Exam 5: Transistor Bias Circuits

Figure 7 -Refer to Figure 7. Assume the thermistor has a resistance of 1.7 k▲. VOUT is approximately

Of the methods shown below, the one that has the most stability is

Assume the output of an amplifier has both peaks clipped. This can be caused by

VBE of properly biased pnp transistor is a positive value.

Figure 1 -Refer to Figure 1. The end points of the dc load line are at approximately

Figure 4 -Refer to Figure 4. The emitter voltage, VE is approximately

Figure 1 -Refer to Figure 1. The Q- point is approximately at

Figure 5 (This is similar to Figure 4 but uses a pnp transistor with the same fi.) -Refer to Figure 5. If the transistor is replaced with a lower fi one, there will be

Figure 5 (This is similar to Figure 4 but uses a pnp transistor with the same fi.) -Refer to Figure 5. If RC is replaced with a 1.5 k▲ resistor, you would expect to see a large change in

At cutoff,

A stiff voltage divider is one in which

The Q- point can be anywhere along the dc load line.

Figure 2 -Refer to Figure 2. VCE is approximately

RIN(BASE)will increase if IE decreases.

Figure 7 -Refer to Figure 7. The input resistance of RIN(BASE)

The dc load line is a straight line drawn from IC(sat)to VCC.

Figure 4 -Refer to Figure 4. If you wanted to develop the equation for IE,

Figure 5 (This is similar to Figure 4 but uses a pnp transistor with the same fi.) -Refer to Figure 5. If RB is increased, VE will

Figure 2 -Refer to Figure 2. The value of IC is approximately

Figure 7 -Refer to Figure 3. Note the transistor is a pnp type. The value of IC is approximately