Question 1

If two events A and B are independent,the P(A and B)= P(A)+ P(B).

Accepted Answer

A) True 
 B)False

Question 2

A small chi-squared test statistic in a goodness-of-fit test supports the null hypothesis.

Accepted Answer

A) True 
 B)False

Question 3

A chi-squared test of a contingency table is applied to a contingency table with 4 rows and 4 columns for two qualitative variables.The degrees of freedom for this test must be 9.

Accepted Answer

A) True 
 B)False

Question 4

The Chairman of a committee has recently circulated pamphlets among the members,attempting to convince them that pension benefits should be the primary issue.A subsequent survey revealed the following breakdown of the members according to the plant at which they worked and the issue that they felt should be supported as the primary one.
 $$\begin{array}{l}
\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\ \text { Issues }\
\begin{array} { | l | c c c | } 
\hline \text { Plant Location } & \text { Very Interesting } & \text { Fairly Interesting } & \text { Nat Interesting } \
\hline \text { New Mexica } & 60 & 62 & 78 \
\text { Utah } & 70 & 56 & 74
\end{array}
\end{array}$$ Do the data indicate at the 5% significant level that there are differences between the two plants regarding which issue should be the primary one?

Accepted Answer

H₀: Plant location and work i

Question 5

If the expected frequency of a cell is less than 5,you should combine cells of the table.

Accepted Answer

A) True 
 B)False

Question 6

If the expected frequency of a cell is less than 5,you should increase the significance level.

Accepted Answer

A) True 
 B)False

Question 7

A(n)____________________ experiment is like a binomial experiment except it contains two or more categories.

Accepted Answer

The answer of A(n)____________________ experiment is like a binomial experiment...

Question 8

When we test for differences between two populations of nominal data with two categories,we can use only one technique,namely,the chi-squared test of a contingency table.

Accepted Answer

A) True 
 B)False

Question 9

Suppose the value of your chi-squared test statistic in a goodness-of-fit test is equal to 0.What do you conclude?

Accepted Answer

A)  Reject H0.Conclude that at least one proportion is not equal to its specified value. 
B)  Fail to reject H0.Not enough evidence to say the proportions are different from what is listed in H0. 
C)  Not enough information;need the degrees of freedom for the test. 
D)  None of these choices. 
A)  Reject H0.Conclude that at least one proportion is not equal to its specified value. 
B)  Fail to reject H0.Not enough evidence to say the proportions are different from what is listed in H0. 
C)  Not enough information;need the degrees of freedom for the test. 
D)  None of these choices.

Question 10

A chi-squared test of a contingency table with 4 rows and 5 columns shows that the value of the test statistic is 22.18.Using a chi-squared table,the most accurate statement that can be made is:

Accepted Answer

A)  p-value is greater than 0.05 
B)  p-value is smaller than 0.025 
C)  p-value is greater than 0.025 but smaller than 0.05 
D)  p-value is greater than 0.10 
A)  p-value is greater than 0.05 
B)  p-value is smaller than 0.025 
C)  p-value is greater than 0.025 but smaller than 0.05 
D)  p-value is greater than 0.10

Question 11

If we want to perform a two-tail test for differences between two populations of nominal data with exactly two categories,we can employ either the z-test of p1 -p2,or the chi-squared test of a contingency table.

Accepted Answer

A) True 
 B)False

Question 12

A chi-squared test of a contingency table can be used to infer that differences exist between ____________________ populations of nominal variables.

Accepted Answer

The answer of A chi-squared test of a contingency table...

Question 13

To test for normality,the ____________________ hypothesis specifies probabilities of certain intervals within the normal distribution.

Accepted Answer

The answer of To test for normality,the ____________________ hypothesis specifies...

Question 14

If you want to compare two populations that each have two categories,which test(s)can you use?

Accepted Answer

You can use a z-test

If two events A and B are independent,the P(A and B)= P(A)+ P(B).

A small chi-squared test statistic in a goodness-of-fit test supports the null hypothesis.

A chi-squared test of a contingency table is applied to a contingency table with 4 rows and 4 columns for two qualitative variables.The degrees of freedom for this test must be 9.

