Exam 10: Amplifier Frequency Response

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A voltage gain of 20 dB represents a voltage gain of 10.

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When each amplifier stage in a two- stage amplifier has equal dominant upper critical frequencies, the overall dominant frequency is equal to

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  Figure 1 Assume r<sub>e</sub>' = 15 ▲. -Refer to Figure 1. The cutoff frequency due to C1 is Figure 1 Assume re' = 15 ▲. -Refer to Figure 1. The cutoff frequency due to C1 is

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  Figure 1 Assume r<sub>e</sub>' = 15 ▲. -Refer to Figure 1. Rin is approximately Figure 1 Assume re' = 15 ▲. -Refer to Figure 1. Rin is approximately

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  Figure 5. The sec/div control is set to 0.05 µS/div. -Refer to Figure 5. From the information given, the fcu is approximately Figure 5. The sec/div control is set to 0.05 µS/div. -Refer to Figure 5. From the information given, the fcu is approximately

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The high- frequency response of a circuit can be measured by

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The phase shift at the upper cutoff frequency of an amplifier is 90°.

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  Figure 1 Assume r<sub>e</sub>' = 15 ▲. -Refer to Figure 1. What value of RL will produce a cutoff frequency due to C3 of 25 Hz? Figure 1 Assume re' = 15 ▲. -Refer to Figure 1. What value of RL will produce a cutoff frequency due to C3 of 25 Hz?

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  Figure 1 Assume r<sub>e</sub>' = 15 ▲. -Refer to Figure 1. Assume that Cbc = 6 pF and RL= 27 k▲. The Miller input capacitance due to Cbc is Figure 1 Assume re' = 15 ▲. -Refer to Figure 1. Assume that Cbc = 6 pF and RL= 27 k▲. The Miller input capacitance due to Cbc is

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The input coupling capacitor is generally smaller on a CS amplifier than its equivalent BJT counterpart because

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The input coupling capacitor affects the low- frequency response.

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A Bode plot is a graph of decibel voltage gain as a function of phase angle.

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  Figure 2 I<sub>GSS </sub>(max)= 100 pA. V<sub>GS </sub>= -2.4 V -Refer to Figure 2. The value of C1 that has a lower cutoff frequency of approximately 20 Hz is Figure 2 IGSS (max)= 100 pA. VGS = -2.4 V -Refer to Figure 2. The value of C1 that has a lower cutoff frequency of approximately 20 Hz is

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