Exam 19: Electrochemistry

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When the following oxidation-reduction reaction in basic solution is balanced,what is the lowest whole-number coefficient for OH-,and on which side of the balanced equation should it appear? Cr2O3(s)→ Cr(OH)2(aq)+ CrO42-(aq)

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Given: Given:       Pb<sup>2+</sup> (aq​)+ 2e<sup>-</sup> <sup> </sup>  Pb(s); E​º = -0.13 V What is the standard cell potential for the following reaction? 2Cr(s)+ 3Pb<sup>2+</sup> (​aq​)→ 3Pb(s​)+ 2Cr<sup>3+</sup> (aq) Given:       Pb<sup>2+</sup> (aq​)+ 2e<sup>-</sup> <sup> </sup>  Pb(s); E​º = -0.13 V What is the standard cell potential for the following reaction? 2Cr(s)+ 3Pb<sup>2+</sup> (​aq​)→ 3Pb(s​)+ 2Cr<sup>3+</sup> (aq) Given:       Pb<sup>2+</sup> (aq​)+ 2e<sup>-</sup> <sup> </sup>  Pb(s); E​º = -0.13 V What is the standard cell potential for the following reaction? 2Cr(s)+ 3Pb<sup>2+</sup> (​aq​)→ 3Pb(s​)+ 2Cr<sup>3+</sup> (aq) Pb2+ (aq​)+ 2e- Given:       Pb<sup>2+</sup> (aq​)+ 2e<sup>-</sup> <sup> </sup>  Pb(s); E​º = -0.13 V What is the standard cell potential for the following reaction? 2Cr(s)+ 3Pb<sup>2+</sup> (​aq​)→ 3Pb(s​)+ 2Cr<sup>3+</sup> (aq)Pb(s); E​º = -0.13 V What is the standard cell potential for the following reaction? 2Cr(s)+ 3Pb2+ (​aq​)→ 3Pb(s​)+ 2Cr3+ (aq)

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What is E of the following cell reaction at 25°C? E°cell = 0.460 V.Cu(s)| Cu2+(0.020M)|| Ag+(0.16M)| Ag(s)

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In a table of standard reduction potentials,the strongest reducing agents are the _______ species in the half-reactions with the _______ E° values.

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For a reaction in a voltaic cell,both ΔH° and ΔS° are positive.Which of the following statements is true?

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Which of the following statements is true concerning the hypthetical electrochemical cell depicted below? (M1 and M2 are differing metals) M1 | M12+(aq)|| M2+(aq)| M2 M12+(aq)+ 2e− Which of the following statements is true concerning the hypthetical electrochemical cell depicted below? (M1 and M2 are differing metals) M1 | M1<sup>2+</sup>(aq)|| M2<sup>+</sup>(aq)| M2 M1<sup>2+</sup>(aq)+ 2e−  M1(s); E° = -2.91 V M2<sup>2+</sup>(aq)+ e−  M2(s); E° = -2.98 VM1(s); E° = -2.91 V M22+(aq)+ e− Which of the following statements is true concerning the hypthetical electrochemical cell depicted below? (M1 and M2 are differing metals) M1 | M1<sup>2+</sup>(aq)|| M2<sup>+</sup>(aq)| M2 M1<sup>2+</sup>(aq)+ 2e−  M1(s); E° = -2.91 V M2<sup>2+</sup>(aq)+ e−  M2(s); E° = -2.98 VM2(s); E° = -2.98 V