If the expected frequency of a cell is less than 5,you should combine cells of the table.

If the expected frequency of a cell is less than 5,you should increase the significance level.

A(n)____________________ experiment is like a binomial experiment except it contains two or more categories.

When we test for differences between two populations of nominal data with two categories,we can use only one technique,namely,the chi-squared test of a contingency table.

Suppose the value of your chi-squared test statistic in a goodness-of-fit test is equal to 0.What do you conclude?

A chi-squared test of a contingency table with 4 rows and 5 columns shows that the value of the test statistic is 22.18.Using a chi-squared table,the most accurate statement that can be made is:

If we want to perform a two-tail test for differences between two populations of nominal data with exactly two categories,we can employ either the z-test of p₁ -p₂,or the chi-squared test of a contingency table.

A chi-squared test of a contingency table can be used to infer that differences exist between ____________________ populations of nominal variables.

To test for normality,the ____________________ hypothesis specifies probabilities of certain intervals within the normal distribution.

If you want to compare two populations that each have two categories,which test(s)can you use?

What Is Statistics

Graphical Descriptive Techniques I

Graphical Descriptive Techniques II

A: Numerical Descriptive Techniques

B: Numerical Descriptive Techniques

C: Numerical Descriptive Techniques

Data Collection and Sampling

Probability

A: Random Variables and Discrete Probability Distributions

B: Random Variables and Discrete Probability Distributions

Continuous Probability Distributions

Sampling Distributions

Introduction to Estimation

Introduction to Hypothesis Testing

Inference About a Population

Inference About Comparing Two Populations

Analysis of Variance

A: Simple Linear Regression and Correlation

B: Simple Linear Regression and Correlation

Multiple Regression

Model Building

Nonparametric Statistics

Time-Series Analysis and Forecasting

Statistical Process Control

Decision Analysis

Conclusion

Filters

Exam 15: Chi-Squared Tests

If two events A and B are independent,the P(A and B)= P(A)+ P(B).

A small chi-squared test statistic in a goodness-of-fit test supports the null hypothesis.

A chi-squared test of a contingency table is applied to a contingency table with 4 rows and 4 columns for two qualitative variables.The degrees of freedom for this test must be 9.

If the expected frequency of a cell is less than 5,you should combine cells of the table.

If the expected frequency of a cell is less than 5,you should increase the significance level.

A(n)____________________ experiment is like a binomial experiment except it contains two or more categories.

When we test for differences between two populations of nominal data with two categories,we can use only one technique,namely,the chi-squared test of a contingency table.

Suppose the value of your chi-squared test statistic in a goodness-of-fit test is equal to 0.What do you conclude?

A chi-squared test of a contingency table with 4 rows and 5 columns shows that the value of the test statistic is 22.18.Using a chi-squared table,the most accurate statement that can be made is:

If we want to perform a two-tail test for differences between two populations of nominal data with exactly two categories,we can employ either the z-test of p1 -p2,or the chi-squared test of a contingency table.

A chi-squared test of a contingency table can be used to infer that differences exist between ____________________ populations of nominal variables.

To test for normality,the ____________________ hypothesis specifies probabilities of certain intervals within the normal distribution.

If you want to compare two populations that each have two categories,which test(s)can you use?

What Is Statistics

Graphical Descriptive Techniques I

Graphical Descriptive Techniques II

A: Numerical Descriptive Techniques

B: Numerical Descriptive Techniques

C: Numerical Descriptive Techniques

Data Collection and Sampling

Probability

A: Random Variables and Discrete Probability Distributions

B: Random Variables and Discrete Probability Distributions

Continuous Probability Distributions

Sampling Distributions

Introduction to Estimation

Introduction to Hypothesis Testing

Inference About a Population

Inference About Comparing Two Populations

Analysis of Variance

A: Simple Linear Regression and Correlation

B: Simple Linear Regression and Correlation

Multiple Regression

Model Building

Nonparametric Statistics

Time-Series Analysis and Forecasting

Statistical Process Control

Decision Analysis

Conclusion

Filters

If we want to perform a two-tail test for differences between two populations of nominal data with exactly two categories,we can employ either the z-test of p₁ -p₂,or the chi-squared test of a contingency table.