Question 1

The squared difference between the observed and expected frequencies should be large if there is a significant difference between the proportions.

Accepted Answer

A) True 
 B)False

Question 2

If you reject H0 in a test of a contingency table,you conclude that based on your data:

Accepted Answer

A)  The two nominal variables are independent. 
B)  The two nominal variables are equal. 
C)  The two nominal variables have the same proportions listed in H0. 
D)  None of these choices. 
A)  The two nominal variables are independent. 
B)  The two nominal variables are equal. 
C)  The two nominal variables have the same proportions listed in H0. 
D)  None of these choices.

Question 3

Seat Belts
A study was conducted to determine whether the use of seat belts in vehicles depends on whether or not a child was present in the car.A sample of 1,000 people treated for injuries sustained from vehicle accidents was obtained,and each person was classified according to (1)child present (yes/no)and (2)seat belt usage (worn or not worn)during the accident.The data are shown in the table below.
   $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $Child present in car $$\begin{array} { | l | c c | } 
\hline \text { Seat Belts } & \text { NO } & \text { YES } \
\hline \text { Worm } & 83 & 200 \
\text { Not Worn } & 337 & 380 \
\hline
\end{array}$$
-{Seat Belts Narrative} Calculate the value of the test statistic.

Accepted Answer

@#LAT-DLM&²

Question 4

A large value of the chi-squared test statistic in a test of normality means you reject H0 and conclude that the data ____________________ (do/do not)come from a normal distribution.

Accepted Answer

Question 5

If the expected frequencies and the observed frequencies are quite different,you are likely to ____________________ the null hypothesis.

Accepted Answer

The answer of If the expected frequencies and the observed...

Question 6

If each element in a population is classified into one and only one of several categories,the population is:

Accepted Answer

A)  normal. 
B)  multinomial. 
C)  chi-squared. 
D)  None of these choices. 
A)  normal. 
B)  multinomial. 
C)  chi-squared. 
D)  None of these choices.

Question 7

A chi-squared goodness-of-fit test is always conducted as a(n):

Accepted Answer

A)  lower-tail test. 
B)  upper-tail test. 
C)  two-tail test. 
D)  All of these choices are true. 
A)  lower-tail test. 
B)  upper-tail test. 
C)  two-tail test. 
D)  All of these choices are true.

Question 8

A chi-squared test of a contingency table with 6 degrees of freedom results in a test statistic of 13.25.Using the chi-squared table,the most accurate statement that can be made about the p-value for this test is that p-value is greater than .025 but smaller than .05.

Accepted Answer

A) True 
 B)False

Question 9

The alternative hypothesis of a goodness-of-fit test states that ____________________ of the proportions is not equal to its value specified in H0.

Accepted Answer

Question 10

A chi-squared test is used to describe a population of nominal data.

Accepted Answer

A) True 
 B)False

Question 11

To analyze the relationship between two nominal variables,use a(n)____________________ test of a(n)____________________.

Accepted Answer

chi-squared;continge

Question 12

Student Absenteeism
Consider a multinomial experiment involving n = 200 students of a large high school.The attendance department recorded the number of students who were absent during the weekdays.The null hypothesis to be tested is: HS1U1B10S1U1B0: pS1U1B11S1U1B0 = .10,pS1U1B12S1U1B0 = .25,pS1U1B13S1U1B0 = .30,pS1U1B14S1U1B0 = .20,pS1U1B15S1U1B0 = .15.
-{Student Absenteeism Narrative} Test the hypothesis at the 5% level of significance with the following frequencies:
 $$\begin{array} { | l | c c c c c | } 
\hline \text { Day of the Week } & \text { Mon. } & \text { Tues. } & \text { Wed. } & \text { Thurs. } & \text { Fri } \
\hline \text { Number Absent } & 16 & 44 & 56 & 48 & 36 \
\hline
\end{array}$$

Accepted Answer

Rejection region: @#LAT-DLM&² > @#LAT-DLM&^2<

Question 13

Suppose that a random sample of 150 observations was drawn from a population.After calculating the mean and standard deviation,each observation was standardized and the number of observations in each of the intervals below was counted.Can we infer at the 5% significance level that the data were drawn from a normal population?
 $$\begin{array} { | l | c |} 
\hline \text { Intervals } & \text { Frequency } \
\hline Z \leq - 1.5 & 15 \
- 1.5  1.5 & 13 \
\hline
\end{array}$$

Accepted Answer

H₀: p₁ = .0668,p

Question 14

Seat Belts
A study was conducted to determine whether the use of seat belts in vehicles depends on whether or not a child was present in the car.A sample of 1,000 people treated for injuries sustained from vehicle accidents was obtained,and each person was classified according to (1)child present (yes/no)and (2)seat belt usage (worn or not worn)during the accident.The data are shown in the table below.
   $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $Child present in car $$\begin{array} { | l | c c | } 
\hline \text { Seat Belts } & \text { NO } & \text { YES } \
\hline \text { Worm } & 83 & 200 \
\text { Not Worn } & 337 & 380 \
\hline
\end{array}$$
-{Seat Belts Narrative} At 5% level of significance,what is the critical value of the test statistic?

