Question 1

All of the expected frequencies in a chi-squared goodness-of-fit test must be equal to each other.

Accepted Answer

A) True 
 B)False

Question 2

In a goodness-of-fit test,H0 lists specific values for proportions and the test of a contingency table does not.

Accepted Answer

A) True 
 B)False

Question 3

If you want to describe a population with more than two categories,which test(s)can you use?

Accepted Answer

You can us

Question 4

The only way the chi-squared test statistic can be zero is if the observed frequencies are all exactly the same as the expected frequencies.

Accepted Answer

A) True 
 B)False

Question 5

Seat Belts
A study was conducted to determine whether the use of seat belts in vehicles depends on whether or not a child was present in the car.A sample of 1,000 people treated for injuries sustained from vehicle accidents was obtained,and each person was classified according to (1)child present (yes/no)and (2)seat belt usage (worn or not worn)during the accident.The data are shown in the table below.
   $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $ $\quad $Child present in car $$\begin{array} { | l | c c | } 
\hline \text { Seat Belts } & \text { NO } & \text { YES } \
\hline \text { Worm } & 83 & 200 \
\text { Not Worn } & 337 & 380 \
\hline
\end{array}$$
-{Seat Belts Narrative} At 5% level of significance,what is the proper conclusion?

Accepted Answer

Since @#LAT-DLM&² = 26.016 > 3.8415,we

Question 6

If you want to compare two populations that each have more than two categories,which test(s)can you use?

Accepted Answer

You can use a chi-sq

Question 7

If we want to test for differences between two populations of nominal data with exactly two categories,we can employ either the z-test of p1 - p2,or the chi-squared test of a contingency table.

Accepted Answer

A) True 
 B)False

Question 8

Mathematical statisticians have established that if we square the value of z,the test statistic for the test of one proportion p,we produce the$\chi$2 statistic.That is,z2 = $\chi$2.

Accepted Answer

A) True 
 B)False

Question 9

In conducting a chi-squared goodness-of-fit test,an essential condition is that all expected frequencies are at least five.

Accepted Answer

A) True 
 B)False

Question 10

In a goodness-of-fit test,the null hypothesis states that the data came from a normally distributed population.The researcher estimated the population mean and population standard deviation from a sample of 300 observations.In addition,the researcher used 6 standardized intervals to test for normality.Using a 2.5% level of significance,the critical value for this test is 14.4494.

Accepted Answer

A) True 
 B)False

Question 11

Consider a multinomial experiment involving 100 trials and 3 categories (cells).The observed frequencies resulting from the experiment are shown in the accompanying table.
 $$\begin{array} { | l | c c c | } 
\hline \text { Category } & 1 & 2 & 3 \
\hline \text { Frequency } & 38 & 35 & 27 \
\hline
\end{array}$$ Use the 5% significance level to test the hypotheses H0: p1 = .45,p2 = .30,p3 = .25 vs.H1: At least one proportion differs from their specified values.

Accepted Answer

Rejection region: @#LAT-DLM&² > @#LAT-DLM&^2<

Question 12

If you want to describe a population with more than two categories,you can use a chi-squared ____________________ test.

Accepted Answer

goodness-o

Question 13

What statistic do we get when we square the value of z?

Accepted Answer

You get a

Question 14

To determine whether a single coin is fair,the coin was tossed 200 times.The observed frequencies with which each of the two sides of the coin turned up are recorded as 112 heads and 88 tails.Is the coin fair? Use a=.05

Accepted Answer

H₀: p₁ = .50,p

Question 15

Which of the following tests does not use the chi-squared distribution?

Accepted Answer

A)  Test of a contingency table. 
B)  Goodness-of-fit test. 
C)  One tailed test for two proportions. 
D)  None of these choices. 
A)  Test of a contingency table. 
B)  Goodness-of-fit test. 
C)  One tailed test for two proportions. 
D)  None of these choices.

Question 16

A chi-squared test of a contingency table with 10 degrees of freedom results in a test statistic of 17.894.Using the chi-squared table,the most accurate statement that can be made about the p-value for this test is that .05 < p-value < .10.

Accepted Answer

A) True 
 B)False

Question 17

The values of a chi-squared distribution are always ____________________ zero.

Accepted Answer

greater th

Question 18

Sales Volumes
A telemarketer makes five calls per day.A sample of 200 days gives the frequencies of sales volumes listed below:
 $$\begin{array} { | c | c | } 
\hline \text { Number of Sales } & \text { Observed Frequency (days) } \
\hline0 & 10 \
1 & 38 \
2 & 69 \
3 & 03 \
4 & 18 \
5 & 2 \
\hline
\end{array}$$ Assume the population is binomial distribution with a probability of purchase p equal to .50.
-{Sales Volumes Narrative} Compute the expected frequencies for x = 0,1,2,3,4,and 5 by using the binomial probability function or the binomial tables.Combine categories if necessary to satisfy the rule of five.

