-angle formula to simplify sin⁡48∘1+cos⁡48∘\frac { \sin 48 ^ { \circ } } { 1 + \cos 48 ^ { \circ } } .

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Find all solutions of tan⁡4xsin⁡x−9sin⁡x=0\tan ^ { 4 } x \sin x - 9 \sin x = 0 .

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Verify the identity. sin⁡(−x)tan⁡(−x)=sin⁡2xsec⁡x\sin ( - x ) \tan ( - x ) = \sin ^ { 2 } x \sec x

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Find all solutions of cos⁡2x=cos⁡x+6\cos ^ { 2 } x = \cos x + 6 .

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Find sin⁡2x\sin 2 x , cos⁡2x\cos 2 x and tan⁡2x\tan 2 x , given that tan⁡θ=12\tan \theta = \frac { 1 } { 2 } and sin⁡θ<0\sin \theta < 0 .

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Use addition or subtraction formulas to find the exact value of tan⁡7π12\tan \frac { 7 \pi } { 12 } .

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Verify the identity. (tan⁡x+cot⁡x)2=sec⁡2x+csc⁡2x( \tan x + \cot x ) ^ { 2 } = \sec ^ { 2 } x + \csc ^ { 2 } x

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Make the indicated trigonometric substitution in the given algebraic expression and simplify. Assume that 0≤x≤π/20 \leq x \leq \pi / 2 x2−4,x=2sec⁡θ\sqrt { x ^ { 2 } - 4 } , \quad x = 2 \sec \theta

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Solve the given equation. sin⁡θ=22\sin \theta = \frac { \sqrt { 2 } } { 2 }

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Find the exact value of the expression. cos⁡(sin⁡−1(3/2)+tan⁡−1(3))\cos \left( \sin ^ { - 1 } ( \sqrt { 3 } / 2 ) + \tan ^ { - 1 } ( \sqrt { 3 } ) \right)

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