Accepted Answer

The answer of Seat Belts
A study was conducted to determine...

Question 15

Seat Belts
A study was conducted to determine whether the use of seat belts in vehicles depends on whether or not a child was present in the car.A sample of 1,000 people treated for injuries sustained from vehicle accidents was obtained,and each person was classified according to (1)child present (yes/no)and (2)seat belt usage (worn or not worn)during the accident.The data are shown in the table below.
   $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $Child present in car $$\begin{array} { | l | c c | } 
\hline \text { Seat Belts } & \text { NO } & \text { YES } \
\hline \text { Worm } & 83 & 200 \
\text { Not Worn } & 337 & 380 \
\hline
\end{array}$$
-{Seat Belts Narrative} Prepare the table of expected values.

Accepted Answer

\[\begin{array}{l}
\quad\quad\quad\quad\

Question 16

If you want to describe a population with two categories,you can use a(n)____________________ test of p or the chi-squared goodness-of-fit test.

Accepted Answer

The answer of If you want to describe a population...

Question 17

If we use the $\chi$2 goodness-of-fit to test for the differences among 4 proportions,the degrees of freedom is equal to:

Accepted Answer

A)  3 
B)  4 
C)  5 
D)  None of these choices. 
A)  3 
B)  4 
C)  5 
D)  None of these choices.

Question 18

To produce expected values for a test of a contingency table,you multiply estimated joint probabilities for each cell by the total sample size,n.

Accepted Answer

A) True 
 B)False

Question 19

A chi-squared goodness-of-fit test is always a two-tailed test.

Accepted Answer

A) True 
 B)False

Question 20

To determine the critical values in the chi-squared distribution table,you need to know the:

Accepted Answer

A)  sample size. 
B)  degrees of freedom 
C)  probability of Type II error. 
D)  All of these choices are true. 
A)  sample size. 
B)  degrees of freedom 
C)  probability of Type II error. 
D)  All of these choices are true.

Exam 15: Chi-Squared Tests

The squared difference between the observed and expected frequencies should be large if there is a significant difference between the proportions.

If you reject H0 in a test of a contingency table,you conclude that based on your data:

A large value of the chi-squared test statistic in a test of normality means you reject H0 and conclude that the data ____________________ (do/do not)come from a normal distribution.

If the expected frequencies and the observed frequencies are quite different,you are likely to ____________________ the null hypothesis.

If each element in a population is classified into one and only one of several categories,the population is:

A chi-squared goodness-of-fit test is always conducted as a(n):

A chi-squared test of a contingency table with 6 degrees of freedom results in a test statistic of 13.25.Using the chi-squared table,the most accurate statement that can be made about the p-value for this test is that p-value is greater than .025 but smaller than .05.

The alternative hypothesis of a goodness-of-fit test states that ____________________ of the proportions is not equal to its value specified in H0.

A chi-squared test is used to describe a population of nominal data.

To analyze the relationship between two nominal variables,use a(n)____________________ test of a(n)____________________.

If you want to describe a population with two categories,you can use a(n)____________________ test of p or the chi-squared goodness-of-fit test.

If we use the χ\chiχ 2 goodness-of-fit to test for the differences among 4 proportions,the degrees of freedom is equal to:

To produce expected values for a test of a contingency table,you multiply estimated joint probabilities for each cell by the total sample size,n.

A chi-squared goodness-of-fit test is always a two-tailed test.

To determine the critical values in the chi-squared distribution table,you need to know the:

What Is Statistics

Graphical Descriptive Techniques I

Graphical Descriptive Techniques II

A: Numerical Descriptive Techniques

B: Numerical Descriptive Techniques

C: Numerical Descriptive Techniques

Data Collection and Sampling

Probability

A: Random Variables and Discrete Probability Distributions

B: Random Variables and Discrete Probability Distributions

Continuous Probability Distributions

Sampling Distributions

Introduction to Estimation

Introduction to Hypothesis Testing

Inference About a Population

Inference About Comparing Two Populations

Analysis of Variance

A: Simple Linear Regression and Correlation

B: Simple Linear Regression and Correlation

Multiple Regression

Model Building

Nonparametric Statistics

Time-Series Analysis and Forecasting

Statistical Process Control

Decision Analysis

Conclusion

Filters

If you reject H₀ in a test of a contingency table,you conclude that based on your data:

A large value of the chi-squared test statistic in a test of normality means you reject H₀ and conclude that the data ____________________ (do/do not)come from a normal distribution.

The alternative hypothesis of a goodness-of-fit test states that ____________________ of the proportions is not equal to its value specified in H₀.

To analyze the relationship between two nominal variables,use a(n) test of a(n).

If we use the $\chi$ ² goodness-of-fit to test for the differences among 4 proportions,the degrees of freedom is equal to: