Exam 8: Trigonometric Identities and Equations

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Factor the trigonometric expression and simplify. - sec⁡4x−2sec⁡2xtan⁡2x+tan⁡4x\sec ^ { 4 } x - 2 \sec ^ { 2 } x \tan ^ { 2 } x + \tan ^ { 4 } x

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Use a calculator to give the value to the nearest degree. - θ=sin⁡−1(−0.4848)\theta = \sin ^ { - 1 } ( - 0.4848 )

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Perform the transformation. -Write csc⁡x\csc x in terms of sec⁡x\sec x .

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Use the cofunction identities to find an angle θ\theta that makes the statement true. - cot⁡5θ=tan⁡4θ\cot 5 \theta = \tan 4 \theta

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Use a sum or difference identity to find the exact value. - tan⁡100∘−tan⁡(−20)∘1+tan⁡100∘tan⁡(−20)∘\frac { \tan 100 ^ { \circ } - \tan ( - 20 ) ^ { \circ } } { 1 + \tan 100 ^ { \circ } \tan ( - 20 ) ^ { \circ } }

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Use a graphing calculator to make a conjecture as to whether each equation is an identity. - sin⁡x2cos⁡x2=sin⁡x2\sin \frac { x } { 2 } \cos \frac { x } { 2 } = \frac { \sin x } { 2 }

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Complete the sentence so the result is an identity. Let x be any real number. - cos⁡x=(cot⁡x)(□)\cos x = ( \cot x ) ( \square )

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Solve the problem. - sec⁡2u2=2sec⁡usec⁡u+1\sec ^ { 2 } \frac { \mathrm { u } } { 2 } = \frac { 2 \sec \mathrm { u } } { \sec \mathrm { u } + 1 }

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Solve the equation for exact solutions. - 4cos⁡−1x=π4 \cos ^ { - 1 } x = \pi

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Use identities to find the indicated value for each angle measure. - sin⁡θ=2107,tan⁡θ<0\sin \theta = \frac { 2 \sqrt { 10 } } { 7 } , \tan \theta < 0 \quad Find sin⁡(2θ)\sin ( 2 \theta )

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Give the exact value of the expression. - csc⁡(csc⁡−1−2)\csc \left( \csc ^ { - 1 } - 2 \right)

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Give the degree measure of θ\theta - θ=sin⁡−1(22)\theta = \sin ^ { - 1 } \left( \frac { \sqrt { 2 } } { 2 } \right)

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Solve the equation for exact solutions over the interval [0, 2 [0,2π)[ 0,2 \pi ) - sin⁡2x+sin⁡x=0\sin ^ { 2 } x + \sin x = 0

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Verify that each equation is an identity. - (1−cos⁡x)(1+cos⁡x)=sin⁡2x( 1 - \cos x ) ( 1 + \cos x ) = \sin ^ { 2 } x

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Solve the equation in the interval [0∘,360∘)\left[ 0 ^ { \circ } , 360 ^ { \circ } \right) ). Give solutions to the nearest tenth, if necessary. - sin⁡2θ−sin⁡θ−12=0\sin ^ { 2 } \theta - \sin \theta - 12 = 0

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Give the degree measure of θ\theta - θ=arcsin⁡(−1)\theta = \arcsin ( - 1 )

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Give the exact value of the expression. - cos⁡(2arcsin⁡14)\cos \left( 2 \arcsin \frac { 1 } { 4 } \right)

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Solve the equation for exact solutions. - sin⁡−1x+cos⁡−1(−12)=π\sin ^ { - 1 } x + \cos ^ { - 1 } \left( - \frac { 1 } { 2 } \right) = \pi

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Verify that the equation is an identity. - sin⁡(x+π2)=cos⁡x\sin \left( x + \frac { \pi } { 2 } \right) = \cos x

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Use an identity to write the expression as a single trigonometric function or as a single number. - sin⁡28∘1+cos⁡28∘\frac { \sin 28 ^ { \circ } } { 1 + \cos 28 ^ { \circ } }

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