In Order to Determine the Identity of a Particular Lanthanide

In order to determine the identity of a particular lanthanide metal (M) ,a voltaic cell is constructed at 25°C with the anode consisting of the lanthanide metal as the electrode immersed in a solution of 0.0467 M MCl₃,and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO₃) ₂ solution.The two half-reactions are as follows:
M(s) M³⁺(aq) + 3e^- Cu²⁺(aq) + 2e^- Cu(s)
The potential measured across the cell is 2.70 V.What is the identity of the metal?
Reduction Half-Reaction
E° (V)
Cu²⁺(aq) + 2e^- Cu(s) 0.34
Ce³⁺(aq) + 3e^- Ce(s) -2.336
Tm³⁺(aq) + 3e^- Tm(s) -2.319
Eu³⁺(aq) + 3e^- Eu(s) -1.991
Gd³⁺(aq) + 3e^- Gd(s) -2.279
Sm³⁺(aq) + 3e^- Sm(s) -2.304

A) Tm
B) Gd
C) Ce
D) Eu
E) Sm

Correct Answer:

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Access For Free