Exam 10: Systems of Equations and Inequalities

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Solve the system of linear equations. {x+z=2y+2z=7−x+z=4\left\{ \begin{array} { r } x + z = 2 \\y + 2 z = 7 \\- x + z = 4\end{array} \right.

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[10120127−1014]\left[ \begin{array} { c c c c } 1 & 0 & 1 & 2 \\0 & 1 & 2 & 7 \\- 1 & 0 & 1 & 4\end{array} \right] ⇒R3+R1→R3\begin{array} { c } \Rightarrow \\R _ {3 } + R _ { 1 } \rightarrow R _ { 3 }\end{array} [101201270026]\left[ \begin{array} { l l l l } 1 & 0 & 1 & 2 \\0 & 1 & 2 & 7 \\0 & 0 & 2 & 6\end{array} \right] R1−12R3→R1⇒R2−R3→R2\begin{array} { c } R _ { 1 } - \frac { 1 } { 2 } R _ {3 } \rightarrow R _ { 1 } \\\Rightarrow \\R _ { 2 } - R _ { 3 } \rightarrow R _ { 2 }\end{array} [100−101010026]\left[ \begin{array} { c c c c } 1 & 0 & 0 & - 1 \\0 & 1 & 0 & 1 \\0 & 0 & 2 & 6\end{array} \right] ⇒12R3\begin{array} { c } \Rightarrow \\\frac { 1 } { 2 } R _ { 3 }\end{array} [100−101010013]\left[ \begin{array} { c c c c } 1 & 0 & 0 & - 1 \\0 & 1 & 0 & 1 \\0 & 0 & 1 & 3\end{array} \right] , so the solution is x=−1x = - 1 , y=1y = 1 , z=3z = 3 .

Graph the solution of the system of inequalities. {x+3y>52x−y≤4\left\{ \begin{array} { l } x + 3 y > 5 \\2 x - y \leq 4\end{array} \right.

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Graph the solution of the system of inequalities. {y>4−x2y≤x\left\{ \begin{array} { l } y > 4 - x ^ { 2 } \\y \leq x\end{array} \right.

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Given A=[65]A = \left[ \begin{array} { l l } 6 & 5\end{array} \right] , B=[−5467]B = \left[ \begin{array} { l l } - 5 & 4 \\6 & 7\end{array} \right] , find ABA B , or explain why the operation cannot be performed.

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Given A=[−98−6−510−16]A = \left[ \begin{array} { c c } - 9 & 8 \\- 6 & - 5 \\10 & - 16\end{array} \right] and B=[102304]B = \left[ \begin{array} { l l } 1 & 0 \\2 & 3 \\0 & 4\end{array} \right] , solve 2X−A=3B2 X - A = 3 B , for XX , or explain why there is no solution.

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Solve the system of equations {3x+2y=8x−2y=0\left\{ \begin{aligned}3 x + 2 y & = 8 \\x - 2 y & = 0\end{aligned} \right. by converting to a matrix equation and using its inverse coefficient matrix [141418−38]\left[ \begin{array} { c c } \frac { 1 } { 4 } & \frac { 1 } { 4 } \\\frac { 1 } { 8 } & - \frac { 3 } { 8 }\end{array} \right] .

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Given A=[3524]A = \left[ \begin{array} { l l } 3 & 5 \\2 & 4\end{array} \right] and B=[−2438]B = \left[ \begin{array} { c c } - 2 & 4 \\3 & 8\end{array} \right] , solve X−2A=BX - 2 A = B , for the matrix XX , or explain why there is no solution.

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Use the graphical method to find all the solutions of the system of equations. {y+4x=x2y=−x2+8x−16\left\{ \begin{array} { l } y + 4 x = x ^ { 2 } \\y = - x ^ { 2 } + 8 x - 16\end{array} \right.

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A money manager invests his client's savings into two accounts, one paying 2%2 \% and the other 10%10 \% simple interest per year. He puts three times as much in the lower yielding investment because it's less risky than the other one. His client's annual interest is $4625\$ 4625 . How much did he invest at each rate?

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Solve the system of linear equations. {x+15y−z=8−x−3y+2z=52x+6y−4z=−10\left\{ \begin{array} { r } x + 15 y - z = 8 \\- x - 3 y + 2 z = 5 \\2 x + 6 y - 4 z = - 10\end{array} \right.

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Solve the system of equations {x+2y+z+w=0x+2y−z−w=0x+4y+z+2w=−1x+3y+z+w=2\left\{ \begin{array} { r } x + 2 y + z + w = 0 \\x + 2 y - z - w = 0 \\x + 4 y + z + 2 w = - 1 \\x + 3 y + z + w = 2\end{array} \right. by converting to a matrix equation and using its inverse coefficient matrix [52120−2−1001−12−12−12101−2]\left[ \begin{array} { c c c c } \frac { 5 } { 2 } & \frac { 1 } { 2 } & 0 & - 2 \\- 1 & 0 & 0 & 1 \\- \frac { 1 } { 2 } & - \frac { 1 } { 2 } & - 1 & 2 \\1 & 0 & 1 & - 2\end{array} \right] .

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Find all solutions for the system. {4x−5y=2−1x+3y=1\left\{ \begin{array} { l } \frac { 4 } { x } - \frac { 5 } { y } = 2 \\- \frac { 1 } { x } + \frac { 3 } { y } = 1\end{array} \right.

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Find the determinant of the matrix. Determine whether the matrix has an inverse or not, but do not calculate the inverse. ∣216−25−3815∣\left| \begin{array} { c c c } 2 & 1 & 6 \\- 2 & 5 & - 3 \\8 & 1 & 5\end{array} \right|

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Use back-substitution to solve the triangular system. {x+2y+z=0y−3z=14z=−4\left\{ \begin{array} { r } x + 2 y + z = 0 \\y - 3 z = 1 \\4 z = - 4\end{array} \right.

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Find the complete solution of the linear system or show that it is inconsistent. {x+2y+w=33x+2y−z−w=0y+2w=1y+z+w=3\left\{ \begin{array} { r } x + 2 y + w = 3 \\3 x + 2 y - z - w = 0 \\y + 2 w = 1 \\y + z + w = 3\end{array} \right.

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State whether the equation 3x−5y+z=423 x - 5 y + z = 42 is linear.

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Graph each linear system, either by hand or using a graphing device. Use the graph to determine whether the system has one solution, no solution, or infinitely many solutions. If there is exactly one solution, use the graph to find it. {3x−4y=12−x+43y=4\left\{ \begin{array} { l } 3 x - 4 y = 12 \\- x + \frac { 4 } { 3 } y = 4\end{array} \right.

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Given A=[1−324−13052]A = \left[ \begin{array} { c c c } 1 & - 3 & 2 \\4 & - 1 & 3 \\0 & 5 & 2\end{array} \right] and B=[03−2210−3−42]B = \left[ \begin{array} { c c c } 0 & 3 & - 2 \\2 & 1 & 0 \\- 3 & - 4 & 2\end{array} \right] , find ABA B , or explain why the operation cannot be performed.

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Given A=[25−33−20422]A = \left[ \begin{array} { c c c } 2 & 5 & - 3 \\3 & - 2 & 0 \\4 & 2 & 2\end{array} \right] and B=[−15025]B = \left[ \begin{array} { c c } - 1 & 5 \\0 & 25\end{array} \right] , find A−BA - B , or explain why the operation cannot be performed.

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Graph the inequality y>−xy > - x .

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