Exam 34: Sum and Difference Formulas

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Simplify the expression algebraically.​ 3cos⁡(π−θ)+3sin⁡(π2+θ)3 \cos ( \pi - \theta ) + 3 \sin \left( \frac { \pi } { 2 } + \theta \right) ​

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B

A weight is attached to a spring suspended vertically from a ceiling.When a driving force is applied to the system,the weight moves vertically from its equilibrium position,and this motion is modeled by​ y=18sin⁡2t+16cos⁡2ty = \frac { 1 } { 8 } \sin 2 t + \frac { 1 } { 6 } \cos 2 t ​ where y is the distance from equilibrium (in feet)and t is the time (in seconds). ​ Use the identity asin⁡Bθ+bcos⁡Bθ=a2+b2sin⁡(Bθ+C)a \sin B \theta + b \cos B \theta = \sqrt { a ^ { 2 } + b ^ { 2 } } \sin ( B \theta + C ) where C=arctan⁡(b/a),a>0C = \arctan ( b / a ) , a > 0 ,to write the model in the form y=a2+b2sin⁡(Bt+C)y = \sqrt { a ^ { 2 } + b ^ { 2 } } \sin ( B t + C ) . ​

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E

Find the exact value of the given expression using a sum or difference formula. sin⁡285∘\sin 285 ^ { \circ }

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B

Find the exact value of the given expression using a sum or difference formula. cos⁡17π12\cos \frac { 17 \pi } { 12 }

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Find the exact value of sin⁡(u+v)\sin ( u + v ) given that sin⁡u=725\sin u = \frac { 7 } { 25 } and cos⁡v=−1213\cos v = - \frac { 12 } { 13 } .(Both u and v are in Quadrant II. )

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Simplify the given expression algebraically. cos⁡(π2+x)\cos \left( \frac { \pi } { 2 } + x \right)

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Find the expression as the tangent of an angle.​ tan⁡3x+tan⁡x1−tan⁡3xtan⁡x\frac { \tan 3 x + \tan x } { 1 - \tan 3 x \tan x } ​

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Use the formula asin⁡Bθ+bcos⁡Bθ=a2+b2sin⁡(Bθ+C)a \sin B \theta + b \cos B \theta = \sqrt { a ^ { 2 } + b ^ { 2 } } \sin ( B \theta + C ) ,where C=arctan⁡(b/a),a=3,b=,B=1C = \arctan ( b / a ) , a = 3 , b = , B = 1 to rewrite the trigonometric expression in the following form.​ y=a2+b2sin⁡(Bθ+C)y = \sqrt { a ^ { 2 } + b ^ { 2 } } \sin ( B \theta + C ) ​ asin⁡Bθ+bcos⁡Bθa \sin B \theta + b \cos B \theta ​

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Write the given expression as the sine of an angle. sin⁡85∘cos⁡50∘−sin⁡50∘cos⁡85∘\sin 85 ^ { \circ } \cos 50 ^ { \circ } - \sin 50 ^ { \circ } \cos 85 ^ { \circ }

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Find the exact solutions of the given equation in the interval [0,2π)[ 0,2 \pi ) . sin 4x= -2sin 2x

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Use the formula asin⁡Bθ+bcos⁡Bθ=a2+b2sin⁡(Bθ−C)a \sin B \theta + b \cos B \theta = \sqrt { a ^ { 2 } + b ^ { 2 } } \sin ( B \theta - C ) ,where C=arctan⁡(a/b),a=2,b=8,B=1C = \arctan ( a / b ) , a = 2 , b = 8 , B = 1 ,to rewrite the trigonometric expression in the following form.​ y=a2+b2sin⁡(Bθ−C)y = \sqrt { a ^ { 2 } + b ^ { 2 } } \sin ( B \theta - C ) ​ asin⁡Bθ+bcos⁡Bθa \sin B \theta + b \cos B \theta ​

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Write the given expression as the tangent of an angle.​ tan⁡7x+tan⁡4x1−tan⁡7xtan⁡4x\frac { \tan 7 x + \tan 4 x } { 1 - \tan 7 x \tan 4 x }

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Find the exact value of cos⁡(u+v)\cos ( u + v ) given that sin⁡u=817\sin u = \frac { 8 } { 17 } and cos⁡v=−6061\cos v = - \frac { 60 } { 61 } .(Both u and v are in Quadrant II. )

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Use the formula asin⁡Bθ+bcos⁡Bθ=a2+b2cos⁡(Bθ−C)a \sin B \theta + b \cos B \theta = \sqrt { a ^ { 2 } + b ^ { 2 } } \cos ( B \theta - C ) ,where C=arctan⁡(a/b),a>0C = \arctan ( a / b ) , a > 0 ,to rewrite the trigonometric expression in the form.​ 6sin⁡(θ+π4)\sqrt { 6 } \sin \left( \theta + \frac { \pi } { 4 } \right) ​

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Find the expression as the tangent of an angle.​ tan⁡60∘−tan⁡20∘1+tan⁡60∘tan⁡20∘\frac { \tan 60 ^ { \circ } - \tan 20 ^ { \circ } } { 1 + \tan 60 ^ { \circ } \tan 20 ^ { \circ } } ​

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Use the formula asin⁡Bθ+bcos⁡Bθ=a2+b2sin⁡(Bθ+C)a \sin B \theta + b \cos B \theta = \sqrt { a ^ { 2 } + b ^ { 2 } } \sin ( B \theta + C ) ,where C=arctan⁡(b/a),a=18,b=6,B=3C = \arctan ( b / a ) , a = 18 , b = 6 , B = 3 ,to rewrite the trigonometric expression in the following form.​ y=a2+b2sin⁡(Bθ+C)y = \sqrt { a ^ { 2 } + b ^ { 2 } } \sin ( B \theta + C ) ​ asin⁡Bθ+bcos⁡Bθa \sin B \theta + b \cos B \theta ​

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Find the expression as the sine of an angle.​ sin⁡55∘cos⁡5∘+cos⁡55∘sin⁡5∘\sin 55 ^ { \circ } \cos 5 ^ { \circ } + \cos 55 ^ { \circ } \sin 5 ^ { \circ } ​

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Simplify the expression algebraically.​ sin⁡(9x+9y)sin⁡(9x−9y)\sin ( 9 x + 9 y ) \sin ( 9 x - 9 y ) ​

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Evaluate the expression.​ sin⁡xsin⁡(x+y)+cos⁡xcos⁡(x+y)\sin x \sin ( x + y ) + \cos x \cos ( x + y ) ​

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Use the formula asin⁡Bθ+bcos⁡Bθ=a2+b2sin⁡(Bθ+C)a \sin B \theta + b \cos B \theta = \sqrt { a ^ { 2 } + b ^ { 2 } } \sin ( B \theta + C ) ,where C=arctan⁡(b/a),a=1,b=3,B=2C = \arctan ( b / a ) , a = 1 , b = 3 , B = 2 ,to rewrite the trigonometric expression in the following form.​ y=a2+b2sin⁡(Bθ+C)y = \sqrt { a ^ { 2 } + b ^ { 2 } } \sin ( B \theta + C ) ​ asin⁡Bθ+bcos⁡Bθa \sin B \theta + b \cos B \theta ​

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