Accepted Answer

\[\begin{array} { | c | c | c | c | } 
\

Question 19

Which of the following tests is appropriate for nominal data if the problem objective is to compare two populations and the number of categories exceeds 2?

Accepted Answer

A)  The z-test for one proportion,p,or difference of two proportions,p1 -p2. 
B)  The chi-squared goodness-of-fit test. 
C)  The chi-squared test of a contingency table. 
D)  All of these choices are true. 
A)  The z-test for one proportion,p,or difference of two proportions,p1 -p2. 
B)  The chi-squared goodness-of-fit test. 
C)  The chi-squared test of a contingency table. 
D)  All of these choices are true.

Question 20

Student Absenteeism
Consider a multinomial experiment involving n = 200 students of a large high school.The attendance department recorded the number of students who were absent during the weekdays.The null hypothesis to be tested is: HS1U1B10S1U1B0: pS1U1B11S1U1B0 = .10,pS1U1B12S1U1B0 = .25,pS1U1B13S1U1B0 = .30,pS1U1B14S1U1B0 = .20,pS1U1B15S1U1B0 = .15.
-{Student Absenteeism Narrative} Test the hypothesis at the 5% level of significance with the following frequencies: (n = 100)
 $$\begin{array} { | l | c c c c c | } 
\hline \text { Day of the Week } & \text { Mon. } & \text { Tues. } & \text { Wed. } & \text { Thurs. } & \text { Fri } \
\hline \text { Number Absent } & \mathbf { 8 } & 22 & 28 & 24 & 18 \
\hline
\end{array}$$

Accepted Answer

Rejection region: @#LAT-DLM&² > @#LAT-DLM&^2<

Exam 15: Chi-Squared Tests

All of the expected frequencies in a chi-squared goodness-of-fit test must be equal to each other.

In a goodness-of-fit test,H0 lists specific values for proportions and the test of a contingency table does not.

If you want to describe a population with more than two categories,which test(s)can you use?

The only way the chi-squared test statistic can be zero is if the observed frequencies are all exactly the same as the expected frequencies.

If you want to compare two populations that each have more than two categories,which test(s)can you use?

If we want to test for differences between two populations of nominal data with exactly two categories,we can employ either the z-test of p1 - p2,or the chi-squared test of a contingency table.

Mathematical statisticians have established that if we square the value of z,the test statistic for the test of one proportion p,we produce the χ\chiχ 2 statistic.That is,z2 = χ\chiχ 2.

In conducting a chi-squared goodness-of-fit test,an essential condition is that all expected frequencies are at least five.

If you want to describe a population with more than two categories,you can use a chi-squared ____________________ test.

What statistic do we get when we square the value of z?

To determine whether a single coin is fair,the coin was tossed 200 times.The observed frequencies with which each of the two sides of the coin turned up are recorded as 112 heads and 88 tails.Is the coin fair? Use a=.05

Which of the following tests does not use the chi-squared distribution?

A chi-squared test of a contingency table with 10 degrees of freedom results in a test statistic of 17.894.Using the chi-squared table,the most accurate statement that can be made about the p-value for this test is that .05 < p-value < .10.

The values of a chi-squared distribution are always ____________________ zero.

Which of the following tests is appropriate for nominal data if the problem objective is to compare two populations and the number of categories exceeds 2?

What Is Statistics

Graphical Descriptive Techniques I

Graphical Descriptive Techniques II

A: Numerical Descriptive Techniques

B: Numerical Descriptive Techniques

C: Numerical Descriptive Techniques

Data Collection and Sampling

Probability

A: Random Variables and Discrete Probability Distributions

B: Random Variables and Discrete Probability Distributions

Continuous Probability Distributions

Sampling Distributions

Introduction to Estimation

Introduction to Hypothesis Testing

Inference About a Population

Inference About Comparing Two Populations

Analysis of Variance

A: Simple Linear Regression and Correlation

B: Simple Linear Regression and Correlation

Multiple Regression

Model Building

Nonparametric Statistics

Time-Series Analysis and Forecasting

Statistical Process Control

Decision Analysis

Conclusion

Filters

In a goodness-of-fit test,H₀ lists specific values for proportions and the test of a contingency table does not.

If we want to test for differences between two populations of nominal data with exactly two categories,we can employ either the z-test of p₁ - p₂,or the chi-squared test of a contingency table.

Mathematical statisticians have established that if we square the value of z,the test statistic for the test of one proportion p,we produce the $\chi$ ² statistic.That is,z² = $\chi$ ².