Solve the Equation for Solutions Over the Interval [0 $[ 0,2 \pi )$

Solve the equation for solutions over the interval [0, $[ 0,2 \pi )$ ) . Write solutions as exact values or to four decimal places, as
appropriate.
-The range $\mathrm { r }$ of a projectile is given by
$$r = \frac { 1 } { 32 } v ^ { 2 } \sin 2 \theta \text {, }$$
where $\mathrm { v }$ is the initial velocity and $\theta$ is the angle of elevation. If $\mathrm { r }$ is to be $3000 \mathrm { ft }$ and $\mathrm { v } = 4000 \mathrm { ft } / \mathrm { sec }$ , what must the angle of elevation be? Give your answer in degrees to the nearest hundredth.

A) $0.24 ^ { \circ }$
B) $89.83 ^ { \circ }$
C) $0.34 ^ { \circ }$
D) $0.17 ^ { \circ }$

Correct Answer:

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