Exam 3: Bioenergetics, Enzymes and Metabolism
Exam 1: Introduction to the Study of Cell and Molecular Biology100 Questions
Exam 2: The Chemical Basis of Life87 Questions
Exam 3: Bioenergetics, Enzymes and Metabolism80 Questions
Exam 4: The Structure and Function of the Plasma Membrane99 Questions
Exam 5: Aerobic Respiration and the Mitochondrion99 Questions
Exam 6: Photosynthesis and the Chloroplast100 Questions
Exam 7: Interactions Between Cells and Their Environment103 Questions
Exam 8: Cytoplasmic Membrane Systems: Structure, Function, and Membrane Trafficking159 Questions
Exam 9: The Cytoskeleton and Cell Motility107 Questions
Exam 10: The Nature of the Gene and the Genome97 Questions
Exam 11: Gene Expression: From Transcription to Translation101 Questions
Exam 12: Control of Gene Expression100 Questions
Exam 13: Dna Replication and Repair98 Questions
Exam 14: Cellular Reproduction103 Questions
Exam 15: Cell Signaling and Signal Transduction: Communication Between Cells109 Questions
Exam 16: Cancer98 Questions
Exam 17: The Immune Response109 Questions
Exam 18: Techniques in Cell and Molecular Biology112 Questions
Select questions type
You are observing an enzyme driven reaction. You add chemical X, which inhibits the reaction. If you add more substrate, the reaction rate approaches the Vmax of the uninhibited reaction. Furthermore, the structure of X is similar to the natural substrate. What kind of inhibitor is X?
(Multiple Choice)
4.8/5
(76)
What kind of inhibitor binds very tightly to an enzyme often forming a covalent bond with an amino acid in the active site?
(Multiple Choice)
4.8/5
(104)
Which reaction below might be a suitable coupled reaction for the reaction
A + B -> C + D ( G = -8.7 kcal/mole)?
(Multiple Choice)
4.9/5
(70)
Doubling the concentration of enzyme will ______ the Vmax and _____ the KM.
(Multiple Choice)
4.9/5
(82)
Phosphorylation of glucose by hexokinase and phosphofructokinase is advantageous because:
(Multiple Choice)
4.8/5
(88)
2-[18F] fluoro-2-deoxy-D-glucose (FDG)acts as a competitive inhibitor of ______________.
(Multiple Choice)
4.9/5
(93)
Advantages derived from the use of a circadian oscillator regulatory mechanism include:
(Multiple Choice)
4.8/5
(86)
Other than controlling the synthesis of photosynthesis-related proteins and other factors, which process has been observed in plants to be regulated by the circadian oscillator?
(Multiple Choice)
4.8/5
(75)
Glycolysis occurs in the ________; the Krebs (TCA)cycle occurs in the ______ of eukaryotes and the ______ of prokaryotes.
(Multiple Choice)
4.8/5
(86)
Why has the pharmaceutical industry drastically cut resources devoted to the development of new antibiotics? (Select all correct choices)
(Multiple Choice)
4.7/5
(85)
Which statements accurately describe the metabolism and detection of tumor cells? (Select all that are correct choices)
(Multiple Choice)
4.7/5
(78)
What is the activity of dehydrogenase enzymes destined to provide in a cell capable of respiration?
(Multiple Choice)
4.8/5
(74)
Entropy is associated with the _________ movement of particles of matter, which because they are ________ cannot accomplish a directed work process.
(Multiple Choice)
4.8/5
(87)
If mice are maintained on very strict diets with reduced caloric intake, what happens to their life span as compared to littermates fed diets with normal caloric content and why? (Select all correct responses)
(Multiple Choice)
4.9/5
(74)
Who was the first scientist to determine the structure and composition of an enzyme?
(Multiple Choice)
4.9/5
(89)
Tumor imaging can exploit soft tissue differences between normal and malignant cells by using all of the following EXCEPT:
(Multiple Choice)
4.7/5
(75)
A pharmacist is looking for a drug which will prevent an enzyme from working by binding to it as an inhibitor. Which of the inhibitors listed as choices will prove most effective, given equality in other considerations such as solubility, toxicity and stability?
(Multiple Choice)
4.9/5
(82)
Showing 21 - 40 of 80
Filters
- Essay(0)
- Multiple Choice(0)
- Short Answer(0)
- True False(0)
- Matching(0)