Exam 4: Bipolar Junction Transistors
Exam 1: Introduction to Semiconductors21 Questions
Exam 2: Diodes and Applications40 Questions
Exam 3: Special-Purpose Diodes40 Questions
Exam 4: Bipolar Junction Transistors40 Questions
Exam 5: Transistor Bias Circuits31 Questions
Exam 6: BJT Amplifiers43 Questions
Exam 7: BJT Power Amplifiers35 Questions
Exam 8: Field-Effect Transistors Fets33 Questions
Exam 9: Fet Amplifiers and Switching Circuits36 Questions
Exam 10: Amplifier Frequency Response33 Questions
Exam 11: Thyristors35 Questions
Exam 12: The Operational Amplifier36 Questions
Exam 13: Basic Op-Amp Circuits35 Questions
Exam 14: Special-Purpose Integrated Circuits35 Questions
Exam 15: Active Filters35 Questions
Exam 16: Oscillators33 Questions
Exam 17: Voltage Regulators35 Questions
Exam 18: Communication Devices and Methods31 Questions
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When a BJT is conducting, the collector current is identical to the emitter current.
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Correct Answer:
False
Figure 3 The transistor has the following ratings: PD(max)= 650 mW, VCE(max)= 40 V, and IC(max)= 200 mA.
-Refer to Figure 3. The maximum value that VCC can be adjusted to without exceeding the VCE(max)rating is (ignore other max ratings).
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Correct Answer:
B
Figure 4
-Refer to Figure 4. If RB = 100 k▲, VC is approximately
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Figure 7
-Refer to Figure 7. Assume a single problem accounts for the readings. From the readings, you can conclude that
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A 10 mV ac signal is applied to the base of a properly biased transistor with RC = 1.2 k▲ and re' = 36 ▲. The output ac voltage is
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Figure 1
-Refer to Figure 1. If VCC is increased to 18 V, IB will
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In a certain BJT, the collector current is 22.0 mA when the base current is 100 µA. The emitter current is
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A forward- biased npn transistor has a typical voltage drop from base to emitter of
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The base region of a BJT is heavily doped and wide compared to the other two regions.
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Figure 6 A phototransistor and its characteristic curve
-Refer to Figure 6. Assume you measure VOUT as 11 V. From this, you can conclude that the light intensity is approximately
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Figure 4
-Refer to Figure 4. If you wanted to change the transistor to a pnp type, you need to
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Figure 4
-Refer to Figure 4. The largest base resistor that will still saturate the transistor is approximately
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Figure 3 The transistor has the following ratings: PD(max)= 650 mW, VCE(max)= 40 V, and IC(max)= 200 mA.
-Refer to Fig 3. Assume VCC is lowered to 15 V. The transistor is
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Figure 4
-Refer to Figure 4. Assume RB = 22 k▲. The collector current will be approximately
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