Exam 34: Sum and Difference Formulas

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Find the exact value of the given expression using a sum or difference formula. sin⁡285∘\sin 285 ^ { \circ }

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Find the exact value of the given expression. sin⁡(2π3−5π4)\sin \left( \frac { 2 \pi } { 3 } - \frac { 5 \pi } { 4 } \right)

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Simplify the expression algebraically.​ 3sin⁡(π2−x)3 \sin \left( \frac { \pi } { 2 } - x \right) ​

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Verify the given identity. cos⁡(x+y)cos⁡(x−y)=cos⁡2x−sin⁡2y\cos ( x + y ) \cos ( x - y ) = \cos ^ { 2 } x - \sin ^ { 2 } y

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Write the given expression as the sine of an angle. sin⁡45∘cos⁡55∘−sin⁡55∘45∘\sin 45 ^ { \circ } \cos 55 ^ { \circ } - \sin 55 ^ { \circ } 45 ^ { \circ }

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Find the exact value of cos⁡(u+v)\cos ( u + v ) given that sin⁡u=513\sin u = \frac { 5 } { 13 } and cos⁡v=−45\cos v = - \frac { 4 } { 5 } .(Both u and v are in Quadrant II. )

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Find the exact value of the given expression. sin⁡105∘cos⁡345∘−sin⁡345∘cos⁡105∘\sin 105 ^ { \circ } \cos 345 ^ { \circ } - \sin 345 ^ { \circ } \cos 105 ^ { \circ }

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Simplify the expression algebraically.​ 92cos⁡(5π4−x)\frac { 9 } { \sqrt { 2 } } \cos \left( \frac { 5 \pi } { 4 } - x \right) ​

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Find the exact solutions of the given equation in the interval [0,2π). sin 2x = sin x ​

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Simplify the expression algebraically.​ 6sin⁡(π2+x)6 \sin \left( \frac { \pi } { 2 } + x \right) ​

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Simplify the following expression algebraically.​ cos⁡(3π2−x)\cos \left( \frac { 3 \pi } { 2 } - x \right) ​

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Simplify the given expression algebraically.​ cos⁡(x−π)\cos ( x - \pi )

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Write the given expression as the cosine of an angle.​ cos⁡45∘cos⁡40∘+sin⁡45∘sin⁡40∘\cos 45 ^ { \circ } \cos 40 ^ { \circ } + \sin 45 ^ { \circ } \sin 40 ^ { \circ }

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Find the exact value of the given expression. sin⁡(π3−π4)\sin \left( \frac { \pi } { 3 } - \frac { \pi } { 4 } \right)

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Use the formula asin⁡Bθ+bcos⁡Bθ=a2+b2cos⁡(Bθ−C)a \sin B \theta + b \cos B \theta = \sqrt { a ^ { 2 } + b ^ { 2 } } \cos ( B \theta - C ) ,where C=arctan⁡(a/b),a=3,b=7,B=2C = \arctan ( a / b ) , a = 3 , b = 7 , B = 2 to rewrite the trigonometric expression in the following form.​ y=a2+b2cos⁡(Bθ−C)y = \sqrt { a ^ { 2 } + b ^ { 2 } } \cos ( B \theta - C ) ​ asin⁡Bθ+bcos⁡Bθa \sin B \theta + b \cos B \theta ​

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Use the formula asin⁡Bθ+bcos⁡Bθ=a2+b2cos⁡(Bθ−C)a \sin B \theta + b \cos B \theta = \sqrt { a ^ { 2 } + b ^ { 2 } } \cos ( B \theta - C ) ,where C=arctan⁡(a/b),a=9,b=2,B=2C = \arctan ( a / b ) , a = 9 , b = 2 , B = 2 to rewrite the trigonometric expression in the following form.​ y=a2+b2cos⁡(Bθ−C)y = \sqrt { a ^ { 2 } + b ^ { 2 } } \cos ( B \theta - C ) ​ asin⁡Bθ+bcos⁡Bθa \sin B \theta + b \cos B \theta ​

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Use a graphing utility to select correct graph of y1y _ { 1 } and y2y _ { 2 } in the same viewing window.Use the graphs to determine whether y1=y2y _ { 1 } = y _ { 2 } .Explain your reasoning.​ y1=sin⁡(x+6),y2=sin⁡(x)+sin⁡(6)y _ { 1 } = \sin ( x + 6 ) , y _ { 2 } = \sin ( x ) + \sin ( 6 ) ​

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Simplify the expression algebraically.​ cos⁡(7x+4y)cos⁡(7x−4y)\cos ( 7 x + 4 y ) \cos ( 7 x - 4 y ) ​

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Write the given expression as the cosine of an angle. cos⁡60∘cos⁡25∘−sin⁡60∘sin⁡25∘\cos 60 ^ { \circ } \cos 25 ^ { \circ } - \sin 60 ^ { \circ } \sin 25 ^ { \circ } ​

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Find the expression as the tangent of an angle.​ tan⁡130∘−tan⁡30∘1+tan⁡130∘tan⁡30∘\frac { \tan 130 ^ { \circ } - \tan 30 ^ { \circ } } { 1 + \tan 130 ^ { \circ } \tan 30 ^ { \circ } } ​

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