A particle is in simple harmonic motion along the x axis. The amplitude of the motion is xm. When it is at x = x1, its kinetic energy is K = 5J and its potential energy (measured with U = 0 at x = 0) is U = 3J. When it is at x = -1/2xm, the kinetic and potential energies are:

A) K = 5J and U = 3J B) K = 5J and U = -3J C) K = 8J and U = 0 D) K = 0 and U = 8J E) K = 0 and U = -8J A) K = 5J and U = 3J B) K = 5J and U = -3J C) K = 8J and U = 0 D) K = 0 and U = 8J E) K = 0 and U = -8J

Exam 15: Oscillations

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A simple pendulum is suspended from the ceiling of an elevator. The elevator is accelerating upwards with acceleration a. The period of this pendulum, in terms of its length L, g and a is:

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Question 41

An oscillatory motion must be simple harmonic if:

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Question 42

A 0.25-kg block oscillates on the end of the spring with a spring constant of 200 N/m. If the system has an energy of 6.0 J, then the maximum speed of the block is:

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Question 43

A 0.25-kg block oscillates on the end of the spring with a spring constant of 200 N/m. If the system has an energy of 6.0 J, then the amplitude of the oscillation is:

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Question 44

A 0.20-kg object mass attached to a spring whose spring constant is 500 N/m executes simple harmonic motion. If its maximum speed is 5.0 m/s, the amplitude of its oscillation is:

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Question 45

A particle is in simple harmonic motion along the x axis. The amplitude of the motion is x_m. When it is at x = x₁, its kinetic energy is K = 5J and its potential energy (measured with U = 0 at x = 0) is U = 3J. When it is at x = -1/2x_m, the kinetic and potential energies are:

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Question 46

A particle is in simple harmonic motion with period T. At time t=0 it is halfway between the equilibrium point and an end point of its motion, travelling toward the end point. The next time it is at the same place is:

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Question 47

A particle moves back and forth along the x axis from x = -x_m to x = +x_m, in simple harmonic motion with period T. At time t = 0 it is at x = +x_m. When t = 0.75T:

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Question 48

The period of a simple pendulum is 1 s on Earth. When brought to a planet where g is one-tenth that on Earth, its period becomes:

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Question 49

A particle moves in simple harmonic motion according to x = 2cos(50t), where x is in meters and t is in seconds. Its maximum velocity in m/s is:

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Question 50

The displacement of an object oscillating on a spring is given by x(t) = x_mcos( $\omega$ t + $\phi$ ). If the object is initially displaced in the negative x direction and given a negative initial velocity, then the phase constant $\phi$ is between:

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Question 51

A 3-kg block, attached to a spring, executes simple harmonic motion according to x = 2cos(50t) where x is in meters and t is in seconds. The spring constant of the spring is:

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Question 52

A particle is in simple harmonic motion with period T. At time t = 0 it is at the equilibrium point. At which of the following times is it furthest from the equilibrium point?

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Question 53

An object attached to one end of a spring makes 20 vibrations in 10 seconds. Its frequency is:

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Question 54

The amplitude of any oscillator can be doubled by:

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Question 55

An oscillator is subjected to a damping force that is proportional to its velocity. A sinusoidal force is applied to it. After a long time:

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Question 56

An object on the end of a spring is set into oscillation by giving it an initial velocity while it is at its equilibrium position. In the first trial the initial velocity is v₀ and in the second it is 4v₀. In the second trial:

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Question 57

A block on a spring is subjected to an applied sinusoidal force AND to a damping force that is proportional to its velocity. The energy dissipated by damping is supplied by:

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Question 58

In simple harmonic motion, the restoring force must be proportional to the:

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Question 59

In simple harmonic motion, the magnitude of the acceleration is greatest when:

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Question 60

Showing 41 - 60 of 62

Exam 15: Oscillations

A simple pendulum is suspended from the ceiling of an elevator. The elevator is accelerating upwards with acceleration a. The period of this pendulum, in terms of its length L, g and a is:

An oscillatory motion must be simple harmonic if:

A 0.25-kg block oscillates on the end of the spring with a spring constant of 200 N/m. If the system has an energy of 6.0 J, then the maximum speed of the block is:

A 0.25-kg block oscillates on the end of the spring with a spring constant of 200 N/m. If the system has an energy of 6.0 J, then the amplitude of the oscillation is:

A 0.20-kg object mass attached to a spring whose spring constant is 500 N/m executes simple harmonic motion. If its maximum speed is 5.0 m/s, the amplitude of its oscillation is:

A particle is in simple harmonic motion along the x axis. The amplitude of the motion is xm. When it is at x = x1, its kinetic energy is K = 5J and its potential energy (measured with U = 0 at x = 0) is U = 3J. When it is at x = -1/2xm, the kinetic and potential energies are:

A particle is in simple harmonic motion with period T. At time t=0 it is halfway between the equilibrium point and an end point of its motion, travelling toward the end point. The next time it is at the same place is:

A particle moves back and forth along the x axis from x = -xm to x = +xm, in simple harmonic motion with period T. At time t = 0 it is at x = +xm. When t = 0.75T:

The period of a simple pendulum is 1 s on Earth. When brought to a planet where g is one-tenth that on Earth, its period becomes:

A particle moves in simple harmonic motion according to x = 2cos(50t), where x is in meters and t is in seconds. Its maximum velocity in m/s is:

The displacement of an object oscillating on a spring is given by x(t) = xmcos( ω \omega ω t + ϕ\phiϕ ). If the object is initially displaced in the negative x direction and given a negative initial velocity, then the phase constant ϕ\phiϕ is between:

A 3-kg block, attached to a spring, executes simple harmonic motion according to x = 2cos(50t) where x is in meters and t is in seconds. The spring constant of the spring is:

A particle is in simple harmonic motion with period T. At time t = 0 it is at the equilibrium point. At which of the following times is it furthest from the equilibrium point?

An object attached to one end of a spring makes 20 vibrations in 10 seconds. Its frequency is:

The amplitude of any oscillator can be doubled by:

An oscillator is subjected to a damping force that is proportional to its velocity. A sinusoidal force is applied to it. After a long time:

An object on the end of a spring is set into oscillation by giving it an initial velocity while it is at its equilibrium position. In the first trial the initial velocity is v0 and in the second it is 4v0. In the second trial:

A block on a spring is subjected to an applied sinusoidal force AND to a damping force that is proportional to its velocity. The energy dissipated by damping is supplied by:

In simple harmonic motion, the restoring force must be proportional to the:

In simple harmonic motion, the magnitude of the acceleration is greatest when:

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A particle is in simple harmonic motion along the x axis. The amplitude of the motion is x_m. When it is at x = x₁, its kinetic energy is K = 5J and its potential energy (measured with U = 0 at x = 0) is U = 3J. When it is at x = -1/2x_m, the kinetic and potential energies are:

A particle moves back and forth along the x axis from x = -x_m to x = +x_m, in simple harmonic motion with period T. At time t = 0 it is at x = +x_m. When t = 0.75T:

The displacement of an object oscillating on a spring is given by x(t) = x_mcos( $\omega$ t + $\phi$ ). If the object is initially displaced in the negative x direction and given a negative initial velocity, then the phase constant $\phi$ is between:

An object on the end of a spring is set into oscillation by giving it an initial velocity while it is at its equilibrium position. In the first trial the initial velocity is v₀ and in the second it is 4v₀. In the second trial: