Exam 41: Quantum Mechanics

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A particle is in the first excited state of a one-dimensional box of length 1.0 m. What is the minimum value of its momentum (in kg ⋅ m/s)?

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The ground state energy of a harmonic oscillator is

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If the interaction of a particle with its environment restricts the particle to a finite region of space, the result is the quantization of ____ of the particle.

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A particle is in the second excited state of a one-dimensional box of length 1.0 m. What is its momentum (in kg ⋅ m/s)?

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The graph below represents a wave function ψ(x) for a particle confined to −4.00 m ≤ x ≤ +4.00 m. The magnitude of the normalization constant A is The graph below represents a wave function ψ(x) for a particle confined to −4.00 m ≤ x ≤ +4.00 m. The magnitude of the normalization constant A is

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What is the quantum number n of a particle of mass m confined to a one-dimensional box of length L when its momentum is 4h/L?

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A particle in a finite potential well has energy E, as shown below. A particle in a finite potential well has energy E, as shown below.   The wave function in region II where x > 0 has the form ψ<sub>II</sub> = The wave function in region II where x > 0 has the form ψII =

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The graph below represents a wave function ψ(x) for a particle confined to −2.00 m ≤ x ≤ +2.00 m. The value of the normalization constant A may be The graph below represents a wave function ψ(x) for a particle confined to −2.00 m ≤ x ≤ +2.00 m. The value of the normalization constant A may be

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The wave function for a particle confined to a one-dimensional box located between x = 0 and x = L is given by Ψ(x) = A sin (nπx/L) + B cos (nπx/L) . The constants A and B are determined to be

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The wave function for a particle in a box of length L is given by The wave function for a particle in a box of length L is given by   . If the box extends from x = 0 to x = L, What is the probability of finding the particle between x = 0.60 L and x = 0.70 L? . If the box extends from x = 0 to x = L, What is the probability of finding the particle between x = 0.60 L and x = 0.70 L?

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The wave function ψ(x) of a particle confined to 0 ≤ x ≤ L is given by ψ(x) = Ax. ψ(x) = 0 for x < 0 and x > L. When the wave function is normalized, the probability density at coordinate x has the value

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A particle in a finite potential well has energy E, as shown below. A particle in a finite potential well has energy E, as shown below.   The wave function in region III where x > L has the form ψ<sub>III</sub> = The wave function in region III where x > L has the form ψIII =

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Classically, the concept of "tunneling" is impossible. Why?

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