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In order to determine the identity of a particular transition metal (M),a voltaic cell is constructed at 25°C with the anode consisting of the transition metal as the electrode immersed in a solution of 0.0977 M M(NO3)2,and the cathode consisting of a copper electrode immersed in a 0.0724M Cu(NO3)2 solution.The two half-reactions are as follows: M(s) In order to determine the identity of a particular transition metal (M),a voltaic cell is constructed at 25°C with the anode consisting of the transition metal as the electrode immersed in a solution of 0.0977 M M(NO<sub>3</sub>)<sub>2</sub>,and the cathode consisting of a copper electrode immersed in a 0.0724M Cu(NO<sub>3</sub>)<sub>2</sub> solution.The two half-reactions are as follows: M(s)   M<sup>2+</sup>(aq)+ 2e<sup>-</sup> Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s) The potential measured across the cell is 1.13 V.What is the identity of the metal M? Reduction Half-Reaction E° (V) Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s) +0.34 Ni<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Ni(s) -0.23 Cd<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cd(s) - 0.40 Zn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Zn(s)-0.76 Mn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Mn(s) -1.18 M2+(aq)+ 2e- Cu2+(aq)+ 2e- In order to determine the identity of a particular transition metal (M),a voltaic cell is constructed at 25°C with the anode consisting of the transition metal as the electrode immersed in a solution of 0.0977 M M(NO<sub>3</sub>)<sub>2</sub>,and the cathode consisting of a copper electrode immersed in a 0.0724M Cu(NO<sub>3</sub>)<sub>2</sub> solution.The two half-reactions are as follows: M(s)   M<sup>2+</sup>(aq)+ 2e<sup>-</sup> Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s) The potential measured across the cell is 1.13 V.What is the identity of the metal M? Reduction Half-Reaction E° (V) Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s) +0.34 Ni<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Ni(s) -0.23 Cd<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cd(s) - 0.40 Zn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Zn(s)-0.76 Mn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Mn(s) -1.18Cu(s) The potential measured across the cell is 1.13 V.What is the identity of the metal M? Reduction Half-Reaction E° (V) Cu2+(aq)+ 2e- In order to determine the identity of a particular transition metal (M),a voltaic cell is constructed at 25°C with the anode consisting of the transition metal as the electrode immersed in a solution of 0.0977 M M(NO<sub>3</sub>)<sub>2</sub>,and the cathode consisting of a copper electrode immersed in a 0.0724M Cu(NO<sub>3</sub>)<sub>2</sub> solution.The two half-reactions are as follows: M(s)   M<sup>2+</sup>(aq)+ 2e<sup>-</sup> Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s) The potential measured across the cell is 1.13 V.What is the identity of the metal M? Reduction Half-Reaction E° (V) Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s) +0.34 Ni<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Ni(s) -0.23 Cd<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cd(s) - 0.40 Zn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Zn(s)-0.76 Mn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Mn(s) -1.18Cu(s) +0.34 Ni2+(aq)+ 2e- In order to determine the identity of a particular transition metal (M),a voltaic cell is constructed at 25°C with the anode consisting of the transition metal as the electrode immersed in a solution of 0.0977 M M(NO<sub>3</sub>)<sub>2</sub>,and the cathode consisting of a copper electrode immersed in a 0.0724M Cu(NO<sub>3</sub>)<sub>2</sub> solution.The two half-reactions are as follows: M(s)   M<sup>2+</sup>(aq)+ 2e<sup>-</sup> Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s) The potential measured across the cell is 1.13 V.What is the identity of the metal M? Reduction Half-Reaction E° (V) Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s) +0.34 Ni<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Ni(s) -0.23 Cd<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cd(s) - 0.40 Zn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Zn(s)-0.76 Mn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Mn(s) -1.18Ni(s) -0.23 Cd2+(aq)+ 2e- In order to determine the identity of a particular transition metal (M),a voltaic cell is constructed at 25°C with the anode consisting of the transition metal as the electrode immersed in a solution of 0.0977 M M(NO<sub>3</sub>)<sub>2</sub>,and the cathode consisting of a copper electrode immersed in a 0.0724M Cu(NO<sub>3</sub>)<sub>2</sub> solution.The two half-reactions are as follows: M(s)   M<sup>2+</sup>(aq)+ 2e<sup>-</sup> Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s) The potential measured across the cell is 1.13 V.What is the identity of the metal M? Reduction Half-Reaction E° (V) Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s) +0.34 Ni<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Ni(s) -0.23 Cd<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cd(s) - 0.40 Zn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Zn(s)-0.76 Mn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Mn(s) -1.18Cd(s) - 0.40 Zn2+(aq)+ 2e- In order to determine the identity of a particular transition metal (M),a voltaic cell is constructed at 25°C with the anode consisting of the transition metal as the electrode immersed in a solution of 0.0977 M M(NO<sub>3</sub>)<sub>2</sub>,and the cathode consisting of a copper electrode immersed in a 0.0724M Cu(NO<sub>3</sub>)<sub>2</sub> solution.The two half-reactions are as follows: M(s)   M<sup>2+</sup>(aq)+ 2e<sup>-</sup> Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s) The potential measured across the cell is 1.13 V.What is the identity of the metal M? Reduction Half-Reaction E° (V) Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s) +0.34 Ni<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Ni(s) -0.23 Cd<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cd(s) - 0.40 Zn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Zn(s)-0.76 Mn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Mn(s) -1.18Zn(s)-0.76 Mn2+(aq)+ 2e- In order to determine the identity of a particular transition metal (M),a voltaic cell is constructed at 25°C with the anode consisting of the transition metal as the electrode immersed in a solution of 0.0977 M M(NO<sub>3</sub>)<sub>2</sub>,and the cathode consisting of a copper electrode immersed in a 0.0724M Cu(NO<sub>3</sub>)<sub>2</sub> solution.The two half-reactions are as follows: M(s)   M<sup>2+</sup>(aq)+ 2e<sup>-</sup> Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s) The potential measured across the cell is 1.13 V.What is the identity of the metal M? Reduction Half-Reaction E° (V) Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s) +0.34 Ni<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Ni(s) -0.23 Cd<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cd(s) - 0.40 Zn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Zn(s)-0.76 Mn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Mn(s) -1.18Mn(s) -1.18

