Exam 8: Trigonometric Identities and Equations

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Solve the equation for solutions in the interval [0 [0∘,360∘)\left[ 0 ^ { \circ } , 360 ^ { \circ } \right) ). Round to the nearest degree. - cos⁡2θ=32\cos 2 \theta = \frac { \sqrt { 3 } } { 2 }

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Use the fundamental identities to find the value of the trigonometric function. -Find sin⁡θ\sin \theta if cos⁡θ=23\cos \theta = \frac { 2 } { 3 } and θ\theta is in quadrant IV.

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Use a calculator to give the value to the nearest degree. - θ=tan⁡−1(2.2460)\theta = \tan ^ { - 1 } ( 2.2460 )

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Use a calculator to give the value to the nearest degree. - θ=cos⁡−1(0.8910)\theta = \cos ^ { - 1 } ( 0.8910 )

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Express the function as a trigonometric function of x. - cos⁡4x\cos 4 \mathrm { x }

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Use an identity to write the expression as a single trigonometric function or as a single number. - 1+cos⁡22∘1−cos⁡22∘\sqrt { \frac { 1 + \cos 22 ^ { \circ } } { 1 - \cos 22 ^ { \circ } } }

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Verify that each equation is an identity. - tan⁡θ⋅csc⁡θ=sec⁡θ\tan \theta \cdot \csc \theta = \sec \theta

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Use identities to write the expression as a single function of x or θ\theta - sin⁡(x+45∘)\sin \left( x + 45 ^ { \circ } \right)

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Solve the equation (x in radians and θ\boldsymbol { \theta } in degrees) for all exact solutions where appropriate. Round approximate answers in radians to four decimal places and approximate answers in degrees to the nearest tenth. - 2sin⁡2x+sin⁡x=12 \sin ^ { 2 } x + \sin x = 1

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Solve the equation for solutions in the interval [0 [0∘,360∘)\left[ 0 ^ { \circ } , 360 ^ { \circ } \right) ). Round to the nearest degree. - 3sec⁡2θ=2\sqrt { 3 } \sec 2 \theta = 2

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Factor the trigonometric expression and simplify. - 1−2sin⁡2x+sin⁡4x1 - 2 \sin ^ { 2 } x + \sin ^ { 4 } x

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Graph the inverse circular function. - y=cos⁡−1xy=\cos ^{-1} x  Graph the inverse circular function. - y=\cos ^{-1} x

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The statement tan-1(tan x) = x for all real numbers in the interval - −π2<x<π2- \frac { \pi } { 2 } < x < \frac { \pi } { 2 }

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Use Identities to find the exact value. - cos⁡(−75∘)\cos \left( - 75 ^ { \circ } \right)

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Solve the equation for solutions over the interval [0, [0,2π)[ 0,2 \pi ) ). Write solutions as exact values or to four decimal places, as appropriate. -The range r\mathrm { r } of a projectile is given by r=132v2sin⁡2θ, r = \frac { 1 } { 32 } v ^ { 2 } \sin 2 \theta \text {, } where v\mathrm { v } is the initial velocity and θ\theta is the angle of elevation. If r\mathrm { r } is to be 3000ft3000 \mathrm { ft } and v=4000ft/sec\mathrm { v } = 4000 \mathrm { ft } / \mathrm { sec } , what must the angle of elevation be? Give your answer in degrees to the nearest hundredth.

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Graph the inverse circular function. - y=12arccot⁡xy = \frac { 1 } { 2 } \operatorname { arccot } x  Graph the inverse circular function. - y = \frac { 1 } { 2 } \operatorname { arccot } x

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Use the cofunction identities to find an angle θ\theta that makes the statement true. - tan⁡(2θ−140∘)=cot⁡(θ+5∘)\tan \left( 2 \theta - 140 ^ { \circ } \right) = \cot \left( \theta + 5 ^ { \circ } \right)

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Use the fundamental identities to simplify the expression. - cos⁡(−x)cos⁡x−sin⁡(−x)sin⁡x\cos ( - x ) \cos x - \sin ( - x ) \sin x

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Determine all solutions of the equation in radians. -Find cos⁡θ2\cos \frac { \theta } { 2 } , given that cos⁡θ=−35\cos \theta = - \frac { 3 } { 5 } and θ\theta terminates in 90∘<θ<180∘90 ^ { \circ } < \theta < 180 ^ { \circ } .

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Use the fundamental identities to simplify the expression. - cos⁡x(csc⁡x−sec⁡x)−cot⁡x\cos x ( \csc x - \sec x ) - \cot x

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