Exam 13: Universal Gravitation

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Suppose the gravitational force of the Earth on a body was Suppose the gravitational force of the Earth on a body was   )What escape velocity v<sub>e</sub> would a body need to escape the gravitational field of the Earth? )What escape velocity ve would a body need to escape the gravitational field of the Earth?

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Knowing that Knowing that   At sea level and that R<sub>E</sub> = 6.37 × 10<sup>6</sup> m,we find that the value of g in   At a distance R<sub>E</sub> from the surface of the Earth is At sea level and that RE = 6.37 × 106 m,we find that the value of g in Knowing that   At sea level and that R<sub>E</sub> = 6.37 × 10<sup>6</sup> m,we find that the value of g in   At a distance R<sub>E</sub> from the surface of the Earth is At a distance RE from the surface of the Earth is

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A satellite revolves around the Earth in a circular orbit with a mechanical energy of A satellite revolves around the Earth in a circular orbit with a mechanical energy of   j.What is its kinetic energy? j.What is its kinetic energy?

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A satellite of mass m circles a planet of mass M and radius R in an orbit at a height 2R above the surface of the planet.What minimum energy is required to change the orbit to one for which the height of the satellite is 3R above the surface of the planet?

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The figure below shows a planet traveling in a counterclockwise direction on an elliptical path around a star located at one focus of the ellipse.When the planet is at point A, The figure below shows a planet traveling in a counterclockwise direction on an elliptical path around a star located at one focus of the ellipse.When the planet is at point A,

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A 50-kg satellite circles the Earth in an orbit with a period of 120 min.What minimum energy is required to change the orbit to another circular orbit with a period of 180 min? (Earth: radius = 6.4 × 106 m,mass = 6.0 × 1024 kg)

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Calculate the Earth's angular momentum in the approximation that treats the Earth's orbit around the sun as a circle.(MSun = 1.99 × 1030 kg;T = 3.156 × 107 s;ME = 5.98 × 1024 kg. )

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