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Which of the following statements is true concerning the electrolysis of a 1.0 M aqueous solution of NaI? Reduction Half-Reaction E° (V) Na+(aq)+ e- Which of the following statements is true concerning the electrolysis of a 1.0 M aqueous solution of NaI? Reduction Half-Reaction E° (V) Na<sup>+</sup>(aq)+ e<sup>-</sup>  Na(s) -2.71 2H<sub>2</sub>O(l)+ 2e<sup>-</sup>  H<sub>2</sub>(g)+ 2OH<sup>-</sup>(aq) -0.83 2H<sup>+</sup>(aq)+ 2e<sup>-</sup>  H<sub>2</sub>(g) 0.00 I<sub>2</sub>(s)+ 2e<sup>-</sup>  2I<sup>-</sup>(aq) 0.54 O<sub>2</sub>(g)+ 4H<sup>+</sup>(aq)+ 4e<sup>-</sup>   2H<sub>2</sub>O(l) 1.23Na(s) -2.71 2H2O(l)+ 2e- Which of the following statements is true concerning the electrolysis of a 1.0 M aqueous solution of NaI? Reduction Half-Reaction E° (V) Na<sup>+</sup>(aq)+ e<sup>-</sup>  Na(s) -2.71 2H<sub>2</sub>O(l)+ 2e<sup>-</sup>  H<sub>2</sub>(g)+ 2OH<sup>-</sup>(aq) -0.83 2H<sup>+</sup>(aq)+ 2e<sup>-</sup>  H<sub>2</sub>(g) 0.00 I<sub>2</sub>(s)+ 2e<sup>-</sup>  2I<sup>-</sup>(aq) 0.54 O<sub>2</sub>(g)+ 4H<sup>+</sup>(aq)+ 4e<sup>-</sup>   2H<sub>2</sub>O(l) 1.23H2(g)+ 2OH-(aq) -0.83 2H+(aq)+ 2e- Which of the following statements is true concerning the electrolysis of a 1.0 M aqueous solution of NaI? Reduction Half-Reaction E° (V) Na<sup>+</sup>(aq)+ e<sup>-</sup>  Na(s) -2.71 2H<sub>2</sub>O(l)+ 2e<sup>-</sup>  H<sub>2</sub>(g)+ 2OH<sup>-</sup>(aq) -0.83 2H<sup>+</sup>(aq)+ 2e<sup>-</sup>  H<sub>2</sub>(g) 0.00 I<sub>2</sub>(s)+ 2e<sup>-</sup>  2I<sup>-</sup>(aq) 0.54 O<sub>2</sub>(g)+ 4H<sup>+</sup>(aq)+ 4e<sup>-</sup>   2H<sub>2</sub>O(l) 1.23H2(g) 0.00 I2(s)+ 2e- Which of the following statements is true concerning the electrolysis of a 1.0 M aqueous solution of NaI? Reduction Half-Reaction E° (V) Na<sup>+</sup>(aq)+ e<sup>-</sup>  Na(s) -2.71 2H<sub>2</sub>O(l)+ 2e<sup>-</sup>  H<sub>2</sub>(g)+ 2OH<sup>-</sup>(aq) -0.83 2H<sup>+</sup>(aq)+ 2e<sup>-</sup>  H<sub>2</sub>(g) 0.00 I<sub>2</sub>(s)+ 2e<sup>-</sup>  2I<sup>-</sup>(aq) 0.54 O<sub>2</sub>(g)+ 4H<sup>+</sup>(aq)+ 4e<sup>-</sup>   2H<sub>2</sub>O(l) 1.232I-(aq) 0.54 O2(g)+ 4H+(aq)+ 4e- Which of the following statements is true concerning the electrolysis of a 1.0 M aqueous solution of NaI? Reduction Half-Reaction E° (V) Na<sup>+</sup>(aq)+ e<sup>-</sup>  Na(s) -2.71 2H<sub>2</sub>O(l)+ 2e<sup>-</sup>  H<sub>2</sub>(g)+ 2OH<sup>-</sup>(aq) -0.83 2H<sup>+</sup>(aq)+ 2e<sup>-</sup>  H<sub>2</sub>(g) 0.00 I<sub>2</sub>(s)+ 2e<sup>-</sup>  2I<sup>-</sup>(aq) 0.54 O<sub>2</sub>(g)+ 4H<sup>+</sup>(aq)+ 4e<sup>-</sup>   2H<sub>2</sub>O(l) 1.23 2H2O(l) 1.23

