Exam 28: Magnetic Fields

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The diagram shows a straight wire carrying a flow of electrons into the page.The wire is between the poles of a permanent magnet.The direction of the magnetic force exerted on the wire is: The diagram shows a straight wire carrying a flow of electrons into the page.The wire is between the poles of a permanent magnet.The direction of the magnetic force exerted on the wire is:

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A beam of electrons is sent horizontally down the axis of a tube to strike a fluorescent screen at the end of the tube.On the way, the electrons encounter a magnetic field directed vertically downward.The spot on the screen will therefore be deflected:

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An electron moves in the negative x direction, through a uniform magnetic field that is in the negative y direction.The magnetic force on the electron is: An electron moves in the negative x direction, through a uniform magnetic field that is in the negative y direction.The magnetic force on the electron is:

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The figure shows the motion of electrons in a wire which is near the N pole of a magnet.The wire will be pushed: The figure shows the motion of electrons in a wire which is near the N pole of a magnet.The wire will be pushed:

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A hydrogen atom that has lost its electron is moving east in a region where the magnetic field is directed from south to north.It will be deflected:

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The current is from left to right in the conductor shown.The magnetic field is into the page and point S is at a higher potential than point T.The charge carriers are: The current is from left to right in the conductor shown.The magnetic field is into the page and point S is at a higher potential than point T.The charge carriers are:

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A current is clockwise around the outside edge of this page and a uniform magnetic field is directed parallel to the page, from left to right.If the magnetic force is the only force acting on the page, the page will rotate so the right edge:

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An electron is launched with velocity  An electron is launched with velocity   in a uniform magnetic field   .The angle  \theta 0between   and   is between 0 and 90<sup>o</sup>.As a result, the electron follows a helix, its velocity vector   returning to its initial value in a time interval of: in a uniform magnetic field  An electron is launched with velocity   in a uniform magnetic field   .The angle  \theta 0between   and   is between 0 and 90<sup>o</sup>.As a result, the electron follows a helix, its velocity vector   returning to its initial value in a time interval of: .The angle θ\theta 0between  An electron is launched with velocity   in a uniform magnetic field   .The angle  \theta 0between   and   is between 0 and 90<sup>o</sup>.As a result, the electron follows a helix, its velocity vector   returning to its initial value in a time interval of: and  An electron is launched with velocity   in a uniform magnetic field   .The angle  \theta 0between   and   is between 0 and 90<sup>o</sup>.As a result, the electron follows a helix, its velocity vector   returning to its initial value in a time interval of: is between 0 and 90o.As a result, the electron follows a helix, its velocity vector  An electron is launched with velocity   in a uniform magnetic field   .The angle  \theta 0between   and   is between 0 and 90<sup>o</sup>.As a result, the electron follows a helix, its velocity vector   returning to its initial value in a time interval of: returning to its initial value in a time interval of:

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In the formula In the formula   : :

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J.J.Thomson's experiment, involving the motion of an electron beam in mutually perpendicular J.J.Thomson's experiment, involving the motion of an electron beam in mutually perpendicular   and   fields, gave the value of: and J.J.Thomson's experiment, involving the motion of an electron beam in mutually perpendicular   and   fields, gave the value of: fields, gave the value of:

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The units of magnetic dipole moment are:

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An electron and a proton are both initially moving with the same speed and in the same direction at 90˚ to the same uniform magnetic field.They experience magnetic forces, which are initially:

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The diagrams show five possible orientations of a magnetic dipole The diagrams show five possible orientations of a magnetic dipole   in a uniform magnetic field   .For which of these is the potential energy the greatest?  in a uniform magnetic field The diagrams show five possible orientations of a magnetic dipole   in a uniform magnetic field   .For which of these is the potential energy the greatest?  .For which of these is the potential energy the greatest? The diagrams show five possible orientations of a magnetic dipole   in a uniform magnetic field   .For which of these is the potential energy the greatest?

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An electron is moving north in a region where the magnetic field is south.The magnetic force exerted on the electron is:

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The magnetic torque exerted on a flat current-carrying loop of wire by a uniform magnetic field The magnetic torque exerted on a flat current-carrying loop of wire by a uniform magnetic field   is: is:

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At any point the magnetic field lines are in the direction of:

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An electron is travelling in the positive x direction.A uniform electric field An electron is travelling in the positive x direction.A uniform electric field   is in the negative y direction.If a uniform magnetic field with the appropriate magnitude and direction also exists in the region, the total force on the electron will be zero.The appropriate direction for the magnetic field is:  is in the negative y direction.If a uniform magnetic field with the appropriate magnitude and direction also exists in the region, the total force on the electron will be zero.The appropriate direction for the magnetic field is: An electron is travelling in the positive x direction.A uniform electric field   is in the negative y direction.If a uniform magnetic field with the appropriate magnitude and direction also exists in the region, the total force on the electron will be zero.The appropriate direction for the magnetic field is:

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Electrons (mass m, charge -e)are accelerated from rest through a potential difference V and are then deflected by a magnetic field Electrons (mass m, charge -e)are accelerated from rest through a potential difference V and are then deflected by a magnetic field   that is perpendicular to their velocity.The radius of the resulting electron trajectory is: that is perpendicular to their velocity.The radius of the resulting electron trajectory is:

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A loop of current-carrying wire has a magnetic dipole moment of 5.0 *10-4 A.m2.If the dipole moment makes an angle of 57° with a magnetic field of 0.35 T, what is its potential energy?

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The magnetic dipole moment of a current-carrying loop of wire is in the positive z direction.If a uniform magnetic field is in the positive x direction the magnetic torque on the loop is:

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