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In order to determine the identity of a particular lanthanide metal (M),a voltaic cell is constructed at 25°C with the anode consisting of the lanthanide metal as the electrode immersed in a solution of 0.0467 M MCl3,and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO3)2 solution.The two half-reactions are as follows: M(s) In order to determine the identity of a particular lanthanide metal (M),a voltaic cell is constructed at 25°C with the anode consisting of the lanthanide metal as the electrode immersed in a solution of 0.0467 M MCl<sub>3</sub>,and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO<sub>3</sub>)<sub>2</sub> solution.The two half-reactions are as follows: M(s)  M<sup>3+</sup>(aq)+ 3e<sup>-</sup> Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s) The potential measured across the cell is 2.70 V.What is the identity of the metal? Reduction Half-Reaction E° (V) Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s)0.34 Ce<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Ce(s)-2.336 Tm<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Tm(s)-2.319 Eu<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Eu(s)-1.991 Gd<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Gd(s)-2.279 Sm<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Sm(s)-2.304M3+(aq)+ 3e- Cu2+(aq)+ 2e- In order to determine the identity of a particular lanthanide metal (M),a voltaic cell is constructed at 25°C with the anode consisting of the lanthanide metal as the electrode immersed in a solution of 0.0467 M MCl<sub>3</sub>,and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO<sub>3</sub>)<sub>2</sub> solution.The two half-reactions are as follows: M(s)  M<sup>3+</sup>(aq)+ 3e<sup>-</sup> Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s) The potential measured across the cell is 2.70 V.What is the identity of the metal? Reduction Half-Reaction E° (V) Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s)0.34 Ce<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Ce(s)-2.336 Tm<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Tm(s)-2.319 Eu<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Eu(s)-1.991 Gd<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Gd(s)-2.279 Sm<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Sm(s)-2.304Cu(s) The potential measured across the cell is 2.70 V.What is the identity of the metal? Reduction Half-Reaction E° (V) Cu2+(aq)+ 2e- In order to determine the identity of a particular lanthanide metal (M),a voltaic cell is constructed at 25°C with the anode consisting of the lanthanide metal as the electrode immersed in a solution of 0.0467 M MCl<sub>3</sub>,and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO<sub>3</sub>)<sub>2</sub> solution.The two half-reactions are as follows: M(s)  M<sup>3+</sup>(aq)+ 3e<sup>-</sup> Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s) The potential measured across the cell is 2.70 V.What is the identity of the metal? Reduction Half-Reaction E° (V) Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s)0.34 Ce<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Ce(s)-2.336 Tm<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Tm(s)-2.319 Eu<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Eu(s)-1.991 Gd<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Gd(s)-2.279 Sm<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Sm(s)-2.304Cu(s)0.34 Ce3+(aq)+ 3e- In order to determine the identity of a particular lanthanide metal (M),a voltaic cell is constructed at 25°C with the anode consisting of the lanthanide metal as the electrode immersed in a solution of 0.0467 M MCl<sub>3</sub>,and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO<sub>3</sub>)<sub>2</sub> solution.The two half-reactions are as follows: M(s)  M<sup>3+</sup>(aq)+ 3e<sup>-</sup> Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s) The potential measured across the cell is 2.70 V.What is the identity of the metal? Reduction Half-Reaction E° (V) Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s)0.34 Ce<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Ce(s)-2.336 Tm<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Tm(s)-2.319 Eu<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Eu(s)-1.991 Gd<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Gd(s)-2.279 Sm<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Sm(s)-2.304Ce(s)-2.336 Tm3+(aq)+ 3e- In order to determine the identity of a particular lanthanide metal (M),a voltaic cell is constructed at 25°C with the anode consisting of the lanthanide metal as the electrode immersed in a solution of 0.0467 M MCl<sub>3</sub>,and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO<sub>3</sub>)<sub>2</sub> solution.The two half-reactions are as follows: M(s)  M<sup>3+</sup>(aq)+ 3e<sup>-</sup> Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s) The potential measured across the cell is 2.70 V.What is the identity of the metal? Reduction Half-Reaction E° (V) Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s)0.34 Ce<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Ce(s)-2.336 Tm<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Tm(s)-2.319 Eu<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Eu(s)-1.991 Gd<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Gd(s)-2.279 Sm<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Sm(s)-2.304Tm(s)-2.319 Eu3+(aq)+ 3e- In order to determine the identity of a particular lanthanide metal (M),a voltaic cell is constructed at 25°C with the anode consisting of the lanthanide metal as the electrode immersed in a solution of 0.0467 M MCl<sub>3</sub>,and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO<sub>3</sub>)<sub>2</sub> solution.The two half-reactions are as follows: M(s)  M<sup>3+</sup>(aq)+ 3e<sup>-</sup> Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s) The potential measured across the cell is 2.70 V.What is the identity of the metal? Reduction Half-Reaction E° (V) Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s)0.34 Ce<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Ce(s)-2.336 Tm<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Tm(s)-2.319 Eu<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Eu(s)-1.991 Gd<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Gd(s)-2.279 Sm<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Sm(s)-2.304Eu(s)-1.991 Gd3+(aq)+ 3e- In order to determine the identity of a particular lanthanide metal (M),a voltaic cell is constructed at 25°C with the anode consisting of the lanthanide metal as the electrode immersed in a solution of 0.0467 M MCl<sub>3</sub>,and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO<sub>3</sub>)<sub>2</sub> solution.The two half-reactions are as follows: M(s)  M<sup>3+</sup>(aq)+ 3e<sup>-</sup> Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s) The potential measured across the cell is 2.70 V.What is the identity of the metal? Reduction Half-Reaction E° (V) Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s)0.34 Ce<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Ce(s)-2.336 Tm<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Tm(s)-2.319 Eu<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Eu(s)-1.991 Gd<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Gd(s)-2.279 Sm<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Sm(s)-2.304Gd(s)-2.279 Sm3+(aq)+ 3e- In order to determine the identity of a particular lanthanide metal (M),a voltaic cell is constructed at 25°C with the anode consisting of the lanthanide metal as the electrode immersed in a solution of 0.0467 M MCl<sub>3</sub>,and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO<sub>3</sub>)<sub>2</sub> solution.The two half-reactions are as follows: M(s)  M<sup>3+</sup>(aq)+ 3e<sup>-</sup> Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s) The potential measured across the cell is 2.70 V.What is the identity of the metal? Reduction Half-Reaction E° (V) Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s)0.34 Ce<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Ce(s)-2.336 Tm<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Tm(s)-2.319 Eu<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Eu(s)-1.991 Gd<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Gd(s)-2.279 Sm<sup>3+</sup>(aq)+ 3e<sup>-</sup>  Sm(s)-2.304Sm(s)-2.304

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Given: Given:             What is the cell potential at 25°C for the following cell? Cr(s)| Cr<sup>3+</sup>(0.010 M)|| Ag<sup>+</sup>(0.00025 M)| Ag(s) Given:             What is the cell potential at 25°C for the following cell? Cr(s)| Cr<sup>3+</sup>(0.010 M)|| Ag<sup>+</sup>(0.00025 M)| Ag(s) Given:             What is the cell potential at 25°C for the following cell? Cr(s)| Cr<sup>3+</sup>(0.010 M)|| Ag<sup>+</sup>(0.00025 M)| Ag(s) Given:             What is the cell potential at 25°C for the following cell? Cr(s)| Cr<sup>3+</sup>(0.010 M)|| Ag<sup>+</sup>(0.00025 M)| Ag(s) Given:             What is the cell potential at 25°C for the following cell? Cr(s)| Cr<sup>3+</sup>(0.010 M)|| Ag<sup>+</sup>(0.00025 M)| Ag(s) Given:             What is the cell potential at 25°C for the following cell? Cr(s)| Cr<sup>3+</sup>(0.010 M)|| Ag<sup>+</sup>(0.00025 M)| Ag(s) What is the cell potential at 25°C for the following cell? Cr(s)| Cr3+(0.010 M)|| Ag+(0.00025 M)| Ag(s)

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What is the balanced spontaneous reaction and standard cell potential of an electrochemical cell constructed from half cells with the following half reactions? Cu2+(aq​)+ 2e¯ → Cu(s)E° = 0.337 V What is the balanced spontaneous reaction and standard cell potential of an electrochemical cell constructed from half cells with the following half reactions? Cu<sup>2+</sup>(aq​)+ 2e¯ <sup> </sup>→ Cu(s)E° = 0.337 V   E° = -0.130 V E° = -0.130 V

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A _____ is a commercial electrochemical cell used to obtain sodium metal by the electrolysis of molten sodium chloride.

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If the value of E°cell is 2.10 V for the reaction F2 (g)+ 2Fe2+ (aq​)→ 2Fe3+ (aq)+ 2F- (aq), What is the value of E°cell for F- (aq)+ Fe3+ (aq)→ Fe2+ (aq​)+ 1/2 F2(g)?

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If E°cell for a certain reaction is 1 V (n = 4),and ΔS° is 11.2 J/(K⋅mol),what is ΔH° in units of J/mol at 25°C?

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Balance the following oxidation-reduction occurring in acidic solution. MnO4-(aq)+ Co2+(aq)→ Mn2+(aq)+ Co3+(aq)

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What is the cell reaction for the following electrochemical cell? Pt | Fe2+(aq),Fe3+(aq)|| Cr3+(aq)| Cr

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Given: Ni2+(aq)+ 2e- Given: Ni<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Ni(s); E° = -0.23 V 2H<sup>+</sup>(aq)+ 2e<sup>-</sup>  H<sub>2</sub>(g); E° = 0.00 VAg<sup>+</sup>(aq)+ e<sup>-</sup>  Ag(s); E° = 0.80 V NO<sub>3</sub><sup>-</sup>(aq)+ 4H<sup>+</sup>(aq)+ 3e<sup>-</sup>  NO(g)+ 2H<sub>2</sub>O(l); E° = 0.96 V Which of the following statements is true?Ni(s); E° = -0.23 V 2H+(aq)+ 2e- Given: Ni<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Ni(s); E° = -0.23 V 2H<sup>+</sup>(aq)+ 2e<sup>-</sup>  H<sub>2</sub>(g); E° = 0.00 VAg<sup>+</sup>(aq)+ e<sup>-</sup>  Ag(s); E° = 0.80 V NO<sub>3</sub><sup>-</sup>(aq)+ 4H<sup>+</sup>(aq)+ 3e<sup>-</sup>  NO(g)+ 2H<sub>2</sub>O(l); E° = 0.96 V Which of the following statements is true?H2(g); E° = 0.00 VAg+(aq)+ e- Given: Ni<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Ni(s); E° = -0.23 V 2H<sup>+</sup>(aq)+ 2e<sup>-</sup>  H<sub>2</sub>(g); E° = 0.00 VAg<sup>+</sup>(aq)+ e<sup>-</sup>  Ag(s); E° = 0.80 V NO<sub>3</sub><sup>-</sup>(aq)+ 4H<sup>+</sup>(aq)+ 3e<sup>-</sup>  NO(g)+ 2H<sub>2</sub>O(l); E° = 0.96 V Which of the following statements is true?Ag(s); E° = 0.80 V NO3-(aq)+ 4H+(aq)+ 3e- Given: Ni<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Ni(s); E° = -0.23 V 2H<sup>+</sup>(aq)+ 2e<sup>-</sup>  H<sub>2</sub>(g); E° = 0.00 VAg<sup>+</sup>(aq)+ e<sup>-</sup>  Ag(s); E° = 0.80 V NO<sub>3</sub><sup>-</sup>(aq)+ 4H<sup>+</sup>(aq)+ 3e<sup>-</sup>  NO(g)+ 2H<sub>2</sub>O(l); E° = 0.96 V Which of the following statements is true?NO(g)+ 2H2O(l); E° = 0.96 V Which of the following statements is true?

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Given: Zn2+(aq)+ 2e- Given: Zn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Zn(s); E° = -0.76 V 2H<sup>+</sup>(aq)+ 2e<sup>-</sup>  H<sub>2</sub>(g); E° = 0.00 V I<sub>2</sub>(s)+ 2e<sup>-</sup>  2I<sup>-</sup>(aq); E° = 0.54 V Br<sub>2</sub>(l)+ 2e<sup>-</sup>  2Br<sup>-</sup>(aq); E° = 1.07 V Ni<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Ni(s); E° = -0.23 V Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s); E° = 0.34 V Which of the following species will oxidize Ni but not Cu?Zn(s); E° = -0.76 V 2H+(aq)+ 2e- Given: Zn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Zn(s); E° = -0.76 V 2H<sup>+</sup>(aq)+ 2e<sup>-</sup>  H<sub>2</sub>(g); E° = 0.00 V I<sub>2</sub>(s)+ 2e<sup>-</sup>  2I<sup>-</sup>(aq); E° = 0.54 V Br<sub>2</sub>(l)+ 2e<sup>-</sup>  2Br<sup>-</sup>(aq); E° = 1.07 V Ni<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Ni(s); E° = -0.23 V Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s); E° = 0.34 V Which of the following species will oxidize Ni but not Cu?H2(g); E° = 0.00 V I2(s)+ 2e- Given: Zn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Zn(s); E° = -0.76 V 2H<sup>+</sup>(aq)+ 2e<sup>-</sup>  H<sub>2</sub>(g); E° = 0.00 V I<sub>2</sub>(s)+ 2e<sup>-</sup>  2I<sup>-</sup>(aq); E° = 0.54 V Br<sub>2</sub>(l)+ 2e<sup>-</sup>  2Br<sup>-</sup>(aq); E° = 1.07 V Ni<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Ni(s); E° = -0.23 V Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s); E° = 0.34 V Which of the following species will oxidize Ni but not Cu?2I-(aq); E° = 0.54 V Br2(l)+ 2e- Given: Zn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Zn(s); E° = -0.76 V 2H<sup>+</sup>(aq)+ 2e<sup>-</sup>  H<sub>2</sub>(g); E° = 0.00 V I<sub>2</sub>(s)+ 2e<sup>-</sup>  2I<sup>-</sup>(aq); E° = 0.54 V Br<sub>2</sub>(l)+ 2e<sup>-</sup>  2Br<sup>-</sup>(aq); E° = 1.07 V Ni<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Ni(s); E° = -0.23 V Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s); E° = 0.34 V Which of the following species will oxidize Ni but not Cu?2Br-(aq); E° = 1.07 V Ni2+(aq)+ 2e- Given: Zn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Zn(s); E° = -0.76 V 2H<sup>+</sup>(aq)+ 2e<sup>-</sup>  H<sub>2</sub>(g); E° = 0.00 V I<sub>2</sub>(s)+ 2e<sup>-</sup>  2I<sup>-</sup>(aq); E° = 0.54 V Br<sub>2</sub>(l)+ 2e<sup>-</sup>  2Br<sup>-</sup>(aq); E° = 1.07 V Ni<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Ni(s); E° = -0.23 V Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s); E° = 0.34 V Which of the following species will oxidize Ni but not Cu?Ni(s); E° = -0.23 V Cu2+(aq)+ 2e- Given: Zn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Zn(s); E° = -0.76 V 2H<sup>+</sup>(aq)+ 2e<sup>-</sup>  H<sub>2</sub>(g); E° = 0.00 V I<sub>2</sub>(s)+ 2e<sup>-</sup>  2I<sup>-</sup>(aq); E° = 0.54 V Br<sub>2</sub>(l)+ 2e<sup>-</sup>  2Br<sup>-</sup>(aq); E° = 1.07 V Ni<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Ni(s); E° = -0.23 V Cu<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Cu(s); E° = 0.34 V Which of the following species will oxidize Ni but not Cu?Cu(s); E° = 0.34 V Which of the following species will oxidize Ni but not Cu?

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What is the cell notation for the voltaic cell shown below? What is the cell notation for the voltaic cell shown below?

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Given: Zn2+(aq)+ 2e- Given: Zn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Zn(s); E° = -0.76 V Co<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Co(s); E° = -0.28 V Sn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Sn(s); E° = -0.15 V Pb<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Pb(s); E° = -0.13 V Fe<sup>3+</sup>(aq)+ e<sup>-</sup>  Fe<sup>2+</sup>(aq); E° = 0.77 V Under standard-state conditions,which of the following pairs of elements or ions is capable of reducing Sn<sup>2+</sup>(aq)to Sn(s)?Zn(s); E° = -0.76 V Co2+(aq)+ 2e- Given: Zn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Zn(s); E° = -0.76 V Co<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Co(s); E° = -0.28 V Sn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Sn(s); E° = -0.15 V Pb<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Pb(s); E° = -0.13 V Fe<sup>3+</sup>(aq)+ e<sup>-</sup>  Fe<sup>2+</sup>(aq); E° = 0.77 V Under standard-state conditions,which of the following pairs of elements or ions is capable of reducing Sn<sup>2+</sup>(aq)to Sn(s)?Co(s); E° = -0.28 V Sn2+(aq)+ 2e- Given: Zn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Zn(s); E° = -0.76 V Co<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Co(s); E° = -0.28 V Sn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Sn(s); E° = -0.15 V Pb<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Pb(s); E° = -0.13 V Fe<sup>3+</sup>(aq)+ e<sup>-</sup>  Fe<sup>2+</sup>(aq); E° = 0.77 V Under standard-state conditions,which of the following pairs of elements or ions is capable of reducing Sn<sup>2+</sup>(aq)to Sn(s)?Sn(s); E° = -0.15 V Pb2+(aq)+ 2e- Given: Zn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Zn(s); E° = -0.76 V Co<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Co(s); E° = -0.28 V Sn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Sn(s); E° = -0.15 V Pb<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Pb(s); E° = -0.13 V Fe<sup>3+</sup>(aq)+ e<sup>-</sup>  Fe<sup>2+</sup>(aq); E° = 0.77 V Under standard-state conditions,which of the following pairs of elements or ions is capable of reducing Sn<sup>2+</sup>(aq)to Sn(s)?Pb(s); E° = -0.13 V Fe3+(aq)+ e- Given: Zn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Zn(s); E° = -0.76 V Co<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Co(s); E° = -0.28 V Sn<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Sn(s); E° = -0.15 V Pb<sup>2+</sup>(aq)+ 2e<sup>-</sup>  Pb(s); E° = -0.13 V Fe<sup>3+</sup>(aq)+ e<sup>-</sup>  Fe<sup>2+</sup>(aq); E° = 0.77 V Under standard-state conditions,which of the following pairs of elements or ions is capable of reducing Sn<sup>2+</sup>(aq)to Sn(s)?Fe2+(aq); E° = 0.77 V Under standard-state conditions,which of the following pairs of elements or ions is capable of reducing Sn2+(aq)to Sn(s)?

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